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Ashley1998
Help me please !!!!
10th term: \[6, 6\frac{ 2 }{ 3 }, 7 \frac{ 1 }{ 3 }, ...\]
if you're going to hack it.....then there is only one way the series is simple arithmetic progression you can observe this series as ( 18/3...20/3....22/3.....) commcon difference is 2/3
plug in numbers to get 12 i think