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Ashley1998

  • 3 years ago

Help me please !!!!

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  1. Ashley1998
    • 3 years ago
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    10th term: \[6, 6\frac{ 2 }{ 3 }, 7 \frac{ 1 }{ 3 }, ...\]

  2. timo86m
    • 3 years ago
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    http://www.mathwords.com/a/arithmetic_sequence.htm

  3. rohankv
    • 3 years ago
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    if you're going to hack it.....then there is only one way the series is simple arithmetic progression you can observe this series as ( 18/3...20/3....22/3.....) commcon difference is 2/3

  4. timo86m
    • 3 years ago
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    plug in numbers to get 12 i think

  5. Ashley1998
    • 3 years ago
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    thanks(:

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