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gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
x^2+4x+3 = 0 (x+1) (x+ 3) = 0 then x = 1 or x = 3
 one year ago

rizwan_uet Group TitleBest ResponseYou've already chosen the best response.0
no no use quadratic formula to solve @gerryliyana
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.1
do you know what the quadratic formula is? or are you asking for that.
 one year ago

JaneDoe100 Group TitleBest ResponseYou've already chosen the best response.1
i know what it is but i still dont know how 2 get the answer...
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.1
set up equation so that you have: ax^2+bx+c=0 and use a, b and c correctly in your formula
 one year ago

JaneDoe100 Group TitleBest ResponseYou've already chosen the best response.1
x²+4x+3=0?
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.1
so a=?,b=?, and c=?
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
yess ur all right
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
smart boy!!
 one year ago

JaneDoe100 Group TitleBest ResponseYou've already chosen the best response.1
a=o b=4 c=3
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
a = 1, b=4, c=3
 one year ago

JaneDoe100 Group TitleBest ResponseYou've already chosen the best response.1
sorry i wasnt thinking
 one year ago

JaneDoe100 Group TitleBest ResponseYou've already chosen the best response.1
so now what?
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
use \[x = \frac{ b \pm \sqrt{(b^{2}  4ac)} }{ 2a }\]
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
substitute all parameter, including a, b, and c
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.1
\[x = \frac{ b \pm \sqrt{b^{2}4ac} }{ 2a }\] \[x = \frac{ 4 \pm \sqrt{4^{2}(4)(1)(3)} }{ 2(1) }\]
 one year ago

JaneDoe101 Group TitleBest ResponseYou've already chosen the best response.0
Thanks both of you!
 one year ago
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