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x^2+4x+3 = 0
(x+1) (x+ 3) = 0
then x = -1 or x = -3

no no use quadratic formula to solve @gerryliyana

do you know what the quadratic formula is? or are you asking for that.

i know what it is but i still dont know how 2 get the answer...

set up equation so that you have:
ax^2+bx+c=0
and use a, b and c correctly in your formula

x²+4x+3=0?

so a=?,b=?, and c=?

yess ur all right

smart boy!!

a=o b=4 c=3

nooo

a = 1, b=4, c=3

yes

sorry i wasnt thinking

so now what?

use
\[x = \frac{ -b \pm \sqrt{(b^{2} - 4ac)} }{ 2a }\]

substitute all parameter, including a, b, and c

to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,

ok

Thanks both of you!