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JaneDoe100

  • 3 years ago

help! use the quadratic formula to solve x²+3=-4x

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  1. gerryliyana
    • 3 years ago
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    x^2+4x+3 = 0 (x+1) (x+ 3) = 0 then x = -1 or x = -3

  2. rizwan_uet
    • 3 years ago
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    no no use quadratic formula to solve @gerryliyana

  3. diongory
    • 3 years ago
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    do you know what the quadratic formula is? or are you asking for that.

  4. JaneDoe100
    • 3 years ago
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    i know what it is but i still dont know how 2 get the answer...

  5. diongory
    • 3 years ago
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    set up equation so that you have: ax^2+bx+c=0 and use a, b and c correctly in your formula

  6. JaneDoe100
    • 3 years ago
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    x²+4x+3=0?

  7. diongory
    • 3 years ago
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    so a=?,b=?, and c=?

  8. gerryliyana
    • 3 years ago
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    yess ur all right

  9. gerryliyana
    • 3 years ago
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    smart boy!!

  10. JaneDoe100
    • 3 years ago
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    a=o b=4 c=3

  11. gerryliyana
    • 3 years ago
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    nooo

  12. gerryliyana
    • 3 years ago
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    a = 1, b=4, c=3

  13. gerryliyana
    • 3 years ago
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    yes

  14. JaneDoe100
    • 3 years ago
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    sorry i wasnt thinking

  15. JaneDoe100
    • 3 years ago
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    so now what?

  16. gerryliyana
    • 3 years ago
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    use \[x = \frac{ -b \pm \sqrt{(b^{2} - 4ac)} }{ 2a }\]

  17. gerryliyana
    • 3 years ago
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    substitute all parameter, including a, b, and c

  18. gerryliyana
    • 3 years ago
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    to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,

  19. gerryliyana
    • 3 years ago
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    \[x = \frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\] \[x = \frac{ -4 \pm \sqrt{4^{2}-(4)(1)(3)} }{ 2(1) }\]

  20. JaneDoe100
    • 3 years ago
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    ok

  21. JaneDoe101
    • 3 years ago
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    Thanks both of you!

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