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JaneDoe100 Group Title

help! use the quadratic formula to solve x²+3=-4x

  • one year ago
  • one year ago

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  1. gerryliyana Group Title
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    x^2+4x+3 = 0 (x+1) (x+ 3) = 0 then x = -1 or x = -3

    • one year ago
  2. rizwan_uet Group Title
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    no no use quadratic formula to solve @gerryliyana

    • one year ago
  3. diongory Group Title
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    do you know what the quadratic formula is? or are you asking for that.

    • one year ago
  4. JaneDoe100 Group Title
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    i know what it is but i still dont know how 2 get the answer...

    • one year ago
  5. diongory Group Title
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    set up equation so that you have: ax^2+bx+c=0 and use a, b and c correctly in your formula

    • one year ago
  6. JaneDoe100 Group Title
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    x²+4x+3=0?

    • one year ago
  7. diongory Group Title
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    so a=?,b=?, and c=?

    • one year ago
  8. gerryliyana Group Title
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    yess ur all right

    • one year ago
  9. gerryliyana Group Title
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    smart boy!!

    • one year ago
  10. JaneDoe100 Group Title
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    a=o b=4 c=3

    • one year ago
  11. gerryliyana Group Title
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    nooo

    • one year ago
  12. gerryliyana Group Title
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    a = 1, b=4, c=3

    • one year ago
  13. gerryliyana Group Title
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    yes

    • one year ago
  14. JaneDoe100 Group Title
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    sorry i wasnt thinking

    • one year ago
  15. JaneDoe100 Group Title
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    so now what?

    • one year ago
  16. gerryliyana Group Title
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    use \[x = \frac{ -b \pm \sqrt{(b^{2} - 4ac)} }{ 2a }\]

    • one year ago
  17. gerryliyana Group Title
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    substitute all parameter, including a, b, and c

    • one year ago
  18. gerryliyana Group Title
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    to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,

    • one year ago
  19. gerryliyana Group Title
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    \[x = \frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\] \[x = \frac{ -4 \pm \sqrt{4^{2}-(4)(1)(3)} }{ 2(1) }\]

    • one year ago
  20. JaneDoe100 Group Title
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    ok

    • one year ago
  21. JaneDoe101 Group Title
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    Thanks both of you!

    • one year ago
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