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gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.1x^2+4x+3 = 0 (x+1) (x+ 3) = 0 then x = 1 or x = 3

rizwan_uet
 one year ago
Best ResponseYou've already chosen the best response.0no no use quadratic formula to solve @gerryliyana

diongory
 one year ago
Best ResponseYou've already chosen the best response.1do you know what the quadratic formula is? or are you asking for that.

JaneDoe100
 one year ago
Best ResponseYou've already chosen the best response.1i know what it is but i still dont know how 2 get the answer...

diongory
 one year ago
Best ResponseYou've already chosen the best response.1set up equation so that you have: ax^2+bx+c=0 and use a, b and c correctly in your formula

JaneDoe100
 one year ago
Best ResponseYou've already chosen the best response.1sorry i wasnt thinking

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.1use \[x = \frac{ b \pm \sqrt{(b^{2}  4ac)} }{ 2a }\]

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.1substitute all parameter, including a, b, and c

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.1to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.1\[x = \frac{ b \pm \sqrt{b^{2}4ac} }{ 2a }\] \[x = \frac{ 4 \pm \sqrt{4^{2}(4)(1)(3)} }{ 2(1) }\]

JaneDoe101
 one year ago
Best ResponseYou've already chosen the best response.0Thanks both of you!
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