JaneDoe100
help!
use the quadratic formula to solve
x²+3=4x



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gerryliyana
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x^2+4x+3 = 0
(x+1) (x+ 3) = 0
then x = 1 or x = 3

rizwan_uet
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no no use quadratic formula to solve @gerryliyana

diongory
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do you know what the quadratic formula is? or are you asking for that.

JaneDoe100
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i know what it is but i still dont know how 2 get the answer...

diongory
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set up equation so that you have:
ax^2+bx+c=0
and use a, b and c correctly in your formula

JaneDoe100
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x²+4x+3=0?

diongory
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so a=?,b=?, and c=?

gerryliyana
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yess ur all right

gerryliyana
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smart boy!!

JaneDoe100
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a=o b=4 c=3

gerryliyana
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nooo

gerryliyana
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a = 1, b=4, c=3

gerryliyana
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yes

JaneDoe100
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sorry i wasnt thinking

JaneDoe100
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so now what?

gerryliyana
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use
\[x = \frac{ b \pm \sqrt{(b^{2}  4ac)} }{ 2a }\]

gerryliyana
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substitute all parameter, including a, b, and c

gerryliyana
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to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,

gerryliyana
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\[x = \frac{ b \pm \sqrt{b^{2}4ac} }{ 2a }\]
\[x = \frac{ 4 \pm \sqrt{4^{2}(4)(1)(3)} }{ 2(1) }\]

JaneDoe100
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ok

JaneDoe101
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Thanks both of you!