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aussy123

  • 3 years ago

How to convert polar to cartesian and cartesian to polar.

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  1. diongory
    • 3 years ago
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    |dw:1366122540329:dw|

  2. diongory
    • 3 years ago
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    for polar to cartesian think about writing r in terms of x and y, and theta in terms of x and y

  3. aussy123
    • 3 years ago
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    I think what you wrote at the top is polar to cartesian. Because your finding x and y. I really need to know how to find cartesian to polar.

  4. diongory
    • 3 years ago
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    |dw:1366123054027:dw|

  5. aussy123
    • 3 years ago
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    I think so Im given something like that with this tan^-1

  6. diongory
    • 3 years ago
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    i know what the answer is. I'm trying to help you get there yourself. Work out those two equations i drew for you.

  7. aussy123
    • 3 years ago
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    \[\sqrt{x^2+y^2}=r\]

  8. diongory
    • 3 years ago
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    excellent!

  9. aussy123
    • 3 years ago
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    \[x+y=r\]

  10. diongory
    • 3 years ago
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    no. not so good.|dw:1366123658835:dw|

  11. diongory
    • 3 years ago
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    your first solution was correct

  12. diongory
    • 3 years ago
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    |dw:1366123719654:dw|

  13. aussy123
    • 3 years ago
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    oh sorry

  14. diongory
    • 3 years ago
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    what about for theta?

  15. aussy123
    • 3 years ago
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    would it be \[\frac{ \sqrt{x} }{ \sqrt{y} }\]

  16. diongory
    • 3 years ago
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    how did you get that?

  17. aussy123
    • 3 years ago
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    theta = tan^-1 (y/x)

  18. diongory
    • 3 years ago
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    great. well done. that is it. you have finished.

  19. aussy123
    • 3 years ago
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    thank you

  20. diongory
    • 3 years ago
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    |dw:1366124051396:dw|

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