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aussy123
Group Title
How to convert polar to cartesian and cartesian to polar.
 one year ago
 one year ago
aussy123 Group Title
How to convert polar to cartesian and cartesian to polar.
 one year ago
 one year ago

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diongory Group TitleBest ResponseYou've already chosen the best response.0
dw:1366122540329:dw
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
for polar to cartesian think about writing r in terms of x and y, and theta in terms of x and y
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
I think what you wrote at the top is polar to cartesian. Because your finding x and y. I really need to know how to find cartesian to polar.
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
dw:1366123054027:dw
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
I think so Im given something like that with this tan^1
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
i know what the answer is. I'm trying to help you get there yourself. Work out those two equations i drew for you.
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{x^2+y^2}=r\]
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
excellent!
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
\[x+y=r\]
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
no. not so good.dw:1366123658835:dw
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
your first solution was correct
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
dw:1366123719654:dw
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
what about for theta?
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
would it be \[\frac{ \sqrt{x} }{ \sqrt{y} }\]
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
how did you get that?
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
theta = tan^1 (y/x)
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
great. well done. that is it. you have finished.
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.0
thank you
 one year ago

diongory Group TitleBest ResponseYou've already chosen the best response.0
dw:1366124051396:dw
 one year ago
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