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|dw:1366122540329:dw|

for polar to cartesian think about writing r in terms of x and y, and theta in terms of x and y

|dw:1366123054027:dw|

I think so Im given something like that with this tan^-1

\[\sqrt{x^2+y^2}=r\]

excellent!

\[x+y=r\]

no. not so good.|dw:1366123658835:dw|

your first solution was correct

|dw:1366123719654:dw|

oh sorry

what about for theta?

would it be \[\frac{ \sqrt{x} }{ \sqrt{y} }\]

how did you get that?

theta = tan^-1 (y/x)

great. well done. that is it. you have finished.

thank you

|dw:1366124051396:dw|