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if the complex number Z lies on the circle |Z-2i| = 2sqrt(2) then find arg( (Z-2)/Z+2) ) ?

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wasnt this answered earlier today?
Yes..But it wanst Convincing For me..

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Other answers:

what do you mean "convincing"? you can have proofs in many ways.. the previous solution was very interpretive and nice. and a valid mathematical proof.
i mean..i cant follow their Solutions..
just because the proof was short doesnt meant that aint right! infact, thats what is expected. the shortest way to proove something
Yeah....But i dont Understand How they did it..
Refer to Phi's drawing at http://openstudy.com/users/yahoo!#/updates/516e916ee4b09b9167f12416 do you agree with the drawing there?
Lol...i cant see his drawing?

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