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Yahoo!
 one year ago
if the complex number Z lies on the circle Z2i = 2sqrt(2) then find arg( (Z2)/Z+2) ) ?
Yahoo!
 one year ago
if the complex number Z lies on the circle Z2i = 2sqrt(2) then find arg( (Z2)/Z+2) ) ?

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Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0@shubhamsrg @siddhantsharan @electrokid @satellite73 @RadEn @ash2326

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0wasnt this answered earlier today?

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0Yes..But it wanst Convincing For me..

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean "convincing"? you can have proofs in many ways.. the previous solution was very interpretive and nice. and a valid mathematical proof.

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0i mean..i cant follow their Solutions..

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0just because the proof was short doesnt meant that aint right! infact, thats what is expected. the shortest way to proove something

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0Yeah....But i dont Understand How they did it..

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0Refer to Phi's drawing at http://openstudy.com/users/yahoo!#/updates/516e916ee4b09b9167f12416 do you agree with the drawing there?

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0Lol...i cant see his drawing?
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