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if the complex number Z lies on the circle Z2i = 2sqrt(2) then find arg( (Z2)/Z+2) ) ?
 one year ago
 one year ago
Yahoo! Group Title
if the complex number Z lies on the circle Z2i = 2sqrt(2) then find arg( (Z2)/Z+2) ) ?
 one year ago
 one year ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@shubhamsrg @siddhantsharan @electrokid @satellite73 @RadEn @ash2326
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.0
wasnt this answered earlier today?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yes..But it wanst Convincing For me..
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.0
what do you mean "convincing"? you can have proofs in many ways.. the previous solution was very interpretive and nice. and a valid mathematical proof.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
i mean..i cant follow their Solutions..
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.0
just because the proof was short doesnt meant that aint right! infact, thats what is expected. the shortest way to proove something
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yeah....But i dont Understand How they did it..
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.0
Refer to Phi's drawing at http://openstudy.com/users/yahoo!#/updates/516e916ee4b09b9167f12416 do you agree with the drawing there?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Lol...i cant see his drawing?
 one year ago
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