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.04v^2+.9v=? I am trying to find the stopping distance of the car when it is traveling at 60 mph.
What's this? .04v^2+.9v=? Anyway the speed = distance/time You have the speed and you want to get the distance so you'll have to find the time first so you can finally answer your question
so do I plug in the 60 for the v? I don't understand how to set the problem up so I can solve it.
i mean... You gave me an equation that is equal to an interrogation sign but at the same time you asked for a distance. I can't even answer you. I don't know if you're considering the friction between the wheels rubber and the road... Please review your data and/or give more detailed info about this particular problem
For a certain driver, the stopping distance in feet is given by 0.04v^2+.9v where the v is the velocity of the car. Find the stopping distance when a car is traveling 60 mph. Sorry about the question mark...I was thinking "what is this" when I typed it. :)
does this help?
Well you have all there then :) It is said that the stopping distance = 0.04v^2+.9v at the same time they say that v = 60mph You just need to switch it in the given equation to find your answer
ok, so I would do this: .04*60^2+.9*60 correct? I come up with 198
then that is your final distance. Don't forget to add the units. I'm not used to imperial system, i use metric so i can't help you with that
ok thank you!