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morgan_89Best ResponseYou've already chosen the best response.0
.04v^2+.9v=? I am trying to find the stopping distance of the car when it is traveling at 60 mph.
 one year ago

DiogoBest ResponseYou've already chosen the best response.1
What's this? .04v^2+.9v=? Anyway the speed = distance/time You have the speed and you want to get the distance so you'll have to find the time first so you can finally answer your question
 one year ago

morgan_89Best ResponseYou've already chosen the best response.0
so do I plug in the 60 for the v? I don't understand how to set the problem up so I can solve it.
 one year ago

DiogoBest ResponseYou've already chosen the best response.1
i mean... You gave me an equation that is equal to an interrogation sign but at the same time you asked for a distance. I can't even answer you. I don't know if you're considering the friction between the wheels rubber and the road... Please review your data and/or give more detailed info about this particular problem
 one year ago

morgan_89Best ResponseYou've already chosen the best response.0
For a certain driver, the stopping distance in feet is given by 0.04v^2+.9v where the v is the velocity of the car. Find the stopping distance when a car is traveling 60 mph. Sorry about the question mark...I was thinking "what is this" when I typed it. :)
 one year ago

DiogoBest ResponseYou've already chosen the best response.1
Well you have all there then :) It is said that the stopping distance = 0.04v^2+.9v at the same time they say that v = 60mph You just need to switch it in the given equation to find your answer
 one year ago

morgan_89Best ResponseYou've already chosen the best response.0
ok, so I would do this: .04*60^2+.9*60 correct? I come up with 198
 one year ago

DiogoBest ResponseYou've already chosen the best response.1
then that is your final distance. Don't forget to add the units. I'm not used to imperial system, i use metric so i can't help you with that
 one year ago
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