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anonymous
 3 years ago
What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth?
No real solutions
x ≈ −0.77 and x ≈ 7.77
x ≈ −0.39 and x ≈ 3.89
x ≈ −3.89 and x ≈ 0.39
anonymous
 3 years ago
What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth? No real solutions x ≈ −0.77 and x ≈ 7.77 x ≈ −0.39 and x ≈ 3.89 x ≈ −3.89 and x ≈ 0.39

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ucreategames
 3 years ago
Best ResponseYou've already chosen the best response.0Im confused by this problem. 2x2 would make people think you're multiplying 2 by 2. What does the equation really look like?

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2factor first: (2x1)(x3)

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2so either 2x1=0 or x3 = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is not in the choices though

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2yeah... somethings wrong...

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.22x^2  7x = 3 2x^2  7x  3 = 0 (2x1)(x3) ===> this line's wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so how do i solve it?

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2y = ax^2 + bx + c y = 0 at x points of:

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2\[ \frac{ b +/\sqrt{(b ^{2}4ac} }{ 2a }\]

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2so: from your equation a = 2 b = 7 c = 3 sub those numbers into the equation I gave you and you'll get answers for x

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2\[x = \frac{ 7  \sqrt{73} }{ 4}\]

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2\[or x = \frac{ 7 + \sqrt{73} }{ 4}\]

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2so x = 3.886 and x = 0.386

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok thanks for the help

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.2all good, sorry for the stuff up earlier
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