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mmiranda50
 one year ago
What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth?
No real solutions
x ≈ −0.77 and x ≈ 7.77
x ≈ −0.39 and x ≈ 3.89
x ≈ −3.89 and x ≈ 0.39
mmiranda50
 one year ago
What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth? No real solutions x ≈ −0.77 and x ≈ 7.77 x ≈ −0.39 and x ≈ 3.89 x ≈ −3.89 and x ≈ 0.39

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ucreategames
 one year ago
Best ResponseYou've already chosen the best response.0Im confused by this problem. 2x2 would make people think you're multiplying 2 by 2. What does the equation really look like?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2factor first: (2x1)(x3)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2so either 2x1=0 or x3 = 0

mmiranda50
 one year ago
Best ResponseYou've already chosen the best response.0that is not in the choices though

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2yeah... somethings wrong...

Jack1
 one year ago
Best ResponseYou've already chosen the best response.22x^2  7x = 3 2x^2  7x  3 = 0 (2x1)(x3) ===> this line's wrong

mmiranda50
 one year ago
Best ResponseYou've already chosen the best response.0so how do i solve it?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2y = ax^2 + bx + c y = 0 at x points of:

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2\[ \frac{ b +/\sqrt{(b ^{2}4ac} }{ 2a }\]

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2so: from your equation a = 2 b = 7 c = 3 sub those numbers into the equation I gave you and you'll get answers for x

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2\[x = \frac{ 7  \sqrt{73} }{ 4}\]

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2\[or x = \frac{ 7 + \sqrt{73} }{ 4}\]

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2so x = 3.886 and x = 0.386

mmiranda50
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks for the help

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2all good, sorry for the stuff up earlier
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