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What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth?
No real solutions
x ≈ −0.77 and x ≈ 7.77
x ≈ −0.39 and x ≈ 3.89
x ≈ −3.89 and x ≈ 0.39
 one year ago
 one year ago
What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth? No real solutions x ≈ −0.77 and x ≈ 7.77 x ≈ −0.39 and x ≈ 3.89 x ≈ −3.89 and x ≈ 0.39
 one year ago
 one year ago

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ucreategamesBest ResponseYou've already chosen the best response.0
Im confused by this problem. 2x2 would make people think you're multiplying 2 by 2. What does the equation really look like?
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
factor first: (2x1)(x3)
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
so either 2x1=0 or x3 = 0
 one year ago

mmiranda50Best ResponseYou've already chosen the best response.0
that is not in the choices though
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
yeah... somethings wrong...
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
2x^2  7x = 3 2x^2  7x  3 = 0 (2x1)(x3) ===> this line's wrong
 one year ago

mmiranda50Best ResponseYou've already chosen the best response.0
so how do i solve it?
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
y = ax^2 + bx + c y = 0 at x points of:
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
\[ \frac{ b +/\sqrt{(b ^{2}4ac} }{ 2a }\]
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
so: from your equation a = 2 b = 7 c = 3 sub those numbers into the equation I gave you and you'll get answers for x
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
\[x = \frac{ 7  \sqrt{73} }{ 4}\]
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
\[or x = \frac{ 7 + \sqrt{73} }{ 4}\]
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
so x = 3.886 and x = 0.386
 one year ago

mmiranda50Best ResponseYou've already chosen the best response.0
ok thanks for the help
 one year ago

Jack1Best ResponseYou've already chosen the best response.2
all good, sorry for the stuff up earlier
 one year ago
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