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missy101
Group Title
help!! how do i solve for n in:
(.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K)
sooo stumped!!!
 one year ago
 one year ago
missy101 Group Title
help!! how do i solve for n in: (.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K) sooo stumped!!!
 one year ago
 one year ago

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aaronq Group TitleBest ResponseYou've already chosen the best response.0
(.9985atm)(.02L)= n (0.082 atm*L/mole*K)(296K) n=[(0.082 atm*L/mole*K)(296K)]/[(.9985atm)(.02L)]
 one year ago

missy101 Group TitleBest ResponseYou've already chosen the best response.0
i cant get a definite number/figure for n tho? i dont understand how to caclulate 0.082 atm*L/mole*K or what it means
 one year ago

chmvijay Group TitleBest ResponseYou've already chosen the best response.1
its PV =nRT n=PV/RT = .9985atm *02L / 0.082 atm*L/mole*K *296K = find it atm*L/mole*K its just unit of gas constant don't worry about it
 one year ago

chmvijay Group TitleBest ResponseYou've already chosen the best response.1
@missy101 got it ???:)
 one year ago

chmvijay Group TitleBest ResponseYou've already chosen the best response.1
@aaaronq is wrong !!!
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.0
my baddd i copied and pasted backwards
 one year ago

chmvijay Group TitleBest ResponseYou've already chosen the best response.1
its all right it happens some times !!!:)
 one year ago

gsoda Group TitleBest ResponseYou've already chosen the best response.0
when you go out on a limb, you sometimes fall off the tree. it's really minor anyway.
 one year ago

toxicsugar22 Group TitleBest ResponseYou've already chosen the best response.0
CAN YOU PLEAE HELP ME
 one year ago

missy101 Group TitleBest ResponseYou've already chosen the best response.0
hmmm ok so theres no specific answer? i was told i needed to find one. . . dont see how its posible :/
 one year ago

gsoda Group TitleBest ResponseYou've already chosen the best response.0
if you want the numbers, give me a sec.
 one year ago

chmvijay Group TitleBest ResponseYou've already chosen the best response.1
8.2 10^4 is answer LOL:)
 one year ago

gsoda Group TitleBest ResponseYou've already chosen the best response.0
you want the number of gas particles in moles, or n. using the ideal gas law: n = P V / (R T) putting everything in atm, L, and K: n = (.9985 * .02) / (0.082 * 296) mol it comes out to be 8.2 x 10(4) mol, just like chmvijay posted
 one year ago
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