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missy101

help!! how do i solve for n in: (.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K) sooo stumped!!!

  • one year ago
  • one year ago

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  1. aaronq
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    (.9985atm)(.02L)= n (0.082 atm*L/mole*K)(296K) n=[(0.082 atm*L/mole*K)(296K)]/[(.9985atm)(.02L)]

    • one year ago
  2. missy101
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    i cant get a definite number/figure for n tho? i dont understand how to caclulate 0.082 atm*L/mole*K or what it means

    • one year ago
  3. chmvijay
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    its PV =nRT n=PV/RT = .9985atm *02L / 0.082 atm*L/mole*K *296K = find it atm*L/mole*K its just unit of gas constant don't worry about it

    • one year ago
  4. chmvijay
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    @missy101 got it ???:)

    • one year ago
  5. chmvijay
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    @aaaronq is wrong !!!

    • one year ago
  6. aaronq
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    my baddd i copied and pasted backwards

    • one year ago
  7. chmvijay
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    its all right it happens some times !!!:)

    • one year ago
  8. gsoda
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    when you go out on a limb, you sometimes fall off the tree. it's really minor anyway.

    • one year ago
  9. toxicsugar22
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    CAN YOU PLEAE HELP ME

    • one year ago
  10. missy101
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    hmmm ok so theres no specific answer? i was told i needed to find one. . . dont see how its posible :/

    • one year ago
  11. gsoda
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    if you want the numbers, give me a sec.

    • one year ago
  12. chmvijay
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    8.2 10^-4 is answer LOL:)

    • one year ago
  13. gsoda
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    you want the number of gas particles in moles, or n. using the ideal gas law: n = P V / (R T) putting everything in atm, L, and K: n = (.9985 * .02) / (0.082 * 296) mol it comes out to be 8.2 x 10(-4) mol, just like chmvijay posted

    • one year ago
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