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 one year ago
help!! how do i solve for n in:
(.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K)
sooo stumped!!!
 one year ago
help!! how do i solve for n in: (.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K) sooo stumped!!!

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aaronq
 one year ago
Best ResponseYou've already chosen the best response.0(.9985atm)(.02L)= n (0.082 atm*L/mole*K)(296K) n=[(0.082 atm*L/mole*K)(296K)]/[(.9985atm)(.02L)]

missy101
 one year ago
Best ResponseYou've already chosen the best response.0i cant get a definite number/figure for n tho? i dont understand how to caclulate 0.082 atm*L/mole*K or what it means

chmvijay
 one year ago
Best ResponseYou've already chosen the best response.1its PV =nRT n=PV/RT = .9985atm *02L / 0.082 atm*L/mole*K *296K = find it atm*L/mole*K its just unit of gas constant don't worry about it

chmvijay
 one year ago
Best ResponseYou've already chosen the best response.1@missy101 got it ???:)

chmvijay
 one year ago
Best ResponseYou've already chosen the best response.1@aaaronq is wrong !!!

aaronq
 one year ago
Best ResponseYou've already chosen the best response.0my baddd i copied and pasted backwards

chmvijay
 one year ago
Best ResponseYou've already chosen the best response.1its all right it happens some times !!!:)

gsoda
 one year ago
Best ResponseYou've already chosen the best response.0when you go out on a limb, you sometimes fall off the tree. it's really minor anyway.

toxicsugar22
 one year ago
Best ResponseYou've already chosen the best response.0CAN YOU PLEAE HELP ME

missy101
 one year ago
Best ResponseYou've already chosen the best response.0hmmm ok so theres no specific answer? i was told i needed to find one. . . dont see how its posible :/

gsoda
 one year ago
Best ResponseYou've already chosen the best response.0if you want the numbers, give me a sec.

chmvijay
 one year ago
Best ResponseYou've already chosen the best response.18.2 10^4 is answer LOL:)

gsoda
 one year ago
Best ResponseYou've already chosen the best response.0you want the number of gas particles in moles, or n. using the ideal gas law: n = P V / (R T) putting everything in atm, L, and K: n = (.9985 * .02) / (0.082 * 296) mol it comes out to be 8.2 x 10(4) mol, just like chmvijay posted
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