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missy101
 2 years ago
help!! how do i solve for n in:
(.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K)
sooo stumped!!!
missy101
 2 years ago
help!! how do i solve for n in: (.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K) sooo stumped!!!

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aaronq
 2 years ago
Best ResponseYou've already chosen the best response.0(.9985atm)(.02L)= n (0.082 atm*L/mole*K)(296K) n=[(0.082 atm*L/mole*K)(296K)]/[(.9985atm)(.02L)]

missy101
 2 years ago
Best ResponseYou've already chosen the best response.0i cant get a definite number/figure for n tho? i dont understand how to caclulate 0.082 atm*L/mole*K or what it means

chmvijay
 2 years ago
Best ResponseYou've already chosen the best response.1its PV =nRT n=PV/RT = .9985atm *02L / 0.082 atm*L/mole*K *296K = find it atm*L/mole*K its just unit of gas constant don't worry about it

chmvijay
 2 years ago
Best ResponseYou've already chosen the best response.1@missy101 got it ???:)

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.0my baddd i copied and pasted backwards

chmvijay
 2 years ago
Best ResponseYou've already chosen the best response.1its all right it happens some times !!!:)

gsoda
 2 years ago
Best ResponseYou've already chosen the best response.0when you go out on a limb, you sometimes fall off the tree. it's really minor anyway.

toxicsugar22
 2 years ago
Best ResponseYou've already chosen the best response.0CAN YOU PLEAE HELP ME

missy101
 2 years ago
Best ResponseYou've already chosen the best response.0hmmm ok so theres no specific answer? i was told i needed to find one. . . dont see how its posible :/

gsoda
 2 years ago
Best ResponseYou've already chosen the best response.0if you want the numbers, give me a sec.

chmvijay
 2 years ago
Best ResponseYou've already chosen the best response.18.2 10^4 is answer LOL:)

gsoda
 2 years ago
Best ResponseYou've already chosen the best response.0you want the number of gas particles in moles, or n. using the ideal gas law: n = P V / (R T) putting everything in atm, L, and K: n = (.9985 * .02) / (0.082 * 296) mol it comes out to be 8.2 x 10(4) mol, just like chmvijay posted
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