anonymous
  • anonymous
Solve equation by factoring. 4) x^2 - 15x=-56 3) a^2- 64=0 I just want to know how you to move numbers to the other side of the equal sign.
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
first you have to move all numbers to one side: x^2-15x+56=0
anonymous
  • anonymous
@mariannu for a, if you were to add 56 (or subtract -56) from each side, you would get what dave said, it's really just that easy.
anonymous
  • anonymous
then you are going to find common factors: (x- 8)(x-7 )=0 then set each side to 0: x-8=0 and x-7=0 solve for x on both sides, and x=8 and x=7

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
but this is solving each equation by factorin I am solving quadratics. not that.
anonymous
  • anonymous
Or my bad Xd your doing exactly what it is? XD
anonymous
  • anonymous
hahaha i was gonna say, you asked for factoring, which is one way to solve quadratics haha do you need help solving the second one?
anonymous
  • anonymous
Because the other one I did It was 5v^2=-30v-40 XD and I gott v=+- jsqaure root of -14
anonymous
  • anonymous
and I didn't have to move it to the other side. What is the easiet way to solve a^2 -64=0 and x^2-15x=-56
anonymous
  • anonymous
I just don't knwo how to solve these type of quadratrics : p XD accept the one that I have the answer for I know how to do that type of problem
anonymous
  • anonymous
the easiest way to solve x^2-15=-56 is how i outlined it above, realizing you have to move -56 to the other side is honestly the trickiest part. and a^2-64=0 is the same thing the first basic rule to solving quadratics is setting it to zero. Ill walk you through the second problem you have and explain what i am doing with each step
anonymous
  • anonymous
a^2-64=0 --------1) already set to 0 so we are good there (a- )(a+ )=0 -------2) since you know that a is squared break it up, and because 64 is negative you know one will be positive and one will be negative. 64/8=8 -----------3) testing for the factor (i chose 8 first because 8^2 is 64) (a+8)(a-8)=0-------4) plug in the factor (a+8)=0 and (a-8)=0 ----5)set both sides to 0 a=0-8 and a=0-8---6)solve both new found equations a=-8 ---------------7)-8 is the answer
anonymous
  • anonymous
Wouldn't it be like this? |dw:1366267980891:dw| the answer/
anonymous
  • anonymous
Since it has a negative? XD Because the other one that I had the answer to was switched to a positive because of imaginery solution
anonymous
  • anonymous
The i
anonymous
  • anonymous
i do not believe it would be under a square root. i do not remember my rules to imaginary numbers that well tho. and it wouldnt be plus minus because there shouldnt be a square root,
anonymous
  • anonymous
Well then ok I will just ask my teacher tomorrow morning if its correect then thank u though Xd and one more I just want to know if this is correct |dw:1366268265757:dw||dw:1366268307044:dw|
anonymous
  • anonymous
It suppose to be a -4 k
anonymous
  • anonymous
not by my work, x should equal 4 and negative 8
anonymous
  • anonymous
Well thank you though. I appreciate it. ^.^ Going to study mre for the test. XD
anonymous
  • anonymous
haha no problem. i am not sure exactly what your teacher is looking for, so i guess dont quote me exactly if i am not doing it in the form your teacher wants
anonymous
  • anonymous
Well its ok. You still helped me at least understand it ^.^ though.
anonymous
  • anonymous
haha no problem!
dwelsher
  • dwelsher
(x-7)(x-8)

Looking for something else?

Not the answer you are looking for? Search for more explanations.