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anonymous
 3 years ago
Solve equation by factoring.
4) x^2  15x=56
3) a^2 64=0
I just want to know how you to move numbers to the other side of the equal sign.
anonymous
 3 years ago
Solve equation by factoring. 4) x^2  15x=56 3) a^2 64=0 I just want to know how you to move numbers to the other side of the equal sign.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0first you have to move all numbers to one side: x^215x+56=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mariannu for a, if you were to add 56 (or subtract 56) from each side, you would get what dave said, it's really just that easy.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then you are going to find common factors: (x 8)(x7 )=0 then set each side to 0: x8=0 and x7=0 solve for x on both sides, and x=8 and x=7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but this is solving each equation by factorin I am solving quadratics. not that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Or my bad Xd your doing exactly what it is? XD

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hahaha i was gonna say, you asked for factoring, which is one way to solve quadratics haha do you need help solving the second one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Because the other one I did It was 5v^2=30v40 XD and I gott v=+ jsqaure root of 14

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and I didn't have to move it to the other side. What is the easiet way to solve a^2 64=0 and x^215x=56

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I just don't knwo how to solve these type of quadratrics : p XD accept the one that I have the answer for I know how to do that type of problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the easiest way to solve x^215=56 is how i outlined it above, realizing you have to move 56 to the other side is honestly the trickiest part. and a^264=0 is the same thing the first basic rule to solving quadratics is setting it to zero. Ill walk you through the second problem you have and explain what i am doing with each step

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a^264=0 1) already set to 0 so we are good there (a )(a+ )=0 2) since you know that a is squared break it up, and because 64 is negative you know one will be positive and one will be negative. 64/8=8 3) testing for the factor (i chose 8 first because 8^2 is 64) (a+8)(a8)=04) plug in the factor (a+8)=0 and (a8)=0 5)set both sides to 0 a=08 and a=086)solve both new found equations a=8 7)8 is the answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wouldn't it be like this? dw:1366267980891:dw the answer/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Since it has a negative? XD Because the other one that I had the answer to was switched to a positive because of imaginery solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i do not believe it would be under a square root. i do not remember my rules to imaginary numbers that well tho. and it wouldnt be plus minus because there shouldnt be a square root,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well then ok I will just ask my teacher tomorrow morning if its correect then thank u though Xd and one more I just want to know if this is correct dw:1366268265757:dwdw:1366268307044:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It suppose to be a 4 k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not by my work, x should equal 4 and negative 8

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well thank you though. I appreciate it. ^.^ Going to study mre for the test. XD

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha no problem. i am not sure exactly what your teacher is looking for, so i guess dont quote me exactly if i am not doing it in the form your teacher wants

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well its ok. You still helped me at least understand it ^.^ though.
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