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Solve equation by factoring.
4) x^2  15x=56
3) a^2 64=0
I just want to know how you to move numbers to the other side of the equal sign.
 one year ago
 one year ago
Solve equation by factoring. 4) x^2  15x=56 3) a^2 64=0 I just want to know how you to move numbers to the other side of the equal sign.
 one year ago
 one year ago

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dave0616Best ResponseYou've already chosen the best response.1
first you have to move all numbers to one side: x^215x+56=0
 one year ago

Khushal_ShahBest ResponseYou've already chosen the best response.0
@mariannu for a, if you were to add 56 (or subtract 56) from each side, you would get what dave said, it's really just that easy.
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
then you are going to find common factors: (x 8)(x7 )=0 then set each side to 0: x8=0 and x7=0 solve for x on both sides, and x=8 and x=7
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
but this is solving each equation by factorin I am solving quadratics. not that.
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Or my bad Xd your doing exactly what it is? XD
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
hahaha i was gonna say, you asked for factoring, which is one way to solve quadratics haha do you need help solving the second one?
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Because the other one I did It was 5v^2=30v40 XD and I gott v=+ jsqaure root of 14
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
and I didn't have to move it to the other side. What is the easiet way to solve a^2 64=0 and x^215x=56
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
I just don't knwo how to solve these type of quadratrics : p XD accept the one that I have the answer for I know how to do that type of problem
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
the easiest way to solve x^215=56 is how i outlined it above, realizing you have to move 56 to the other side is honestly the trickiest part. and a^264=0 is the same thing the first basic rule to solving quadratics is setting it to zero. Ill walk you through the second problem you have and explain what i am doing with each step
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
a^264=0 1) already set to 0 so we are good there (a )(a+ )=0 2) since you know that a is squared break it up, and because 64 is negative you know one will be positive and one will be negative. 64/8=8 3) testing for the factor (i chose 8 first because 8^2 is 64) (a+8)(a8)=04) plug in the factor (a+8)=0 and (a8)=0 5)set both sides to 0 a=08 and a=086)solve both new found equations a=8 7)8 is the answer
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Wouldn't it be like this? dw:1366267980891:dw the answer/
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Since it has a negative? XD Because the other one that I had the answer to was switched to a positive because of imaginery solution
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
i do not believe it would be under a square root. i do not remember my rules to imaginary numbers that well tho. and it wouldnt be plus minus because there shouldnt be a square root,
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Well then ok I will just ask my teacher tomorrow morning if its correect then thank u though Xd and one more I just want to know if this is correct dw:1366268265757:dwdw:1366268307044:dw
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
It suppose to be a 4 k
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
not by my work, x should equal 4 and negative 8
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Well thank you though. I appreciate it. ^.^ Going to study mre for the test. XD
 one year ago

dave0616Best ResponseYou've already chosen the best response.1
haha no problem. i am not sure exactly what your teacher is looking for, so i guess dont quote me exactly if i am not doing it in the form your teacher wants
 one year ago

mariannuBest ResponseYou've already chosen the best response.0
Well its ok. You still helped me at least understand it ^.^ though.
 one year ago
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