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How to prove that (2/5)(sqrt(H/2g)) is equal to
(1/5)(sqrt(2H/g)) ?
 one year ago
 one year ago
How to prove that (2/5)(sqrt(H/2g)) is equal to (1/5)(sqrt(2H/g)) ?
 one year ago
 one year ago

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dondon93Best ResponseYou've already chosen the best response.0
\[prove that \frac{ 2 }{ 5 } \sqrt{\frac{ H }{ 2g }} is equal \to \frac{ 1 }{ 5 }\sqrt{\frac{ 2H }{ g }}\]
 one year ago

RadEnBest ResponseYou've already chosen the best response.1
2/5 sqrt(H/2g) = 2/5 sqrt(H)/(sqrt(2) * sqrt(g)) multiply by sqrt(2)/sqrt(2) = 2/5 sqrt(H)/(sqrt(2) * sqrt(g)) * sqrt(2)/sqrt(2) = 2/5 sqrt(2H)/((2)*sqrt(g)) = 2/10 * sqrt(2H)/sqrt(g) = 1/5 * sqtr(2H/g)
 one year ago

dondon93Best ResponseYou've already chosen the best response.0
Thanks :) That was really helpful :)
 one year ago

tmayBest ResponseYou've already chosen the best response.0
\[25\times \left( \frac{ 2 }{ 5 } \times \sqrt{\frac{ H }{ 2g }} \right) = 25\times \left( \frac{ 1 }{ 5 } \times \sqrt{\frac{ 2H }{ g }} \right)\] \[10\times \sqrt{\frac{ H }{ 2g }}=5\times \sqrt{\frac{ 2H }{ g }}\] \[\left( 10\times \sqrt{\frac{ H }{ 2g }} \right)^{2} = \left( 5\times \sqrt{\frac{ 2H }{ g }} \right)^{2}\] \[\frac{ 100H }{ 2g } = \frac{ 25\times2H}{ g }\] \[\frac{ 50H }{ g } = \frac{ 50H }{ g }\] \[\frac{ H }{ g } = \frac{ H }{ g }\]
 one year ago
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