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DeadShot

  • 3 years ago

How do I solve x= log12 over log4?

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  1. DeadShot
    • 3 years ago
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    \[x=\frac{ \log12 }{ \log4 }\]

  2. horotat
    • 3 years ago
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    \[x = \frac{ \log 12 }{ \log 4 } = \frac{ \log 3*4 }{ \log 4 } = \frac{ \log 3 + \log 4 }{ \log 4 } = \frac{ \log 3 }{ \log 2*2 }+\frac{ \log 4 }{ \log 4 }=\frac{ \log 3 }{ \log 2 + \log 2} +1 = \frac{ \log 3 }{ 2*\log 2 }+1\] \[= \frac{ 0.47712125472 }{ 0.60205999132 }+1\approx 1.79\]

  3. DeadShot
    • 3 years ago
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    Thanks for the help!

  4. horotat
    • 3 years ago
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    your welcome :)

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