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DLS

  • 3 years ago

How to see the table and use log and anti-log? Someone explain please!

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  1. DLS
    • 3 years ago
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    \[\LARGE \log(2.23)+\log( 6.022)+{23} + 3\log(3.608)-24\] example^^

  2. electrokid
    • 3 years ago
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    |dw:1366282435383:dw|

  3. electrokid
    • 3 years ago
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    so, what about log (6.022)

  4. DLS
    • 3 years ago
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    I'm getting.. 0.7797?

  5. electrokid
    • 3 years ago
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    yep

  6. DLS
    • 3 years ago
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    :")

  7. DLS
    • 3 years ago
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    cool! thanks :D

  8. electrokid
    • 3 years ago
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    so, \(=0.3483+0.7797+3(0.5573)-1\)

  9. DLS
    • 3 years ago
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    yes i got that!

  10. electrokid
    • 3 years ago
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    are you doing logs to solve a chemistry multiplication??

  11. DLS
    • 3 years ago
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    yes!

  12. electrokid
    • 3 years ago
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    I see Avogadro's const and and the universal Gas const. :D

  13. electrokid
    • 3 years ago
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    2.23 is the number of moles of the gas?

  14. DLS
    • 3 years ago
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    nah :/ its a random no. :P I was trying this.. \[\LARGE \frac{28.88}{2.39 \times 10^{-23}}\] I got.. log(28.88) as 1.4606 log(2.39) as 0.3784 and log(10^-23) as -23 so.. 1.4606-0.3784+23 24.0822?

  15. DLS
    • 3 years ago
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    its incorrect somehow :/

  16. DLS
    • 3 years ago
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    @shubhamsrg tell this one

  17. shubhamsrg
    • 3 years ago
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    this is just log,need to take antilog now -_-

  18. DLS
    • 3 years ago
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    10^24.0822..:/

  19. DLS
    • 3 years ago
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    approximately \[\sqrt{\sqrt{10}}\] :P

  20. shubhamsrg
    • 3 years ago
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    10^24 *10^0.0822 hmm

  21. DLS
    • 3 years ago
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    kya?

  22. shubhamsrg
    • 3 years ago
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    see the table you may use either log table or antilog table for that. anyways, approximately,10^0.0822 is close to 10^0.1 i.e. it'll be around 1.2

  23. DLS
    • 3 years ago
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    dhang se antilog lena sikhade bc :/ fir kahani khatam :|

  24. shubhamsrg
    • 3 years ago
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    bc bola na raat me :| log table se sikhaya na kaise dekhte hai antilog

  25. DLS
    • 3 years ago
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    okay..

  26. DLS
    • 3 years ago
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    is their a shortcut to get the cube of a 3x3 matrix i,e A^3?

  27. shubhamsrg
    • 3 years ago
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    please follow the code of conduct of openstudy and post this as a new question

  28. shubhamsrg
    • 3 years ago
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    :D

  29. shubhamsrg
    • 3 years ago
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    itna acha laga ye bolke :')

  30. DLS
    • 3 years ago
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    -_-'

  31. DLS
    • 3 years ago
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    bhak ?

  32. shubhamsrg
    • 3 years ago
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    mujhe nahi pata koi shortcut batayenge aapko @yrelhan4

  33. yrelhan4
    • 3 years ago
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    LOL.

  34. DLS
    • 3 years ago
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    o.O

  35. DLS
    • 3 years ago
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    @electrokid

  36. electrokid
    • 3 years ago
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    you look for the mantissa in the antilogs table the same way as for the logs... but only the mantissa.. not the characteristic.

  37. electrokid
    • 3 years ago
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    then you put the number down and put a decimal the characteristic +1 number of digits from the left

  38. DLS
    • 3 years ago
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    an example ?

  39. electrokid
    • 3 years ago
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    take one

  40. electrokid
    • 3 years ago
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    3.5352

  41. electrokid
    • 3 years ago
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    look for .53 row and column "5" and difference "2"

  42. DLS
    • 3 years ago
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    0.3430 till here

  43. DLS
    • 3 years ago
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    what are we supposed to do with the decimal? and another thing.. is antilog 3.532 same thing as \[\large 10^{3.532}\] in this particular case

  44. electrokid
    • 3 years ago
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    no we are not done.. we had to accomodate the characteristic. once you get the 0.3430, from the original number, the characteristic is "3" so, we move the decimal point 4 digits to the right so, antilog of 3.5352 = 3430.0

  45. electrokid
    • 3 years ago
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    if you had 1.5352 its antilog would have been 34.30

  46. DLS
    • 3 years ago
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    I see! awesome thanks!

  47. electrokid
    • 3 years ago
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    yw

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