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allisonhe

Determine the values of sin θ, cos θ, tan θ, csc θ, sec θ, and cot θ at (-3, -4) on the terminal arm of an angle θ in standard position.

  • one year ago
  • one year ago

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  1. aussy123
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    hi, ill show you by doing it in a^2+b^2=c^2

    • one year ago
  2. aussy123
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    |dw:1366290386156:dw|

    • one year ago
  3. aussy123
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    Ok in order to figure out sin θ, cos θ, tan θ, csc θ, sec θ, and cot θ, you must know its properties.

    • one year ago
  4. aussy123
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    In quad 1 all of the properties are positive In quad 2 on sin and csc are positive In quad 3 only tan and cot are positive In quad 4 only cos and sec are positive

    • one year ago
  5. aussy123
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    For your we are in quad 3, so only tan and cot are positive.

    • one year ago
  6. aussy123
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    Now one of your properties are already given. tan θ= which is opposite over adjacent. |dw:1366290912052:dw|

    • one year ago
  7. aussy123
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    so tan θ= 3/4 Its positive because tan θ is positive in 3rd quad. and since we know tanθ, we know cotθ. cotθ is the reciprocal of tanθ, being that it is adjacent over opposite. so cot θ = 4/3. Remember dont mark negative just because it is given that way. Follow the rules of the quads.

    • one year ago
  8. aussy123
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    Now we use a^2 +b^2=c^2 formula to solve

    • one year ago
  9. aussy123
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    |dw:1366291285028:dw|

    • one year ago
  10. aussy123
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    |dw:1366291332244:dw|

    • one year ago
  11. aussy123
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    |dw:1366291457845:dw|

    • one year ago
  12. aussy123
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    Now Using what is above you can solve for the rest by following these rules. sinθ= Opposite over Hypotenuse ONLY POSITIVE IN QUAD 1 and QUAD 2 cscθ=Hypotenuse over Opposite __________________________________________________ cosθ= Adjacent over Hypotenuse ONLY POSITIVE IN QUAD 1 AND 4 secθ= Hypotenuse over Adjacent HOPE YOU FOUND THIS HELPFUL! :)

    • one year ago
  13. aussy123
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    Did you find the rest?

    • one year ago
  14. allisonhe
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    yes, and i think this helpful

    • one year ago
  15. aussy123
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    Ok Happy to know! Have a great Day!

    • one year ago
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