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Solve for x: (x - 9)2 = 1

Algebra
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x: (x - 9)^2 = 1 Is your question this one
Why is it that you don't answer the people who try to help you?
sorry yes that is I read it wrong

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x: (x - 9)^2 = 1 so this is question
yes
(x - 9)^2 = 1 (x - 9) (x - 9) = 1 Now expand the brackets. (x - 9) (x - 9) = 1 x^2 - 18x + 81 = 1 Move the 1 across the equal sign x^2 - 18x + 81 = 1 x^2 - 18x + 80 = 0 Factor x^2 - 18x + 80 = 0 (x - 8) (x - 10) = 0 x = 8 or 10
i hope this answer satisfies you
method 2: \[(x-9)^2=1\\ \therefore x-9=\pm1\\ \therefore x-9=-1\qquad\qquad x-9=1\\ \therefore x=8\qquad\qquad\qquad x=10 \]

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