anonymous
  • anonymous
Simplifying radical expressions.
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[\sqrt{4a^2}\]
anonymous
  • anonymous
|dw:1366344988992:dw|
anonymous
  • anonymous
What do i do with the a^2

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anonymous
  • anonymous
?
anonymous
  • anonymous
|dw:1366345074437:dw|
anonymous
  • anonymous
a is squared, and the opposite of a square root is to the second power. because this expression can also be written as (4a^2)^1/2. so if you take 2 and multiply it by a half, you get 1. so the answer is 2a
anonymous
  • anonymous
|dw:1366345329452:dw|
anonymous
  • anonymous
same principle is used. (4x^4)^1/2, 4*(1/2)=2= 2x^2
anonymous
  • anonymous
|dw:1366345558930:dw|
anonymous
  • anonymous
correct
anonymous
  • anonymous
|dw:1366345964027:dw|
anonymous
  • anonymous
i wanna help you through this one. what is x*x*x*x?
anonymous
  • anonymous
|dw:1366346145214:dw|
anonymous
  • anonymous
you can only pull two x's out right?
anonymous
  • anonymous
that is correct. so now you have sqrt(x^4). well in a way yes, but lets go ahead and use the formula we had.: (x^4)^1/2 4*(1/2)=2
anonymous
  • anonymous
so you have x^2
anonymous
  • anonymous
|dw:1366346262015:dw|
anonymous
  • anonymous
That would be the answer? ^^^
anonymous
  • anonymous
nope, because you origonally had :\[\sqrt{x^{4}}\] and you took the square root of that to get x^2
anonymous
  • anonymous
So what would it be? Just x^2
hartnn
  • hartnn
\(\large \sqrt{9x^4}= 3x^2\) is correct.
anonymous
  • anonymous
@hartnn and @hogie i guess i am confused as to where the sqrt(9x^4) came from, because i dont see that any where, thought 3x^2 would be correct for that
hartnn
  • hartnn
|dw:1366347228041:dw|
anonymous
  • anonymous
ohhhh i mistook that as a four, im sorry, then yes 3x^2 would be correct

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