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\[\sqrt{4a^2}\]

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What do i do with the a^2

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same principle is used. (4x^4)^1/2, 4*(1/2)=2= 2x^2

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correct

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i wanna help you through this one. what is x*x*x*x?

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you can only pull two x's out right?

so you have x^2

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That would be the answer? ^^^

nope, because you origonally had :\[\sqrt{x^{4}}\]
and you took the square root of that to get x^2

So what would it be? Just x^2

\(\large \sqrt{9x^4}= 3x^2\)
is correct.

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ohhhh i mistook that as a four, im sorry, then yes 3x^2 would be correct