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Jaweria
 3 years ago
I need help with one question of Calculus 1.
Jaweria
 3 years ago
I need help with one question of Calculus 1.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is your question?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0My question is this: USe 5 rectangles to estimate the area under the graph of: f(x) = 2x^3+2x5. from x=2 to x=7

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0And also tell whether your estimate is an over or an upper estimate, explain why?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh you are doing reimann sums? let me do some work, give me a second

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0if you can check with me that I got my 5 rectangles: 35, 93, 193, 92, 128 are they right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmmmm im gonna draw up the graph so that we know we have the same thingdw:1366346945142:dw That is the graph that i have, roughly at least, is that the same thing that you are working with?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0but can you please check my numbers plzz

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i punched this into my calculator, and the base for each rectangle would be 1, because you are using 5 rectangles, and the difference between 7 and 2 is 5. so you are basicallly looking at the height, but i got 15, 55, 131, 255, and 439. i dont see how you could get any negative because the line is going up

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i got that too but I m saying that arent we suppose to add up those rectangles?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0so whats my answer basically?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0intervals =ba/n (72)/5 =1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea, you just add what you got for the areas, so 15+55+131+255+439=839. and it would be an under estimate because it is a left side reimann sum. meaning that the left corner of the boxes hit the line

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0i thought its over estimate because its increasing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1366348904077:dw that isnt to scale, but that is the basic idea of what is going on

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0Use 5 rectangles to esitmate the area under the graph: y=x^310x^2+27x18

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0from 1<equal to x <equalt to 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so your graph is going to look like: dw:1366349701319:dw roughly of course.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0so how am I actually going to solve this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are you supposed to use 5 boxes again?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0yeah its says 5 rectangles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does this problem have the same basis as the other problem you posted? meaning you are just looking for rectangles to find the area under the graph? ok, 5 rectangles

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0and it also gives you from where to where

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0which is this dw:1366349945211:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right, so this again is the same difference as the other problem, (5) so each will have the same base length of 1

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0can we work on this together little bit ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes of course we can. how would you like to do that? i would like to help you in the best way that suits you

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0can you first show me how to get the value for the 1st rectangle?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, i personally am using a graphing calculator because i find it is the easiest way to do it. are you using the same, or are you trying to do this by hand?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0we are not allow to use calculator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, that is fine, that just means that we are going to have to find the value for y at every point. and our points are going to be 1,2,3,4,5,6. do you think you can solve for y using the equation for these six points? and would you like to solve them on your own, and then post them, and we can compare values?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0ok so first I m using 1 for my y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nope, we are gonna be solving for y, so we are going to plug 1,2,3,4,5 and 6 in for x into the equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so solve for y, using those six values and let me know what you get

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0so let me get their values then I ll tell you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, and solve for 1,2,3,4,5 that will give us 5 rectangles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did you get the values?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmmm, that first one isnt correct try it again

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is correct, now go ahead and fine the y value for 4 and 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did you solve for them? sorry if i am rushing you, i dont mean to be

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0I m sorry my stupid laptop is giving me tough time

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its all good no worries

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you need, two more values, but 10 is not correct, you are going to need to solve for 4 and 5. go ahead and do that and let me know what you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is correct. now we need to find the area of each of those rectangles. and the base of each of those rectangles is 1, so the area of each of those rectangles will be equal to the value, so we have 0,4,0,6,8. so now all we need to do is add those values.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so A=0+4+068. what do you get for area?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i got that too all of them

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0but then how am i suppose to find an area add them up?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0and then divide it by some number?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we found that the base of each of those rectangles would be 1. and the area of a rectangle is b*h. we found the height by finding the y. so in essence you are multplying each of the values we found (0,4,0,6,8) by one, but they will equal the values themselves. so what wer are actually doing is A=0(1)+4(1)+0(1)6(1)8(1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you solve for area from that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do you get for area?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thta is right. is that what you were reffering to earlier when you said 10?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh im extremely sorry, i did not realize that is what you were referrring to. i really do feel bad, im sorry. but yes it is 10, and it would still be an under estimate because we used a left corner triangle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha ok. well im glad we went through it still. yes the area under the graph by the estimate of 5 rectangles is 10. do you understand how we came to the answer?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0yup I completely did thanks a lot:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0absolutely no problem!

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.0I should go to sleep now its really late take care bye.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i hear ya haha. take care and good luck in your studies
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