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There are six chairs in a row. Person A picks one of the chairs at random. Then Person B picks a chair at random from the five chairs that remain. Find the chance that they pick chairs that are next to each other.

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there are 5 ways to be seated next to each other , then times 2 because you can have AB or BA. there are a total of 6x5 ways to choose two chairs . so the probability is ( 5x2) / (6x5) = 10/30 = 1/3
do you agree?

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Other answers:

ya that's correct. I too had a problem with this one. I computed the 10 right and mistook the sample space to be 25 and not 30. This one is right.

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