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Assume from electricity the following equations which are valid in free space. (They are called Maxwell equations)
 one year ago
 one year ago
Assume from electricity the following equations which are valid in free space. (They are called Maxwell equations)
 one year ago
 one year ago

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gerryliyanaBest ResponseYou've already chosen the best response.0
\(\nabla . \bar E = 0 \) \(\nabla . \bar H = 0 \) \(\nabla \times \bar E=\mu (\frac{ \delta \bar H }{ \delta t }\)) \(\nabla \times \bar E=\epsilon (\frac{ \delta \bar E }{ \delta t }\)) from them show that any component of \(\ \bar E\) or \(\ \bar H \) satisfies the wave equation with \(\ v = (\epsilon \mu )^{1/2}\). Hint: use vector identity!
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
have idea @CarlosGP ????
 one year ago

CarlosGPBest ResponseYou've already chosen the best response.5
Yes. I have. You should start by correcting the fourth equation. The right one is: \[\nabla \times H=\epsilon \frac{ \delta E }{ \delta t } \] How to obtain the wave equation from this particular case of Maxwell equations, can be found in any book of Electromagnetism
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
@CarlosGP and then what should i do ??
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
Where are you getting these \[\frac{ \delta^{2} E }{ \delta^{2}t } =  \omega ^{2} E_{s} \] ????
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
then for Ey \[E_{ys} = E_{ys} (x) \rightarrow \frac{ \delta^{2}E_{ys} (x) }{ \delta z^{2} } =0 ; \frac{ \delta^{2}E_{ys}(x) }{ \delta y^{2} }=0 \] \[\frac{ \delta^{2}E_{ys} (x) }{ \delta x^{2} } + \left( \frac{ \omega }{ v } \right)^{2} E_{ys} = 0\] and for z \[E_{zs} = E_{zs} (x) \rightarrow \frac{ \delta^{2} E_{zs}(x) }{ \delta z^{2} }=0 ; \frac{ \delta^{2}E_{zs}(x) }{ \delta y^{2} }=0\] \[\frac{ \delta^{2} E_{zs} (x) }{ \delta x^{2} } + \left( \frac{ \omega }{ v } \right)^{2} E_{zs} =0\] correct me if i wrong.., :)
 one year ago

BAdhiBest ResponseYou've already chosen the best response.0
we assume that E field is time harmonic, i.e. $$E=E_0e^{j\omega t}\implies \frac{d^2E}{dt^2}=\omega^2E_0e^{j\omega t}=\omega^2E$$
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
cool @BAdhi ..., then.., what's the next? would you like to check my work above before you?
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
hi @Jonask nice to meet you :)
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
nice to meet you too are you taking electrıcty wıth edx
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
no i'm not.., i'm taking 2.01x Elements of Structures
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
@Jonask , would you like to check my work above??
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
not famılıar wıth these sorry
 one year ago

perlBest ResponseYou've already chosen the best response.0
whats elements of structures?
 one year ago
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