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 one year ago
Assume from electricity the following equations which are valid in free space. (They are called Maxwell equations)
 one year ago
Assume from electricity the following equations which are valid in free space. (They are called Maxwell equations)

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gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0\(\nabla . \bar E = 0 \) \(\nabla . \bar H = 0 \) \(\nabla \times \bar E=\mu (\frac{ \delta \bar H }{ \delta t }\)) \(\nabla \times \bar E=\epsilon (\frac{ \delta \bar E }{ \delta t }\)) from them show that any component of \(\ \bar E\) or \(\ \bar H \) satisfies the wave equation with \(\ v = (\epsilon \mu )^{1/2}\). Hint: use vector identity!

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0have idea @CarlosGP ????

CarlosGP
 one year ago
Best ResponseYou've already chosen the best response.5Yes. I have. You should start by correcting the fourth equation. The right one is: \[\nabla \times H=\epsilon \frac{ \delta E }{ \delta t } \] How to obtain the wave equation from this particular case of Maxwell equations, can be found in any book of Electromagnetism

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0@CarlosGP and then what should i do ??

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0Where are you getting these \[\frac{ \delta^{2} E }{ \delta^{2}t } =  \omega ^{2} E_{s} \] ????

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0then for Ey \[E_{ys} = E_{ys} (x) \rightarrow \frac{ \delta^{2}E_{ys} (x) }{ \delta z^{2} } =0 ; \frac{ \delta^{2}E_{ys}(x) }{ \delta y^{2} }=0 \] \[\frac{ \delta^{2}E_{ys} (x) }{ \delta x^{2} } + \left( \frac{ \omega }{ v } \right)^{2} E_{ys} = 0\] and for z \[E_{zs} = E_{zs} (x) \rightarrow \frac{ \delta^{2} E_{zs}(x) }{ \delta z^{2} }=0 ; \frac{ \delta^{2}E_{zs}(x) }{ \delta y^{2} }=0\] \[\frac{ \delta^{2} E_{zs} (x) }{ \delta x^{2} } + \left( \frac{ \omega }{ v } \right)^{2} E_{zs} =0\] correct me if i wrong.., :)

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0we assume that E field is time harmonic, i.e. $$E=E_0e^{j\omega t}\implies \frac{d^2E}{dt^2}=\omega^2E_0e^{j\omega t}=\omega^2E$$

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0cool @BAdhi ..., then.., what's the next? would you like to check my work above before you?

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0hi @Jonask nice to meet you :)

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0nice to meet you too are you taking electrıcty wıth edx

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0no i'm not.., i'm taking 2.01x Elements of Structures

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0@Jonask , would you like to check my work above??

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0not famılıar wıth these sorry

perl
 one year ago
Best ResponseYou've already chosen the best response.0whats elements of structures?
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