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anonymous
 3 years ago
Assume from electricity the following equations which are valid in free space. (They are called Maxwell equations)
anonymous
 3 years ago
Assume from electricity the following equations which are valid in free space. (They are called Maxwell equations)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(\nabla . \bar E = 0 \) \(\nabla . \bar H = 0 \) \(\nabla \times \bar E=\mu (\frac{ \delta \bar H }{ \delta t }\)) \(\nabla \times \bar E=\epsilon (\frac{ \delta \bar E }{ \delta t }\)) from them show that any component of \(\ \bar E\) or \(\ \bar H \) satisfies the wave equation with \(\ v = (\epsilon \mu )^{1/2}\). Hint: use vector identity!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0have idea @CarlosGP ????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. I have. You should start by correcting the fourth equation. The right one is: \[\nabla \times H=\epsilon \frac{ \delta E }{ \delta t } \] How to obtain the wave equation from this particular case of Maxwell equations, can be found in any book of Electromagnetism

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@CarlosGP and then what should i do ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Where are you getting these \[\frac{ \delta^{2} E }{ \delta^{2}t } =  \omega ^{2} E_{s} \] ????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then for Ey \[E_{ys} = E_{ys} (x) \rightarrow \frac{ \delta^{2}E_{ys} (x) }{ \delta z^{2} } =0 ; \frac{ \delta^{2}E_{ys}(x) }{ \delta y^{2} }=0 \] \[\frac{ \delta^{2}E_{ys} (x) }{ \delta x^{2} } + \left( \frac{ \omega }{ v } \right)^{2} E_{ys} = 0\] and for z \[E_{zs} = E_{zs} (x) \rightarrow \frac{ \delta^{2} E_{zs}(x) }{ \delta z^{2} }=0 ; \frac{ \delta^{2}E_{zs}(x) }{ \delta y^{2} }=0\] \[\frac{ \delta^{2} E_{zs} (x) }{ \delta x^{2} } + \left( \frac{ \omega }{ v } \right)^{2} E_{zs} =0\] correct me if i wrong.., :)

BAdhi
 3 years ago
Best ResponseYou've already chosen the best response.0we assume that E field is time harmonic, i.e. $$E=E_0e^{j\omega t}\implies \frac{d^2E}{dt^2}=\omega^2E_0e^{j\omega t}=\omega^2E$$

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cool @BAdhi ..., then.., what's the next? would you like to check my work above before you?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hi @Jonask nice to meet you :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nice to meet you too are you taking electrıcty wıth edx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no i'm not.., i'm taking 2.01x Elements of Structures

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Jonask , would you like to check my work above??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not famılıar wıth these sorry

perl
 3 years ago
Best ResponseYou've already chosen the best response.0whats elements of structures?
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