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ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Should I use \(a^3 + b^3 = (a + b)(a^2  ab+b^2)\)?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Or am I complicating it?
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
The factorization is not that easy to find
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but Wolfram does give a simple solution.
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
Why simple? Complex numbers join the party and you can't even find a real root to get started...
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but the solution is simple. :P This is 9th grade math... I don't know why I'm not able to do this one
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
Gimme a minute...
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
\[\begin{array}{l} 9{x^4} + 9{x^3} + 8{x^2} + 9x + 9 = 0 \\ 9({x^4} + {x^3} + 2{x^2} + x + 1) = 10{x^2} \\ 9{({x^2} + 1)^2} + 9x({x^2} + 1)  10{x^2} = 0 \\ {\left( {3({x^2} + 1)} \right)^2} + \left( {3({x^2} + 1)} \right)(3x)  10{x^2} = 0 \\ {\left( {3({x^2} + 1)} \right)^2}  \left( {3({x^2} + 1)} \right)(2x) + \left( {3({x^2} + 1)} \right)(5x)  (2x)(5x) = 0 \\ \end{array}\] Actually 4 mins already, and I left out the last step :P
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Ha, but how did you choose to add \(10x^2\) to both sides? Doesn't it seem arbitrary?
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
No it does not. At first glance I was going to add x^2 only, but then to complete the square I have to add another 9x^2
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
How do you complete the square in a polynomial with degree 3 or higher? :O
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[(3x)^2 + (3)^2\]has the middle term \(2(3x)^2 (3)^2 = 18x^2\). Thanks :)
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
just pick the dominant term with even degree and add/subtract until you have a complete square
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
KUDOS FOR DRAWAR , GREAT WORK MR. DRAWAR :)
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
Thanks for that @mathslover :) Oh kids have to study so many things nowadays...
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
@drawar Can you send me the link where you learnt how to do this?
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
Sorry I don't have any link to share here, just do more practice and you'll eventually get the hang of it!
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
Just out of curiosity, are you a 9th grader?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Just started 9th grade.
 one year ago

drawar Group TitleBest ResponseYou've already chosen the best response.2
Nice, all the best with your study then!
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Thanks!
 one year ago
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