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gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
Show that: \[P_{2} (\cos \theta) = \frac{ 1 }{ 4 } (1+ 3 \cos (2\theta))\]
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
wanna help me again @mukushla ??
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
@oldrin.bataku @ajprincess @amistre64 @abb0t wanna help me ?
 one year ago

oldrin.bataku Group TitleBest ResponseYou've already chosen the best response.2
This is still vague... but:$$P(x)=\frac12\left(3x^21\right)\\P(\cos \theta)=\frac12\left(3\cos^2 \theta1\right)$$We use a few trigonometric identities to rewrite our \(\cos^2\theta\):$$\cos(\alpha+\beta)=\cos\alpha\cos\beta\sin\alpha\sin\beta\\\cos2\theta=\cos(\theta+\theta)=\cos^2\theta\sin^2\theta\\\cos^2\theta+\sin^2\theta=1\implies\sin^2\theta=1\cos^2\theta\\\text{so }\cos2\theta=\cos^2\theta1+\cos^2\theta=2\cos^2\theta1\\\text{so }\cos^2\theta=\frac{\cos2\theta+1}{2}$$Now actually use these:$$P(\cos\theta)=\frac12\left(\frac{3\cos2\theta+3}{2}1\right)=\frac14\left(3\cos2\theta+1\right)$$
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
@oldrin.bataku Cool hah.., thanks mate ;)
 one year ago
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