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kevincourtes

  • 3 years ago

Need help with this problem...

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  1. kevincourtes
    • 3 years ago
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  2. kausarsalley
    • 3 years ago
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    http://www.icoachmath.com/problems/solution.aspx?Qversid=fqLF3Cf96cQ=#

  3. cwrw238
    • 3 years ago
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    if y varies directly with x then y = kx where k is a constant find k by plugging in the given values of y and x when y = 3 , x = 2 3 = k * 2 can you find k?

  4. kevincourtes
    • 3 years ago
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    @cwrw238 3/2?

  5. cwrw238
    • 3 years ago
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    divide both sides of the equation by 2 to find k right

  6. kevincourtes
    • 3 years ago
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    @cwrw238 so the answers D right?

  7. cwrw238
    • 3 years ago
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    so now we have |dw:1366501494754:dw|

  8. kevincourtes
    • 3 years ago
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    @cwrw238 can you help me with this one?

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  9. cwrw238
    • 3 years ago
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    can u see what i've done i've substituted 3/2 for k now to find y when x = 3 plug in 3 for x and work out the value of y

  10. kevincourtes
    • 3 years ago
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    @cwrw238 9/2?

  11. cwrw238
    • 3 years ago
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    right

  12. cwrw238
    • 3 years ago
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    if y varies directly by x y = kx and k = y/x

  13. kevincourtes
    • 3 years ago
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    @cwrw238 i dont understand the 2nd problem

  14. cwrw238
    • 3 years ago
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    now plug in the values of x and y y = -3 and x = 1 k = -3 / 1 = -3 y = -9 and x = 3 k = -9/3 = -3 also k = -15 / 5 = -3 so is this varying direct;y?

  15. kevincourtes
    • 3 years ago
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    @cwrw238 no?

  16. cwrw238
    • 3 years ago
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    these values of y and x do satisfy the relation y = kx which is direct variation do you see that?

  17. cwrw238
    • 3 years ago
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    k - -3 in all 3 cases

  18. kevincourtes
    • 3 years ago
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    @cwrw238 ohhhh okay so the answer would be A?

  19. cwrw238
    • 3 years ago
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    right there are 2 types of variation direct where y = kx and indirect where y = k / x

  20. kevincourtes
    • 3 years ago
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    @cwrw238 thanks

  21. kevincourtes
    • 3 years ago
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    @cwrw238 also can you help me with this last one?

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