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kausarsalley
 one year ago
Best ResponseYou've already chosen the best response.0http://www.icoachmath.com/problems/solution.aspx?Qversid=fqLF3Cf96cQ=#

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2if y varies directly with x then y = kx where k is a constant find k by plugging in the given values of y and x when y = 3 , x = 2 3 = k * 2 can you find k?

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2divide both sides of the equation by 2 to find k right

kevincourtes
 one year ago
Best ResponseYou've already chosen the best response.0@cwrw238 so the answers D right?

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2so now we have dw:1366501494754:dw

kevincourtes
 one year ago
Best ResponseYou've already chosen the best response.0@cwrw238 can you help me with this one?

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2can u see what i've done i've substituted 3/2 for k now to find y when x = 3 plug in 3 for x and work out the value of y

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2if y varies directly by x y = kx and k = y/x

kevincourtes
 one year ago
Best ResponseYou've already chosen the best response.0@cwrw238 i dont understand the 2nd problem

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2now plug in the values of x and y y = 3 and x = 1 k = 3 / 1 = 3 y = 9 and x = 3 k = 9/3 = 3 also k = 15 / 5 = 3 so is this varying direct;y?

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2these values of y and x do satisfy the relation y = kx which is direct variation do you see that?

kevincourtes
 one year ago
Best ResponseYou've already chosen the best response.0@cwrw238 ohhhh okay so the answer would be A?

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2right there are 2 types of variation direct where y = kx and indirect where y = k / x

kevincourtes
 one year ago
Best ResponseYou've already chosen the best response.0@cwrw238 also can you help me with this last one?
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