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what are you solving for?
x=15/6 solve for one variable and plug it back into the original equation to get the other.. so 8x-4y=20 4y=8x-20 y=(8x-20)/4----y=2x-5 plug y value back into original equation?? this may not be right!!!
8x-4y=20 first divide everything by 4 and you get: 8x/4-4y/4=20/4 2x-y=5 add y 2x-y+y=5+y 2x=5+y divide by 2 to isolate x 2x/2=(5+y)/2 x=(5+y)/2 so far you solved for x Now if you want to solve for y here is what you do: 8x-4y=20 first divide everything by 4 and you get: 8x/4-4y/4=20/4 2x-y=5 subtract 2x 2x-2x-y=5-2x -y=5-2x divide by (-1) both sides of the equation (-1)(-y)=(-1)(5-2x) y=-5+2x or y=2x-5 This is as far as you can go with these kind of equation, unless you are given more info.

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Other answers:

dwelsher suggests to plug back into the original equation, but that would give you 0=0... and you did not find x nor y.

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