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 one year ago
Solve the semiimfinite plate problem if the bottom edge of width 20 is held at
T = 0o for 0 < x < 10, and T = 100o for 10< x<20. And the other sides are at 0o
 one year ago
Solve the semiimfinite plate problem if the bottom edge of width 20 is held at T = 0o for 0 < x < 10, and T = 100o for 10< x<20. And the other sides are at 0o

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gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0Solve the semiimfinite plate problem if the bottom edge of width 20 is held at: \[T = 0^{o} \rightarrow 0 < x < 10\]\[T = 100^{o} \rightarrow 10 < x < 20\] and the other sides are at \(\ 0^{o}\)

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0dw:1366518323249:dw @oldrin.bataku hbu mate ??

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0have idea ?? i'm little bit confused for \(\ 100^{o}\) > 10 < x < 20..,

LolWolf
 one year ago
Best ResponseYou've already chosen the best response.0Is this similar to the Fourier heat problem?

mukushla
 one year ago
Best ResponseYou've already chosen the best response.1gerry this is the same problem except that boundary condition for bottom edge

mukushla
 one year ago
Best ResponseYou've already chosen the best response.1we had (note that 10 turens to 20)\[T = \sum_{n=1}^{\infty} a_ne^{\frac{n \pi}{20} y} \sin (\frac{n \pi}{20} x)\]now for evaluating \(a_n\) using fourier series\[T = 0 \rightarrow 0 < x < 10 \\ T = 100 \rightarrow 10 < x < 20 \\ \ \ @ \ \ y=0\]so\[a_n=\frac{2}{20} (\int_{0}^{10} 0 \times \sin (\frac{n \pi}{20} x) \ \text{d}x+\int_{10}^{20} 100 \times \sin (\frac{n \pi}{20} x) \ \text{d}x)\]\[a_n=\frac{1}{10} \int_{10}^{20} 100 \times \sin (\frac{n \pi}{20} x) \ \text{d}x=...\]makes sense?
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