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Solve the semiimfinite plate problem if the bottom edge of width 20 is held at
T = 0o for 0 < x < 10, and T = 100o for 10< x<20. And the other sides are at 0o
 one year ago
 one year ago
Solve the semiimfinite plate problem if the bottom edge of width 20 is held at T = 0o for 0 < x < 10, and T = 100o for 10< x<20. And the other sides are at 0o
 one year ago
 one year ago

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gerryliyanaBest ResponseYou've already chosen the best response.0
Solve the semiimfinite plate problem if the bottom edge of width 20 is held at: \[T = 0^{o} \rightarrow 0 < x < 10\]\[T = 100^{o} \rightarrow 10 < x < 20\] and the other sides are at \(\ 0^{o}\)
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
dw:1366518323249:dw @oldrin.bataku hbu mate ??
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
have idea ?? i'm little bit confused for \(\ 100^{o}\) > 10 < x < 20..,
 one year ago

LolWolfBest ResponseYou've already chosen the best response.0
Is this similar to the Fourier heat problem?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
gerry this is the same problem except that boundary condition for bottom edge
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
we had (note that 10 turens to 20)\[T = \sum_{n=1}^{\infty} a_ne^{\frac{n \pi}{20} y} \sin (\frac{n \pi}{20} x)\]now for evaluating \(a_n\) using fourier series\[T = 0 \rightarrow 0 < x < 10 \\ T = 100 \rightarrow 10 < x < 20 \\ \ \ @ \ \ y=0\]so\[a_n=\frac{2}{20} (\int_{0}^{10} 0 \times \sin (\frac{n \pi}{20} x) \ \text{d}x+\int_{10}^{20} 100 \times \sin (\frac{n \pi}{20} x) \ \text{d}x)\]\[a_n=\frac{1}{10} \int_{10}^{20} 100 \times \sin (\frac{n \pi}{20} x) \ \text{d}x=...\]makes sense?
 one year ago
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