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gerryliyana

  • 2 years ago

Solve the semi-imfinite plate problem if the bottom edge of width 20 is held at T = 0o for 0 < x < 10, and T = 100o for 10< x<20. And the other sides are at 0o

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  1. gerryliyana
    • 2 years ago
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    Solve the semi-imfinite plate problem if the bottom edge of width 20 is held at: \[T = 0^{o} \rightarrow 0 < x < 10\]\[T = 100^{o} \rightarrow 10 < x < 20\] and the other sides are at \(\ 0^{o}\)

  2. gerryliyana
    • 2 years ago
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    |dw:1366518323249:dw| @oldrin.bataku hbu mate ??

  3. gerryliyana
    • 2 years ago
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    have idea ?? i'm little bit confused for \(\ 100^{o}\) ---> 10 < x < 20..,

  4. LolWolf
    • 2 years ago
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    Is this similar to the Fourier heat problem?

  5. mukushla
    • 2 years ago
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    gerry this is the same problem except that boundary condition for bottom edge

  6. mukushla
    • 2 years ago
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    we had (note that 10 turens to 20)\[T = \sum_{n=1}^{\infty} a_ne^{-\frac{n \pi}{20} y} \sin (\frac{n \pi}{20} x)\]now for evaluating \(a_n\) using fourier series\[T = 0 \rightarrow 0 < x < 10 \\ T = 100 \rightarrow 10 < x < 20 \\ \ \ @ \ \ y=0\]so\[a_n=\frac{2}{20} (\int_{0}^{10} 0 \times \sin (\frac{n \pi}{20} x) \ \text{d}x+\int_{10}^{20} 100 \times \sin (\frac{n \pi}{20} x) \ \text{d}x)\]\[a_n=\frac{1}{10} \int_{10}^{20} 100 \times \sin (\frac{n \pi}{20} x) \ \text{d}x=...\]makes sense?

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