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Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1ok, so you see that as the function approaches 1 and 1 that it is undefined, right? So what does that tell you about the denominator?

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1oh wait, i see that you've already narrowed it down to those three, thats good

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1you also see that as x approaches infinity, that the functions goes to zero. That also tells you something about the denominator, but do you konw what?

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1@u0860867 this question is directed towards you man, see if you can figure it out :)

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0does it mean it has a horizontal asymptote i am guessing @Khushal_Shah

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1well, yes, we see that it has a horizontal asymtote, but what conditions need to be met for it to have one? Does the numerator have to be larger than the denominator, or the other way around?

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0the denominator needs to be larger so that it approaches 0

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1exactly! now of those three options you selected, which one appears to be the right one?

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0so will it be the 3rd one

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1well, not exactly, it can still be either the second or the third one actually

Khushal_Shah
 one year ago
Best ResponseYou've already chosen the best response.1they say to select all that apply, so I believe the second and third would both be correct options
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