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u0860867 Group Title

Urgent help needed pls help solve this question Please Thanks

  • one year ago
  • one year ago

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  1. u0860867 Group Title
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    • one year ago
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  2. Khushal_Shah Group Title
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    ok, so you see that as the function approaches 1 and -1 that it is undefined, right? So what does that tell you about the denominator?

    • one year ago
  3. Khushal_Shah Group Title
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    oh wait, i see that you've already narrowed it down to those three, thats good

    • one year ago
  4. Khushal_Shah Group Title
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    you also see that as x approaches infinity, that the functions goes to zero. That also tells you something about the denominator, but do you konw what?

    • one year ago
  5. Khushal_Shah Group Title
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    @u0860867 this question is directed towards you man, see if you can figure it out :)

    • one year ago
  6. u0860867 Group Title
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    does it mean it has a horizontal asymptote i am guessing @Khushal_Shah

    • one year ago
  7. Khushal_Shah Group Title
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    well, yes, we see that it has a horizontal asymtote, but what conditions need to be met for it to have one? Does the numerator have to be larger than the denominator, or the other way around?

    • one year ago
  8. u0860867 Group Title
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    the denominator needs to be larger so that it approaches 0

    • one year ago
  9. Khushal_Shah Group Title
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    exactly! now of those three options you selected, which one appears to be the right one?

    • one year ago
  10. u0860867 Group Title
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    so will it be the 3rd one

    • one year ago
  11. Khushal_Shah Group Title
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    well, not exactly, it can still be either the second or the third one actually

    • one year ago
  12. Khushal_Shah Group Title
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    they say to select all that apply, so I believe the second and third would both be correct options

    • one year ago
  13. u0860867 Group Title
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    thanks

    • one year ago
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