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ok, so you see that as the function approaches 1 and -1 that it is undefined, right? So what does that tell you about the denominator?
oh wait, i see that you've already narrowed it down to those three, thats good
you also see that as x approaches infinity, that the functions goes to zero. That also tells you something about the denominator, but do you konw what?
well, yes, we see that it has a horizontal asymtote, but what conditions need to be met for it to have one? Does the numerator have to be larger than the denominator, or the other way around?
the denominator needs to be larger so that it approaches 0
exactly! now of those three options you selected, which one appears to be the right one?
so will it be the 3rd one
well, not exactly, it can still be either the second or the third one actually
they say to select all that apply, so I believe the second and third would both be correct options