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u0860867

  • one year ago

Urgent help needed pls help solve this question Please Thanks

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  1. u0860867
    • one year ago
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  2. Khushal_Shah
    • one year ago
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    ok, so you see that as the function approaches 1 and -1 that it is undefined, right? So what does that tell you about the denominator?

  3. Khushal_Shah
    • one year ago
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    oh wait, i see that you've already narrowed it down to those three, thats good

  4. Khushal_Shah
    • one year ago
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    you also see that as x approaches infinity, that the functions goes to zero. That also tells you something about the denominator, but do you konw what?

  5. Khushal_Shah
    • one year ago
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    @u0860867 this question is directed towards you man, see if you can figure it out :)

  6. u0860867
    • one year ago
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    does it mean it has a horizontal asymptote i am guessing @Khushal_Shah

  7. Khushal_Shah
    • one year ago
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    well, yes, we see that it has a horizontal asymtote, but what conditions need to be met for it to have one? Does the numerator have to be larger than the denominator, or the other way around?

  8. u0860867
    • one year ago
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    the denominator needs to be larger so that it approaches 0

  9. Khushal_Shah
    • one year ago
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    exactly! now of those three options you selected, which one appears to be the right one?

  10. u0860867
    • one year ago
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    so will it be the 3rd one

  11. Khushal_Shah
    • one year ago
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    well, not exactly, it can still be either the second or the third one actually

  12. Khushal_Shah
    • one year ago
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    they say to select all that apply, so I believe the second and third would both be correct options

  13. u0860867
    • one year ago
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    thanks

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