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u0860867

  • 2 years ago

Urgent help needed pls help solve this question Please Thanks

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  1. u0860867
    • 2 years ago
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  2. Khushal_Shah
    • 2 years ago
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    ok, so you see that as the function approaches 1 and -1 that it is undefined, right? So what does that tell you about the denominator?

  3. Khushal_Shah
    • 2 years ago
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    oh wait, i see that you've already narrowed it down to those three, thats good

  4. Khushal_Shah
    • 2 years ago
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    you also see that as x approaches infinity, that the functions goes to zero. That also tells you something about the denominator, but do you konw what?

  5. Khushal_Shah
    • 2 years ago
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    @u0860867 this question is directed towards you man, see if you can figure it out :)

  6. u0860867
    • 2 years ago
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    does it mean it has a horizontal asymptote i am guessing @Khushal_Shah

  7. Khushal_Shah
    • 2 years ago
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    well, yes, we see that it has a horizontal asymtote, but what conditions need to be met for it to have one? Does the numerator have to be larger than the denominator, or the other way around?

  8. u0860867
    • 2 years ago
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    the denominator needs to be larger so that it approaches 0

  9. Khushal_Shah
    • 2 years ago
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    exactly! now of those three options you selected, which one appears to be the right one?

  10. u0860867
    • 2 years ago
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    so will it be the 3rd one

  11. Khushal_Shah
    • 2 years ago
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    well, not exactly, it can still be either the second or the third one actually

  12. Khushal_Shah
    • 2 years ago
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    they say to select all that apply, so I believe the second and third would both be correct options

  13. u0860867
    • 2 years ago
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    thanks

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