In an egg carton there are 12 eggs, of which 9 are hard-boiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.

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\[P(1\ raw)=\frac{3C1\times 9C5}{12C6}\]

i dont understant this formulae

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