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KABRIC
 2 years ago
In an egg carton there are 12 eggs, of which 9 are hardboiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.
KABRIC
 2 years ago
In an egg carton there are 12 eggs, of which 9 are hardboiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.

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kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0\[P(1\ raw)=\frac{3C1\times 9C5}{12C6}\]

KABRIC
 2 years ago
Best ResponseYou've already chosen the best response.0i dont understant this formulae

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0The hpergeometric distribution applies in this case. The formula is \[p(x)=\frac{\left(\begin{matrix}a \\ x\end{matrix}\right)\left(\begin{matrix}b \\ nx\end{matrix}\right)}{\left(\begin{matrix}a+b \\ n\end{matrix}\right)}\] The values from the question are a = 3, b = 9, n = 6 and x = 1 The required probability is found from \[3\times \frac{\frac{9!}{5!4!}}{\frac{12!}{6!6!}}\]

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0The calculation for the required probability simplifies to the following after cancellations \[P(1\ raw)=\frac{3\times 6\times 6\times5}{12\times 11\times 10}=you\ can\ calculate\]

KABRIC
 2 years ago
Best ResponseYou've already chosen the best response.0its 0.4090 so this is the required answer or do i have to do something more

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0The rounded decimal answer is 0.4091. The exact answer is the fraction \[\frac{9}{22}\]

KABRIC
 2 years ago
Best ResponseYou've already chosen the best response.0ok thank you very much now i got it

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0The answer 9/22 is correct. Are you sure that you copied the question correctly?

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0What other answer do you have?

KABRIC
 2 years ago
Best ResponseYou've already chosen the best response.0i mean what could be wrong here

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0How did you submit the answer? Did you use a decimal value or a fractional value?

perl
 2 years ago
Best ResponseYou've already chosen the best response.2hello, the question asks "at least one raw egg' Let X = # of raw eggs. P( at least one raw egg ) = P( X > = 1 ) = P ( X = 1 or X = 2 or X = 3) However we can simplify computation by using the complement approach. P(A) = 1  P(A') P ( at least one raw egg) = 1 P ( X= 0 raw eggs) = 1  ( 3C0 * 9C6 ) / 12C6 the answer is 10/11

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0Yes @perl is correct. I did not read the question carefully. My bad :(
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