KABRIC Group Title In an egg carton there are 12 eggs, of which 9 are hard-boiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw. one year ago one year ago

1. kropot72 Group Title

$P(1\ raw)=\frac{3C1\times 9C5}{12C6}$

2. KABRIC Group Title

i dont understant this formulae

3. kropot72 Group Title

The hpergeometric distribution applies in this case. The formula is $p(x)=\frac{\left(\begin{matrix}a \\ x\end{matrix}\right)\left(\begin{matrix}b \\ n-x\end{matrix}\right)}{\left(\begin{matrix}a+b \\ n\end{matrix}\right)}$ The values from the question are a = 3, b = 9, n = 6 and x = 1 The required probability is found from $3\times \frac{\frac{9!}{5!4!}}{\frac{12!}{6!6!}}$

4. kropot72 Group Title

hypergeometric*

5. kropot72 Group Title

The calculation for the required probability simplifies to the following after cancellations $P(1\ raw)=\frac{3\times 6\times 6\times5}{12\times 11\times 10}=you\ can\ calculate$

6. KABRIC Group Title

its 0.4090 so this is the required answer or do i have to do something more

7. kropot72 Group Title

The rounded decimal answer is 0.4091. The exact answer is the fraction $\frac{9}{22}$

8. KABRIC Group Title

ok thank you very much now i got it

9. kropot72 Group Title

You're welcome :)

10. KABRIC Group Title

11. KABRIC Group Title

can you recheck it plz

12. kropot72 Group Title

The answer 9/22 is correct. Are you sure that you copied the question correctly?

13. KABRIC Group Title

yes infact i did

14. kropot72 Group Title

What other answer do you have?

15. KABRIC Group Title

i tried yours

16. KABRIC Group Title

i mean what could be wrong here

17. kropot72 Group Title

How did you submit the answer? Did you use a decimal value or a fractional value?

18. perl Group Title

hello, the question asks "at least one raw egg' Let X = # of raw eggs. P( at least one raw egg ) = P( X > = 1 ) = P ( X = 1 or X = 2 or X = 3) However we can simplify computation by using the complement approach. P(A) = 1 - P(A') P ( at least one raw egg) = 1- P ( X= 0 raw eggs) = 1 - ( 3C0 * 9C6 ) / 12C6 the answer is 10/11

19. kropot72 Group Title

Yes @perl is correct. I did not read the question carefully. My bad :(

20. perl Group Title

no worries :)

21. KABRIC Group Title

thanks perl