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KABRIC
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In an egg carton there are 12 eggs, of which 9 are hardboiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.
 one year ago
 one year ago
KABRIC Group Title
In an egg carton there are 12 eggs, of which 9 are hardboiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.
 one year ago
 one year ago

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kropot72 Group TitleBest ResponseYou've already chosen the best response.0
\[P(1\ raw)=\frac{3C1\times 9C5}{12C6}\]
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
i dont understant this formulae
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
The hpergeometric distribution applies in this case. The formula is \[p(x)=\frac{\left(\begin{matrix}a \\ x\end{matrix}\right)\left(\begin{matrix}b \\ nx\end{matrix}\right)}{\left(\begin{matrix}a+b \\ n\end{matrix}\right)}\] The values from the question are a = 3, b = 9, n = 6 and x = 1 The required probability is found from \[3\times \frac{\frac{9!}{5!4!}}{\frac{12!}{6!6!}}\]
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
hypergeometric*
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
The calculation for the required probability simplifies to the following after cancellations \[P(1\ raw)=\frac{3\times 6\times 6\times5}{12\times 11\times 10}=you\ can\ calculate\]
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
its 0.4090 so this is the required answer or do i have to do something more
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
The rounded decimal answer is 0.4091. The exact answer is the fraction \[\frac{9}{22}\]
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
ok thank you very much now i got it
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
You're welcome :)
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
but my answer got wrong
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
can you recheck it plz
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
The answer 9/22 is correct. Are you sure that you copied the question correctly?
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
yes infact i did
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
What other answer do you have?
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
i tried yours
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
i mean what could be wrong here
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
How did you submit the answer? Did you use a decimal value or a fractional value?
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.2
hello, the question asks "at least one raw egg' Let X = # of raw eggs. P( at least one raw egg ) = P( X > = 1 ) = P ( X = 1 or X = 2 or X = 3) However we can simplify computation by using the complement approach. P(A) = 1  P(A') P ( at least one raw egg) = 1 P ( X= 0 raw eggs) = 1  ( 3C0 * 9C6 ) / 12C6 the answer is 10/11
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Yes @perl is correct. I did not read the question carefully. My bad :(
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.2
no worries :)
 one year ago

KABRIC Group TitleBest ResponseYou've already chosen the best response.0
thanks perl
 one year ago
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