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 one year ago
In an egg carton there are 12 eggs, of which 9 are hardboiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.
 one year ago
In an egg carton there are 12 eggs, of which 9 are hardboiled and 3 are raw. Six of the eggs are chosen at random to take to a picnic (yes, the draws are made without replacement). Find the chance that at least one of the chosen eggs is raw.

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kropot72
 one year ago
Best ResponseYou've already chosen the best response.0\[P(1\ raw)=\frac{3C1\times 9C5}{12C6}\]

KABRIC
 one year ago
Best ResponseYou've already chosen the best response.0i dont understant this formulae

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0The hpergeometric distribution applies in this case. The formula is \[p(x)=\frac{\left(\begin{matrix}a \\ x\end{matrix}\right)\left(\begin{matrix}b \\ nx\end{matrix}\right)}{\left(\begin{matrix}a+b \\ n\end{matrix}\right)}\] The values from the question are a = 3, b = 9, n = 6 and x = 1 The required probability is found from \[3\times \frac{\frac{9!}{5!4!}}{\frac{12!}{6!6!}}\]

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0The calculation for the required probability simplifies to the following after cancellations \[P(1\ raw)=\frac{3\times 6\times 6\times5}{12\times 11\times 10}=you\ can\ calculate\]

KABRIC
 one year ago
Best ResponseYou've already chosen the best response.0its 0.4090 so this is the required answer or do i have to do something more

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0The rounded decimal answer is 0.4091. The exact answer is the fraction \[\frac{9}{22}\]

KABRIC
 one year ago
Best ResponseYou've already chosen the best response.0ok thank you very much now i got it

KABRIC
 one year ago
Best ResponseYou've already chosen the best response.0but my answer got wrong

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0The answer 9/22 is correct. Are you sure that you copied the question correctly?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0What other answer do you have?

KABRIC
 one year ago
Best ResponseYou've already chosen the best response.0i mean what could be wrong here

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0How did you submit the answer? Did you use a decimal value or a fractional value?

perl
 one year ago
Best ResponseYou've already chosen the best response.2hello, the question asks "at least one raw egg' Let X = # of raw eggs. P( at least one raw egg ) = P( X > = 1 ) = P ( X = 1 or X = 2 or X = 3) However we can simplify computation by using the complement approach. P(A) = 1  P(A') P ( at least one raw egg) = 1 P ( X= 0 raw eggs) = 1  ( 3C0 * 9C6 ) / 12C6 the answer is 10/11

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Yes @perl is correct. I did not read the question carefully. My bad :(
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