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Grazes

A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC.

  • one year ago
  • one year ago

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  1. Grazes
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    |dw:1366580105267:dw|

    • one year ago
  2. cybergurken
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    is that the actual sketch coz with that u cant do much

    • one year ago
  3. cybergurken
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    oh sorry...

    • one year ago
  4. Grazes
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    yep

    • one year ago
  5. Grazes
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    I believe you need to use the law of sines

    • one year ago
  6. cybergurken
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    do you know the sin rule or cos rule for trig???

    • one year ago
  7. Grazes
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    |dw:1366580369646:dw|

    • one year ago
  8. cybergurken
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    answer

    • one year ago
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  9. Grazes
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    no... CAB is 21 degrees

    • one year ago
  10. Grazes
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    and you're assuming that Angle CBA is a right angle

    • one year ago
  11. eSpeX
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    |dw:1366585349856:dw| \[\frac{35}{\sin(21)} = \frac{b}{\sin(101)} \rightarrow (35)\sin(101)=b \sin(21) \rightarrow \frac{(35)\sin(101)}{\sin(21)}\] which gives me 95.87.

    • one year ago
  12. Grazes
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    I have one problem with this. How do you know that CB is perpendicular to the horizontal-ish line A? If you don't know that, you can't assume the 90 degrees or the 11 degrees via parallel lines+transversal.

    • one year ago
  13. eSpeX
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    I know that the pole is perpendicular because it does not say otherwise, and thus I drew the line parallel to the horizontal and created the 90.

    • one year ago
  14. Grazes
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    |dw:1366600067027:dw|

    • one year ago
  15. eSpeX
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    Since that is not what I did, I certainly would not use similar logic.

    • one year ago
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