A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC.

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A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC.

Mathematics
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|dw:1366580105267:dw|
is that the actual sketch coz with that u cant do much
oh sorry...

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yep
I believe you need to use the law of sines
do you know the sin rule or cos rule for trig???
|dw:1366580369646:dw|
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no... CAB is 21 degrees
and you're assuming that Angle CBA is a right angle
|dw:1366585349856:dw| \[\frac{35}{\sin(21)} = \frac{b}{\sin(101)} \rightarrow (35)\sin(101)=b \sin(21) \rightarrow \frac{(35)\sin(101)}{\sin(21)}\] which gives me 95.87.
I have one problem with this. How do you know that CB is perpendicular to the horizontal-ish line A? If you don't know that, you can't assume the 90 degrees or the 11 degrees via parallel lines+transversal.
I know that the pole is perpendicular because it does not say otherwise, and thus I drew the line parallel to the horizontal and created the 90.
|dw:1366600067027:dw|
Since that is not what I did, I certainly would not use similar logic.

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