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Grazes

  • one year ago

A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC.

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  1. Grazes
    • one year ago
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    |dw:1366580105267:dw|

  2. cybergurken
    • one year ago
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    is that the actual sketch coz with that u cant do much

  3. cybergurken
    • one year ago
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    oh sorry...

  4. Grazes
    • one year ago
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    yep

  5. Grazes
    • one year ago
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    I believe you need to use the law of sines

  6. cybergurken
    • one year ago
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    do you know the sin rule or cos rule for trig???

  7. Grazes
    • one year ago
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    |dw:1366580369646:dw|

  8. cybergurken
    • one year ago
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    answer

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  9. Grazes
    • one year ago
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    no... CAB is 21 degrees

  10. Grazes
    • one year ago
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    and you're assuming that Angle CBA is a right angle

  11. eSpeX
    • one year ago
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    |dw:1366585349856:dw| \[\frac{35}{\sin(21)} = \frac{b}{\sin(101)} \rightarrow (35)\sin(101)=b \sin(21) \rightarrow \frac{(35)\sin(101)}{\sin(21)}\] which gives me 95.87.

  12. Grazes
    • one year ago
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    I have one problem with this. How do you know that CB is perpendicular to the horizontal-ish line A? If you don't know that, you can't assume the 90 degrees or the 11 degrees via parallel lines+transversal.

  13. eSpeX
    • one year ago
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    I know that the pole is perpendicular because it does not say otherwise, and thus I drew the line parallel to the horizontal and created the 90.

  14. Grazes
    • one year ago
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    |dw:1366600067027:dw|

  15. eSpeX
    • one year ago
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    Since that is not what I did, I certainly would not use similar logic.

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