## Grazes Group Title A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC. one year ago one year ago

1. Grazes

|dw:1366580105267:dw|

2. cybergurken

is that the actual sketch coz with that u cant do much

3. cybergurken

oh sorry...

4. Grazes

yep

5. Grazes

I believe you need to use the law of sines

6. cybergurken

do you know the sin rule or cos rule for trig???

7. Grazes

|dw:1366580369646:dw|

8. cybergurken

9. Grazes

no... CAB is 21 degrees

10. Grazes

and you're assuming that Angle CBA is a right angle

11. eSpeX

|dw:1366585349856:dw| $\frac{35}{\sin(21)} = \frac{b}{\sin(101)} \rightarrow (35)\sin(101)=b \sin(21) \rightarrow \frac{(35)\sin(101)}{\sin(21)}$ which gives me 95.87.

12. Grazes

I have one problem with this. How do you know that CB is perpendicular to the horizontal-ish line A? If you don't know that, you can't assume the 90 degrees or the 11 degrees via parallel lines+transversal.

13. eSpeX

I know that the pole is perpendicular because it does not say otherwise, and thus I drew the line parallel to the horizontal and created the 90.

14. Grazes

|dw:1366600067027:dw|

15. eSpeX

Since that is not what I did, I certainly would not use similar logic.