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Grazes
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A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC.
 one year ago
 one year ago
Grazes Group Title
A telephone pole 35 feet high is situated on a 11 degree slope from the horizontal. The measure of angle CAB is 21 degrees. Find the length of AC.
 one year ago
 one year ago

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Grazes Group TitleBest ResponseYou've already chosen the best response.0
dw:1366580105267:dw
 one year ago

cybergurken Group TitleBest ResponseYou've already chosen the best response.0
is that the actual sketch coz with that u cant do much
 one year ago

cybergurken Group TitleBest ResponseYou've already chosen the best response.0
oh sorry...
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
I believe you need to use the law of sines
 one year ago

cybergurken Group TitleBest ResponseYou've already chosen the best response.0
do you know the sin rule or cos rule for trig???
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
dw:1366580369646:dw
 one year ago

cybergurken Group TitleBest ResponseYou've already chosen the best response.0
answer
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
no... CAB is 21 degrees
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
and you're assuming that Angle CBA is a right angle
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
dw:1366585349856:dw \[\frac{35}{\sin(21)} = \frac{b}{\sin(101)} \rightarrow (35)\sin(101)=b \sin(21) \rightarrow \frac{(35)\sin(101)}{\sin(21)}\] which gives me 95.87.
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
I have one problem with this. How do you know that CB is perpendicular to the horizontalish line A? If you don't know that, you can't assume the 90 degrees or the 11 degrees via parallel lines+transversal.
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
I know that the pole is perpendicular because it does not say otherwise, and thus I drew the line parallel to the horizontal and created the 90.
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
dw:1366600067027:dw
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
Since that is not what I did, I certainly would not use similar logic.
 one year ago
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