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Amoy

  • 2 years ago

first principle to compute the derivative of xsin2x

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  1. croot
    • 2 years ago
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    u = x, v=sin(2x) u' * v + u * v'

  2. siddharthsawhney1996
    • 2 years ago
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    using product rule to compute derivative of function F(x) = u v it states f'(x) = (u)(derivative of v) + (v)(derivative of u) now in order to find derivative of x sin(2x) , use above rule that is, F'(x) = (x)(derivative of sin 2x) + (sin2x)(derivative of x) = (x)(2cos2x) + (sin2x) (1) = 2xcos2x + sin 2x

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