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Three congruent kites are placed together edgetoedge as shown. The bottom edge is 4x and the top edge is x. How much bigger than the perimeter of a one kite is the perimeter of the entire figure?
 one year ago
 one year ago
Three congruent kites are placed together edgetoedge as shown. The bottom edge is 4x and the top edge is x. How much bigger than the perimeter of a one kite is the perimeter of the entire figure?
 one year ago
 one year ago

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Annetta_MartinBest ResponseYou've already chosen the best response.0
@Luis_Rivera @timo86m @kropot72 @mth3v4
 one year ago

timo86mBest ResponseYou've already chosen the best response.1
perimeter of one kite is 2x+2*4x perimeter of whole figure is 2*4x+6x so you do a ratio (2*4x+6x)/(2x+2*4x) that is answer
 one year ago

genius12Best ResponseYou've already chosen the best response.1
Just count. The entire figure has 6 small kite sides and 2 long sides. That's\[2(4x)+6(x)=14x \] One kite has 2 small sides and 2 long sides which is: \[2x+8x=10x\] The difference then becomes \(1410x=4x\). So the large perimeter is longer by a difference of 4x than the small perimeter.
 one year ago

Annetta_MartinBest ResponseYou've already chosen the best response.0
Well I thought the answer was 6x? No?
 one year ago

Annetta_MartinBest ResponseYou've already chosen the best response.0
Ohhh, ok! I see what I did wrong now...
 one year ago

Annetta_MartinBest ResponseYou've already chosen the best response.0
You're right, thank you
 one year ago

timo86mBest ResponseYou've already chosen the best response.1
how do i know i am right?
 one year ago

genius12Best ResponseYou've already chosen the best response.1
idk what do you think?
 one year ago

genius12Best ResponseYou've already chosen the best response.1
7/5 is the ratio of the perimeter which means that the larger one is 1.4 times longer. But it doesn't give us the exact difference, i.e exactly by how much is it longer? And that's the question...
 one year ago

timo86mBest ResponseYou've already chosen the best response.1
how much longer lol ok.
 one year ago
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