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u0860867
 one year ago
Urgent Help needed due today pls help
In a hydrogen atom in its ground state, the electron is on average a distance of about 1×1010 m from the proton. What is the magnitude of the electric field due to the proton a distance of 0.9 1010 m away?
u0860867
 one year ago
Urgent Help needed due today pls help In a hydrogen atom in its ground state, the electron is on average a distance of about 1×1010 m from the proton. What is the magnitude of the electric field due to the proton a distance of 0.9 1010 m away?

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John_ES
 one year ago
Best ResponseYou've already chosen the best response.1Using, \[E=\frac{1}{4\pi\epsilon_0}\frac{Q_{proton}}{r^2}=\frac{1}{4\pi\epsilon_0}\frac{Q^2_{electron}}{r^2}=\frac{1}{4\pi 8.85\cdot10^{12}}\frac{1.609\cdot10^{19}}{(0.9\cdot10^{10})^2}=2.87\cdot10^{8}\ N/C \]
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