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How many 5 digit numbers N are there, such that the digit sum of N is 43, and N is divisible by 11?

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greatest five digit no. divisible by 11 having sum of digits as 43=99979 It can have four9's and one 7 or three 9's and two 8's. now possible digits with sum of digits are 88999,89899,89989,89998, 98899,99889,99988,99997,99979,99799,97999,79999 By hit & trial method only there are only two digits satisfying the given condition. They are99979,97999.

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