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dusty

  • 2 years ago

i need help please!!

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  1. HemerickLee
    • 2 years ago
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    With what

  2. dusty
    • 2 years ago
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    \[15q ^{4}r ^{2} \over 5qr ^{3}\] thats the equation

  3. HemerickLee
    • 2 years ago
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    3q^3 divided by r is the answer

  4. HemerickLee
    • 2 years ago
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    \[\frac{ -3q^3 }{ r^2 }\]

  5. HemerickLee
    • 2 years ago
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    You would factor out constants then use the power rule to figure it out

  6. dusty
    • 2 years ago
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    wouldnt it be just \[3q ^{3} \over r\]

  7. HemerickLee
    • 2 years ago
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    Yea thats what I had the first time but you had to simplify the last equation i put

  8. dusty
    • 2 years ago
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    ohh i see thank you very much!!!

  9. HemerickLee
    • 2 years ago
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    Your welcome!!

  10. dusty
    • 2 years ago
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    would u help me with one more?

  11. HemerickLee
    • 2 years ago
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    Surely

  12. dusty
    • 2 years ago
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    \[4x-12 \over 3x-9\]

  13. HemerickLee
    • 2 years ago
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    I got (4x/3) constant

  14. HemerickLee
    • 2 years ago
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    \[\frac{ 4x }{ 3 } constant\]

  15. HemerickLee
    • 2 years ago
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    Sound good??

  16. dusty
    • 2 years ago
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    sounds like the same thing i got lol thanks again for all ur help

  17. HemerickLee
    • 2 years ago
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    Your welcome

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