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With what

\[15q ^{4}r ^{2} \over 5qr ^{3}\] thats the equation

3q^3 divided by r is the answer

\[\frac{ -3q^3 }{ r^2 }\]

You would factor out constants then use the power rule to figure it out

wouldnt it be just \[3q ^{3} \over r\]

Yea thats what I had the first time but you had to simplify the last equation i put

ohh i see thank you very much!!!

Your welcome!!

would u help me with one more?

Surely

\[4x-12 \over 3x-9\]

I got (4x/3) constant

\[\frac{ 4x }{ 3 } constant\]

Sound good??

sounds like the same thing i got lol thanks again for all ur help

Your welcome