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MarcLeclair

  • 3 years ago

help with the following sequence

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  1. MarcLeclair
    • 3 years ago
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    \[a _{n}=e ^{2n/(n+2)} \]

  2. MarcLeclair
    • 3 years ago
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    I ln both side ( after putting the limit) and then used the hospital rule but my book solved it in a completely different way :/ and came to a different answer. So, I'm kinda lost on how to solve it

  3. MarcLeclair
    • 3 years ago
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    multiplied ln to both side*

  4. anonymous
    • 3 years ago
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    what does "solve" mean in this context?

  5. anonymous
    • 3 years ago
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    you have \[a_n=e^{\frac{2n}{n+2}}\] what are you trying to find?

  6. anonymous
    • 3 years ago
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    if you are looking for \[\lim_{n\to \infty}e^{\frac{2n}{n+2}}\] then since \[\lim_{n\to \infty}\frac{2n}{n+2}=2\] the answer is \(e^2\)

  7. MarcLeclair
    • 3 years ago
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    Sorry I was gone for a while but yea it was what I was looking for^^

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