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ln(n)^2/n * sorry

I believe he means (ln(n))^2

Not ln(n)^2

Yeah, ln^2(n) is >1 so you can't use that.

oh ok

Wait I thought (ln(n))^2 meant (ln(n)) * (ln(n))

Oh yeah I see it it could be greater than one, stupid question :/

Yeah, just noticed it, anyway thanks, basic math issues I guess ^^

Yeah lol ok so your left hand side should also be something better than 0 I think, that way you're actually squeezing.
ln(n)/n

Haha there's no "s" in L'Hopital.

Yikes. Anyway thanks hehe!!