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Frostbite
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Derive an expression for the contribution to the molar heat capacity at constant volume CV,m(T) of Cl atoms from these electronic states and evaluate it for T = 500 K.
 one year ago
 one year ago
Frostbite Group Title
Derive an expression for the contribution to the molar heat capacity at constant volume CV,m(T) of Cl atoms from these electronic states and evaluate it for T = 500 K.
 one year ago
 one year ago

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Theory: The electronic ground state of the Cl atom is fourfold degenerate, while the first electronically excited state is doubly degenerate and lies 881 cm–1 above the ground state.
 one year ago

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Work so far; \[C _{V,m}=\left( \frac{ \partial U _{m} }{ \partial T } \right)_{V}=\frac{ N _{a} \left( \langle \epsilon ^{2} \rangle  \langle \epsilon \rangle ^{2} \right) }{ kT ^{2} }\] \[\langle \epsilon \rangle=\sum_{i}^{n}p _{i} \epsilon _{i}\] \[\langle \epsilon \rangle=\frac{ 4 }{ q } \epsilon _{0}+\frac{ 2e ^{ \beta \epsilon} }{ q } \epsilon=\frac{ 2e ^{ \beta \epsilon} }{ q } \epsilon\] \[\langle \epsilon ^{2} \rangle=\sum_{i=0}^{1} p _{i} \epsilon ^{2} _{i}=\frac{ 4 }{ q } \epsilon _{0} ^{2}+\frac{ 2e ^{ \beta \epsilon} }{ q } \epsilon ^{2}=\frac{ 2e ^{ \beta \epsilon} }{ q } \epsilon ^{2}\\\] \[C _{V,m}=\frac{ N _{A}\left( \frac{ 2e ^{ \beta \epsilon} }{ q } \epsilon ^{2}\left( \frac{ 2e ^{ \beta \epsilon} }{ q } \epsilon \right)^{2} \right) }{ kT ^{2} }\] Now from here things are going down hill. I know I need to substitute the equation: \[E=\frac{ hc }{ \lambda } \Leftrightarrow \epsilon=hc \bar{v}\] But at the same time I like to make the expression more simple.
 one year ago

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@ataly @aaronq @blues @Preetha @amistre64
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
if your notation is correct, i dont see way that e^2 cant be factored out of the top
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
other than that, i got no idea what the setup is doing :)
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.0
I don't follow the exponential function to 2?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
its all a bit above my reading abilities :/ srry
 one year ago

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p = Boltzmann distribution q = the molecular partition function. beta = the thermodynamical beta (dah?) CV,m = molar heat capacity epsilon = the energy.
 one year ago

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The method for solving the problem I wrote up for my self was the following: 1. The heat capacity at constant volume is related to the variance of the molecular energy levels. 2. Calculate the mean value of the electronic energy of Cl atoms <epsilon> and the mean value of the square of the electronic energy of Cl atoms <epsilon^2>. 3. insert the results from step 2. into the expression from step 1.
 one year ago
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