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Ozzy733

  • 3 years ago

Simplify: 8x^2 - x^3/16 - 2x

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  1. Ozzy733
    • 3 years ago
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    \[\frac{ 8x ^{2}-x ^{3} }{ 16-2x}\]

  2. Annetta_Martin
    • 3 years ago
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    7x^2 / 2(8-x)

  3. Ozzy733
    • 3 years ago
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    Can you show me the work? @Annetta_Martin

  4. Mertsj
    • 3 years ago
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    Can you factor x^2 out of the numerator?

  5. Ozzy733
    • 3 years ago
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    Yeah , right? @Mertsj

  6. Mertsj
    • 3 years ago
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    Did you do it?

  7. Ozzy733
    • 3 years ago
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    I'm not good at factoring. @Mertsj

  8. Ozzy733
    • 3 years ago
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    How would you factor it out entirely? @Mertsj

  9. thomaster
    • 3 years ago
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    \[\frac{ 8x^2-x^2 }{ 16-2x }\] \[\ 8x^2-x^2 = 7x^2\] 16-2x = 2(8-x) because 2*8=16 and 2*x = 2x so: \[\frac{ 8x^2-x^2 }{ 16-2x }=\frac{ 7x^2 }{ x(8-x) }\]

  10. Ozzy733
    • 3 years ago
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    Thank you! But the equation is 8x2-x^3 not x squared. @thomaster

  11. radar
    • 3 years ago
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    F|dw:1366847941021:dw|

  12. radar
    • 3 years ago
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    I have written it correctly as x^3

  13. radar
    • 3 years ago
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    |dw:1366848329138:dw|

  14. thomaster
    • 3 years ago
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    Sorry misread :p

  15. thomaster
    • 3 years ago
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    superscript 2 & 3 are almost indistinguishable on my screen :(

  16. Ozzy733
    • 3 years ago
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    Sorry I was afk for a moment. Is that the final answer? And no problem! @thomaster @radar

  17. thomaster
    • 3 years ago
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    @radar worked it out right yea

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