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Simplify: 8x^2 - x^3/16 - 2x

Mathematics
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\[\frac{ 8x ^{2}-x ^{3} }{ 16-2x}\]
7x^2 / 2(8-x)
Can you show me the work? @Annetta_Martin

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Other answers:

Can you factor x^2 out of the numerator?
Yeah , right? @Mertsj
Did you do it?
I'm not good at factoring. @Mertsj
How would you factor it out entirely? @Mertsj
\[\frac{ 8x^2-x^2 }{ 16-2x }\] \[\ 8x^2-x^2 = 7x^2\] 16-2x = 2(8-x) because 2*8=16 and 2*x = 2x so: \[\frac{ 8x^2-x^2 }{ 16-2x }=\frac{ 7x^2 }{ x(8-x) }\]
Thank you! But the equation is 8x2-x^3 not x squared. @thomaster
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I have written it correctly as x^3
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Sorry misread :p
superscript 2 & 3 are almost indistinguishable on my screen :(
Sorry I was afk for a moment. Is that the final answer? And no problem! @thomaster @radar
@radar worked it out right yea

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