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anonymous
 3 years ago
To solve 3x+2<4, split the equation into
3x + 2 < 4 and 3x + 2 < 4
3x + 2 < 4 and 3x + 2 >  4
3x  2 < 4 and 3x  2 >  4
3x + 2 <  4 and 3x + 2 > 4
anonymous
 3 years ago
To solve 3x+2<4, split the equation into 3x + 2 < 4 and 3x + 2 < 4 3x + 2 < 4 and 3x + 2 >  4 3x  2 < 4 and 3x  2 >  4 3x + 2 <  4 and 3x + 2 > 4

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is it 3x + 2 < 4 and 3x + 2 < 4 ? (The first choice)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0There up there with the question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's not the first choice. see how the inequality signs point the same way? the inequality signs should point in opposite directions.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So then it'd be the second choice?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0an easy way to do this problem if you have a graphing calculator is to graph y=abs(3x2)4 (solve your equation for zero, then put y in instead of the zero)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Could you help me with one more question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but I have a question for you afterward

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which domain number causes this relation not to be a function? R = { (1, 1), (2, 0), (2, 1), (3, 1), (4, 4) } 1 zero 1 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how much do you already know about what is and is not a function?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a relation is not a function if it has two yvalues for one xvalue.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0domain is xvalues which xvalue appears twice and has two different yvalues?
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