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Annetta_Martin

To solve |3x+2|<4, split the equation into 3x + 2 < 4 and 3x + 2 < -4 3x + 2 < 4 and 3x + 2 > - 4 3x - 2 < 4 and 3x - 2 > - 4 3x + 2 < - 4 and 3x + 2 > 4

  • 11 months ago
  • 11 months ago

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  1. Annetta_Martin
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    Is it 3x + 2 < 4 and 3x + 2 < -4 ? (The first choice)

    • 11 months ago
  2. snowman97
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    need help

    • 11 months ago
  3. Annetta_Martin
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    Yes

    • 11 months ago
  4. snowman97
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    have answer choices

    • 11 months ago
  5. Annetta_Martin
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    There up there with the question

    • 11 months ago
  6. Annetta_Martin
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    They're

    • 11 months ago
  7. Peter14
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    it's not the first choice. see how the inequality signs point the same way? the inequality signs should point in opposite directions.

    • 11 months ago
  8. Peter14
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    do you see why?

    • 11 months ago
  9. Annetta_Martin
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    Yes, I do

    • 11 months ago
  10. Annetta_Martin
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    So then it'd be the second choice?

    • 11 months ago
  11. Peter14
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    yes

    • 11 months ago
  12. Peter14
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    an easy way to do this problem if you have a graphing calculator is to graph y=abs(3x-2)-4 (solve your equation for zero, then put y in instead of the zero)

    • 11 months ago
  13. Annetta_Martin
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    Ok, I'll try that!

    • 11 months ago
  14. Annetta_Martin
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    Could you help me with one more question?

    • 11 months ago
  15. Peter14
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    sure

    • 11 months ago
  16. Peter14
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    but I have a question for you afterward

    • 11 months ago
  17. Annetta_Martin
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    Ok!

    • 11 months ago
  18. Annetta_Martin
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    Which domain number causes this relation not to be a function? R = { (-1, -1), (2, 0), (2, 1), (3, 1), (4, 4) } -1 zero 1 2

    • 11 months ago
  19. Peter14
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    how much do you already know about what is and is not a function?

    • 11 months ago
  20. Peter14
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    a relation is not a function if it has two y-values for one x-value.

    • 11 months ago
  21. Annetta_Martin
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    I thought it was 1?

    • 11 months ago
  22. Peter14
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    domain is x-values which x-value appears twice and has two different y-values?

    • 11 months ago
  23. Annetta_Martin
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    2

    • 11 months ago
  24. Peter14
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    yes

    • 11 months ago
  25. Annetta_Martin
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    Ok, your question?

    • 11 months ago
  26. Peter14
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    I pm'd it to you

    • 11 months ago
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