Annetta_Martin 2 years ago To solve |3x+2|<4, split the equation into 3x + 2 < 4 and 3x + 2 < -4 3x + 2 < 4 and 3x + 2 > - 4 3x - 2 < 4 and 3x - 2 > - 4 3x + 2 < - 4 and 3x + 2 > 4

1. Annetta_Martin

Is it 3x + 2 < 4 and 3x + 2 < -4 ? (The first choice)

2. snowman97

need help

3. Annetta_Martin

Yes

4. snowman97

5. Annetta_Martin

There up there with the question

6. Annetta_Martin

They're

7. Peter14

it's not the first choice. see how the inequality signs point the same way? the inequality signs should point in opposite directions.

8. Peter14

do you see why?

9. Annetta_Martin

Yes, I do

10. Annetta_Martin

So then it'd be the second choice?

11. Peter14

yes

12. Peter14

an easy way to do this problem if you have a graphing calculator is to graph y=abs(3x-2)-4 (solve your equation for zero, then put y in instead of the zero)

13. Annetta_Martin

Ok, I'll try that!

14. Annetta_Martin

Could you help me with one more question?

15. Peter14

sure

16. Peter14

but I have a question for you afterward

17. Annetta_Martin

Ok!

18. Annetta_Martin

Which domain number causes this relation not to be a function? R = { (-1, -1), (2, 0), (2, 1), (3, 1), (4, 4) } -1 zero 1 2

19. Peter14

how much do you already know about what is and is not a function?

20. Peter14

a relation is not a function if it has two y-values for one x-value.

21. Annetta_Martin

I thought it was 1?

22. Peter14

domain is x-values which x-value appears twice and has two different y-values?

23. Annetta_Martin

2

24. Peter14

yes

25. Annetta_Martin