Annetta_Martin
To solve |3x+2|<4, split the equation into
3x + 2 < 4 and 3x + 2 < -4
3x + 2 < 4 and 3x + 2 > - 4
3x - 2 < 4 and 3x - 2 > - 4
3x + 2 < - 4 and 3x + 2 > 4
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Annetta_Martin
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Is it 3x + 2 < 4 and 3x + 2 < -4 ?
(The first choice)
snowman97
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need help
Annetta_Martin
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Yes
snowman97
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have answer choices
Annetta_Martin
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There up there with the question
Annetta_Martin
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They're
Peter14
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it's not the first choice. see how the inequality signs point the same way? the inequality signs should point in opposite directions.
Peter14
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do you see why?
Annetta_Martin
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Yes, I do
Annetta_Martin
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So then it'd be the second choice?
Peter14
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yes
Peter14
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an easy way to do this problem if you have a graphing calculator is to graph y=abs(3x-2)-4 (solve your equation for zero, then put y in instead of the zero)
Annetta_Martin
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Ok, I'll try that!
Annetta_Martin
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Could you help me with one more question?
Peter14
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sure
Peter14
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but I have a question for you afterward
Annetta_Martin
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Ok!
Annetta_Martin
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Which domain number causes this relation not to be a function?
R = { (-1, -1), (2, 0), (2, 1), (3, 1), (4, 4) }
-1
zero
1
2
Peter14
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how much do you already know about what is and is not a function?
Peter14
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a relation is not a function if it has two y-values for one x-value.
Annetta_Martin
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I thought it was 1?
Peter14
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domain is x-values
which x-value appears twice and has two different y-values?
Annetta_Martin
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2
Peter14
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yes
Annetta_Martin
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Ok, your question?
Peter14
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I pm'd it to you