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Luigi0210Best ResponseYou've already chosen the best response.1
Do you know what the graph looks like?
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Well it might be a good idea to sketch a graph
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
would it possible to solve the problem without a graph?
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Well yes but it be a bit harder since we don't know which graph is higher
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
oh i see... how do you draw a graph
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
wait, are you finding total area or net area?
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
it says find the area between the curves?
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
If I'm not mistaken then the graphs should look like this when graphed dw:1366855841011:dw
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Uhm no, the ends of the graph go off into infinity after they have intersected
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Now, do you notice anything about the two graphs?
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
they get smaller and smaller? they intersects
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Well yes but also they are reflections of one another
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
So that means that whatever area on graph has the other has the opposite area. Such as x and x.
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
So that means the area would be zero
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
i thought i need more calculations
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Well you could if you want but the answer would still be zero. These two graphs are going to cancel each others area out
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
i entered zero into the answer but it tells me that it was wrong
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Well let's solve it right now, do you know how to set it up as an integral?
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Sorry I was trying to evaluate the problem
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
but anyways we would set up the problem like this: \[\int\limits_{0}^{9} (x^314x^2+45x)(x^3+14x^245x) dx\]
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
I'm betting that they want you to set up two different integrals...based on the two enclosed regions.
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
so between...= minus. i got it
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
Setting up two equations would take a bit longer
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=area+between+x^314x^2%2B45x+and+x^3%2B14x^245x
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
The answer I got was 253/2..
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
the answer was wrong but thanks for ur help!
 11 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
I'm sorry I couldn't help you solve it..
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
No thanks for your time!
 11 months ago
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