anonymous
  • anonymous
curve problems?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
Luigi0210
  • Luigi0210
Do you know what the graph looks like?
anonymous
  • anonymous
No, I have no idea!

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Luigi0210
  • Luigi0210
Well it might be a good idea to sketch a graph
anonymous
  • anonymous
would it possible to solve the problem without a graph?
anonymous
  • anonymous
would it be
Luigi0210
  • Luigi0210
Well yes but it be a bit harder since we don't know which graph is higher
anonymous
  • anonymous
oh i see... how do you draw a graph
Luigi0210
  • Luigi0210
wait, are you finding total area or net area?
anonymous
  • anonymous
it says find the area between the curves?
Luigi0210
  • Luigi0210
If I'm not mistaken then the graphs should look like this when graphed |dw:1366855841011:dw|
anonymous
  • anonymous
sin and cos graph?
Luigi0210
  • Luigi0210
Uhm no, the ends of the graph go off into infinity after they have intersected
anonymous
  • anonymous
Oh.
Luigi0210
  • Luigi0210
Now, do you notice anything about the two graphs?
anonymous
  • anonymous
-they get smaller and smaller? -they intersects
Luigi0210
  • Luigi0210
Well yes but also they are reflections of one another
anonymous
  • anonymous
Yes,
Luigi0210
  • Luigi0210
So that means that whatever area on graph has the other has the opposite area. Such as -x and x.
anonymous
  • anonymous
Yes,
Luigi0210
  • Luigi0210
So that means the area would be zero
anonymous
  • anonymous
the answer is zero?
anonymous
  • anonymous
i thought i need more calculations
Luigi0210
  • Luigi0210
Well you could if you want but the answer would still be zero. These two graphs are going to cancel each others area out
anonymous
  • anonymous
i entered zero into the answer but it tells me that it was wrong
Luigi0210
  • Luigi0210
Well let's solve it right now, do you know how to set it up as an integral?
anonymous
  • anonymous
No, I have no idea!!
anonymous
  • anonymous
Luigi0210
  • Luigi0210
Sorry I was trying to evaluate the problem
Luigi0210
  • Luigi0210
but anyways we would set up the problem like this: \[\int\limits_{0}^{9} (x^3-14x^2+45x)-(-x^3+14x^2-45x) dx\]
Zarkon
  • Zarkon
I'm betting that they want you to set up two different integrals...based on the two enclosed regions.
anonymous
  • anonymous
so between...= minus. i got it
Luigi0210
  • Luigi0210
Setting up two equations would take a bit longer
Zarkon
  • Zarkon
http://www.wolframalpha.com/input/?i=area+between+x^3-14x^2%2B45x+and+-x^3%2B14x^2-45x
anonymous
  • anonymous
whats next step?
Luigi0210
  • Luigi0210
The answer I got was 253/2..
Luigi0210
  • Luigi0210
*243/2
anonymous
  • anonymous
the answer was wrong but thanks for ur help!
Luigi0210
  • Luigi0210
I'm sorry I couldn't help you solve it..
anonymous
  • anonymous
No thanks for your time!

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