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Do you know what the graph looks like?

No, I have no idea!

Well it might be a good idea to sketch a graph

would it possible to solve the problem without a graph?

would it be

Well yes but it be a bit harder since we don't know which graph is higher

oh i see...
how do you draw a graph

wait, are you finding total area or net area?

it says find the area between the curves?

If I'm not mistaken then the graphs should look like this when graphed
|dw:1366855841011:dw|

sin and cos graph?

Uhm no, the ends of the graph go off into infinity after they have intersected

Oh.

Now, do you notice anything about the two graphs?

-they get smaller and smaller?
-they intersects

Well yes but also they are reflections of one another

Yes,

So that means that whatever area on graph has the other has the opposite area.
Such as -x and x.

Yes,

So that means the area would be zero

the answer is zero?

i thought i need more calculations

i entered zero into the answer but it tells me that it was wrong

Well let's solve it right now, do you know how to set it up as an integral?

No, I have no idea!!

Sorry I was trying to evaluate the problem

so between...= minus.
i got it

Setting up two equations would take a bit longer

http://www.wolframalpha.com/input/?i=area+between+x^3-14x^2%2B45x+and+-x^3%2B14x^2-45x

whats next step?

The answer I got was 253/2..

*243/2

the answer was wrong but thanks for ur help!

I'm sorry I couldn't help you solve it..

No thanks for your time!