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Dodo1
 one year ago
curve problems?
Dodo1
 one year ago
curve problems?

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Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Do you know what the graph looks like?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Well it might be a good idea to sketch a graph

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0would it possible to solve the problem without a graph?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Well yes but it be a bit harder since we don't know which graph is higher

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0oh i see... how do you draw a graph

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1wait, are you finding total area or net area?

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0it says find the area between the curves?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1If I'm not mistaken then the graphs should look like this when graphed dw:1366855841011:dw

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Uhm no, the ends of the graph go off into infinity after they have intersected

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Now, do you notice anything about the two graphs?

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0they get smaller and smaller? they intersects

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Well yes but also they are reflections of one another

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1So that means that whatever area on graph has the other has the opposite area. Such as x and x.

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1So that means the area would be zero

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0i thought i need more calculations

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Well you could if you want but the answer would still be zero. These two graphs are going to cancel each others area out

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0i entered zero into the answer but it tells me that it was wrong

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Well let's solve it right now, do you know how to set it up as an integral?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Sorry I was trying to evaluate the problem

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1but anyways we would set up the problem like this: \[\int\limits_{0}^{9} (x^314x^2+45x)(x^3+14x^245x) dx\]

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0I'm betting that they want you to set up two different integrals...based on the two enclosed regions.

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0so between...= minus. i got it

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Setting up two equations would take a bit longer

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=area+between+x^314x^2%2B45x+and+x^3%2B14x^245x

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1The answer I got was 253/2..

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0the answer was wrong but thanks for ur help!

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1I'm sorry I couldn't help you solve it..

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0No thanks for your time!
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