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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
\[\log_7M=\frac{\log_910\log_95}{\log_97}\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
first use this log law in the numerator of the right hand side \[\boxed{\log_b x\log_by=\log_b\frac xy}\]
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
yeah i did that so i got log 2
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
now use the change of base formula \[\large\boxed{\log_b x=\frac{\log_c x}{ \log_c b}}\]
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
0.31 for the numerator
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
leave it in log form
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
So you have \[\log_7M=\frac{\log_92}{\log_97}\] comparing with the change of base formula \[\boxed{\log_b x=\dfrac{\log_c x}{ \log_c b}}\] we see that \(M= ~ . . .\)
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
so will u get Log7M= 0.35 @UnkleRhaukus
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
so will M =2 ?????
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
dont convert to decimal
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
yeah that's it M=2
 one year ago
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