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anonymous
 3 years ago
help needed
anonymous
 3 years ago
help needed

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UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3\[\log_7M=\frac{\log_910\log_95}{\log_97}\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3first use this log law in the numerator of the right hand side \[\boxed{\log_b x\log_by=\log_b\frac xy}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i did that so i got log 2

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3now use the change of base formula \[\large\boxed{\log_b x=\frac{\log_c x}{ \log_c b}}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.00.31 for the numerator

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3leave it in log form

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3So you have \[\log_7M=\frac{\log_92}{\log_97}\] comparing with the change of base formula \[\boxed{\log_b x=\dfrac{\log_c x}{ \log_c b}}\] we see that \(M= ~ . . .\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so will u get Log7M= 0.35 @UnkleRhaukus

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3dont convert to decimal

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.3yeah that's it M=2
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