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u0860867
 one year ago
help needed
u0860867
 one year ago
help needed

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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3\[\log_7M=\frac{\log_910\log_95}{\log_97}\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3first use this log law in the numerator of the right hand side \[\boxed{\log_b x\log_by=\log_b\frac xy}\]

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0yeah i did that so i got log 2

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3now use the change of base formula \[\large\boxed{\log_b x=\frac{\log_c x}{ \log_c b}}\]

u0860867
 one year ago
Best ResponseYou've already chosen the best response.00.31 for the numerator

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3leave it in log form

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3So you have \[\log_7M=\frac{\log_92}{\log_97}\] comparing with the change of base formula \[\boxed{\log_b x=\dfrac{\log_c x}{ \log_c b}}\] we see that \(M= ~ . . .\)

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0so will u get Log7M= 0.35 @UnkleRhaukus

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3dont convert to decimal

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3yeah that's it M=2
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