## u0860867 2 years ago help needed

1. u0860867

2. UnkleRhaukus

$\log_7M=\frac{\log_910-\log_95}{\log_97}$

3. UnkleRhaukus

first use this log law in the numerator of the right hand side $\boxed{\log_b x-\log_by=\log_b\frac xy}$

4. u0860867

yeah i did that so i got log 2

5. UnkleRhaukus

now use the change of base formula $\large\boxed{\log_b x=\frac{\log_c x}{ \log_c b}}$

6. u0860867

0.31 for the numerator

7. UnkleRhaukus

leave it in log form

8. u0860867

ok

9. UnkleRhaukus

So you have $\log_7M=\frac{\log_92}{\log_97}$ comparing with the change of base formula $\boxed{\log_b x=\dfrac{\log_c x}{ \log_c b}}$ we see that $$M= ~ . . .$$

10. u0860867

so will u get Log7M= 0.35 @UnkleRhaukus

11. u0860867

so will M =2 ?????

12. UnkleRhaukus

dont convert to decimal

13. UnkleRhaukus

yeah that's it M=2