perl
  • perl
Geometry Mathquestion for Loveya69
Mathematics
katieb
  • katieb
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perl
  • perl
give me a second, lol
anonymous
  • anonymous
Okay cx
perl
  • perl
how do you upload an image?

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anonymous
  • anonymous
Attach File *I think*
perl
  • perl
thanks
perl
  • perl
sorry for the wait
perl
  • perl
number 31
perl
  • perl
|dw:1366882143016:dw|
perl
  • perl
nope, doesnt have to be congruent
perl
  • perl
we want it to be a parallelogram. only opposite sides of a parallogram have to be congruent, but thats not really going to be used here
perl
  • perl
lets start with D)
anonymous
  • anonymous
Well, if DAB = 40º, and DCB = 40º then ADC = ABC which makes it a parallelogram right?
perl
  • perl
i meant, not all 4 sides have to be congruent
perl
  • perl
why does
anonymous
  • anonymous
because if those two angles are equal then wouldnt the other two that are across from each other be equal?
anonymous
  • anonymous
not necessarily
perl
  • perl
let me redraw that
anonymous
  • anonymous
Really Peter?:/ Try drawing that with those two angles equaling exactly 40º and see if you can get the other two angles not to equal each other.
anonymous
  • anonymous
a kite
perl
  • perl
|dw:1366882582720:dw|
perl
  • perl
peter, oh yes a kite does satisfy these conditions , but is not a parallelogram
anonymous
  • anonymous
are rhombuses (rhombii?) kites?
.Sam.
  • .Sam.
Can I post the solution? ;)
perl
  • perl
sam, i would prefer you not, but...
perl
  • perl
give loveyou a chance :)
anonymous
  • anonymous
DC and AB are congruent angles tho right? so if ABC = DCB then ADC = CBA which means DC = AB and DA = BC
anonymous
  • anonymous
Lets not give me a chance lol im making myself feel stupid
anonymous
  • anonymous
how about this: look at all the choices from D to A and try to draw a counterexample for each one.
perl
  • perl
peter, good idea :)
anonymous
  • anonymous
lol,letsnot, i didnt get sleep im too tired for this :P
anonymous
  • anonymous
no, let's do it!
anonymous
  • anonymous
Feel free
anonymous
  • anonymous
no! i'm volunteering you to do it! it's your problem... I already know the answer.
anonymous
  • anonymous
It's not my problem lol
anonymous
  • anonymous
"Geometry Mathquestion for Loveya69"
anonymous
  • anonymous
It's not mine .-. If it was mine I'd be able to do it. I have 100 in my geometry class. but im not even doing this stuff in mine
perl
  • perl
Definition: A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent. (1) The diagonals of a kite meet at a right angle. (2) Kites have exactly one pair of opposite angles that are congruent.
anonymous
  • anonymous
thanks perl, I didn't remember that
perl
  • perl
and here http://www.wyzant.com/help/math/geometry/quadrilaterals/trapezoids_and_kites
perl
  • perl
peter I got B)
mayankdevnani
  • mayankdevnani
@perl in my opinion the answer would be option b and option d!!!!!
perl
  • perl
option d is wrong, because you can produce a kite , b is right
perl
  • perl
a kite satisfies option d and is not a parallelogram
mayankdevnani
  • mayankdevnani
but in quest. it is given that it is a parallegoram and in parallelogram , opposite sides are equal!!!!!
mayankdevnani
  • mayankdevnani
anonymous
  • anonymous
no, in question it is given what conditions must be true for it to be a parallellogram
mayankdevnani
  • mayankdevnani
but what about angles of kite?????
mayankdevnani
  • mayankdevnani
mayankdevnani
  • mayankdevnani
|dw:1366929990059:dw|
anonymous
  • anonymous
only two angles are given to be 40 degrees. The other two angles can be anything so that the sum of the 4 angles is 360 degrees
mayankdevnani
  • mayankdevnani
|dw:1366930082573:dw|
mayankdevnani
  • mayankdevnani
in triangle abc, it is an isosceles triangle. it means that angle 1=angle2!!!! right @Peter14
anonymous
  • anonymous
sure. set the sum of angles 1 and 4 to 40 degrees and the sum of angles 2 and 5 will also be 40 degrees.
anonymous
  • anonymous
sure, it could be a rhombus, and therefore a parallelogram, but you can't assume that.
mayankdevnani
  • mayankdevnani
@Peter14 for this time, please forgot the question, concerntrate on my question!!!!
anonymous
  • anonymous
angles 3 and (not given) could vary. the sum just has to be 280.
anonymous
  • anonymous
sure, let's go with your question. yes, angle 1 = angle 2 and angle 4= angle 5.
mayankdevnani
  • mayankdevnani
but in perl question!!!!!
anonymous
  • anonymous
|dw:1366885812169:dw| so what about its angles?
mayankdevnani
  • mayankdevnani
angle 1=angle2 and angle4=angle 5
anonymous
  • anonymous
yes... and?
mayankdevnani
  • mayankdevnani
and what?
anonymous
  • anonymous
what exactly are you trying to prove here?
mayankdevnani
  • mayankdevnani
that adjacent angles are equal
perl
  • perl
|dw:1366886101425:dw|
perl
  • perl
its difficult to force this into a kite shape
perl
  • perl
@Peter14 this definition is wrong: Definition: A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent. (1) The diagonals of a kite meet at a right angle. (2) Kites have exactly one pair of opposite angles that are congruent.
anonymous
  • anonymous
(shrug) It doesn't really matter to me. I've already taken geometry.
perl
  • perl
it doesnt have to be exactly one pair of congruent sides, both pairs could be congruent. here is an animation http://www.mathsisfun.com/definitions/kite.html
perl
  • perl
for instance a square is a kite
perl
  • perl
it should say, a kite has at least one pair of congruent angles
perl
  • perl
@Peter14 here is a discussion, its a controversy http://answers.yahoo.com/question/index?qid=20100506151637AAPkWXY
perl
  • perl
about kites!

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