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give me a second, lol
how do you upload an image?
Attach File *I think*
nope, doesnt have to be congruent
we want it to be a parallelogram. only opposite sides of a parallogram have to be congruent, but thats not really going to be used here
lets start with D)
Well, if DAB = 40º, and DCB = 40º then ADC = ABC which makes it a parallelogram right?
i meant, not all 4 sides have to be congruent
because if those two angles are equal then wouldnt the other two that are across from each other be equal?
let me redraw that
Really Peter?:/ Try drawing that with those two angles equaling exactly 40º and see if you can get the other two angles not to equal each other.
peter, oh yes a kite does satisfy these conditions , but is not a parallelogram
are rhombuses (rhombii?) kites?
Can I post the solution? ;)
sam, i would prefer you not, but...
give loveyou a chance :)
DC and AB are congruent angles tho right? so if ABC = DCB then ADC = CBA which means DC = AB and DA = BC
Lets not give me a chance lol im making myself feel stupid
how about this: look at all the choices from D to A and try to draw a counterexample for each one.
peter, good idea :)
lol,letsnot, i didnt get sleep im too tired for this :P
no, let's do it!
no! i'm volunteering you to do it! it's your problem... I already know the answer.
It's not my problem lol
"Geometry Mathquestion for Loveya69"
It's not mine .-. If it was mine I'd be able to do it. I have 100 in my geometry class. but im not even doing this stuff in mine
Definition: A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent. (1) The diagonals of a kite meet at a right angle. (2) Kites have exactly one pair of opposite angles that are congruent.
thanks perl, I didn't remember that
and here http://www.wyzant.com/help/math/geometry/quadrilaterals/trapezoids_and_kites
peter I got B)
@perl in my opinion the answer would be option b and option d!!!!!
option d is wrong, because you can produce a kite , b is right
a kite satisfies option d and is not a parallelogram
but in quest. it is given that it is a parallegoram and in parallelogram , opposite sides are equal!!!!!
@perl and @Peter14
no, in question it is given what conditions must be true for it to be a parallellogram
but what about angles of kite?????
@perl and @Peter14
only two angles are given to be 40 degrees. The other two angles can be anything so that the sum of the 4 angles is 360 degrees
in triangle abc, it is an isosceles triangle. it means that angle 1=angle2!!!! right @Peter14
sure. set the sum of angles 1 and 4 to 40 degrees and the sum of angles 2 and 5 will also be 40 degrees.
sure, it could be a rhombus, and therefore a parallelogram, but you can't assume that.
@Peter14 for this time, please forgot the question, concerntrate on my question!!!!
angles 3 and (not given) could vary. the sum just has to be 280.
sure, let's go with your question. yes, angle 1 = angle 2 and angle 4= angle 5.
but in perl question!!!!!
|dw:1366885812169:dw| so what about its angles?
angle 1=angle2 and angle4=angle 5
what exactly are you trying to prove here?
that adjacent angles are equal
its difficult to force this into a kite shape
@Peter14 this definition is wrong: Definition: A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent. (1) The diagonals of a kite meet at a right angle. (2) Kites have exactly one pair of opposite angles that are congruent.
(shrug) It doesn't really matter to me. I've already taken geometry.
it doesnt have to be exactly one pair of congruent sides, both pairs could be congruent. here is an animation http://www.mathsisfun.com/definitions/kite.html
for instance a square is a kite
it should say, a kite has at least one pair of congruent angles
@Peter14 here is a discussion, its a controversy http://answers.yahoo.com/question/index?qid=20100506151637AAPkWXY