Geometry Mathquestion for Loveya69

- perl

Geometry Mathquestion for Loveya69

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- katieb

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- perl

give me a second, lol

- anonymous

Okay cx

- perl

how do you upload an image?

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## More answers

- anonymous

Attach File *I think*

- perl

thanks

- perl

sorry for the wait

##### 1 Attachment

- perl

number 31

- perl

|dw:1366882143016:dw|

- perl

nope, doesnt have to be congruent

- perl

we want it to be a parallelogram. only opposite sides of a parallogram have to be congruent, but thats not really going to be used here

- perl

lets start with D)

- anonymous

Well, if DAB = 40º, and DCB = 40º then ADC = ABC which makes it a parallelogram right?

- perl

i meant, not all 4 sides have to be congruent

- perl

why does

- anonymous

because if those two angles are equal then wouldnt the other two that are across from each other be equal?

- anonymous

not necessarily

- perl

let me redraw that

- anonymous

Really Peter?:/ Try drawing that with those two angles equaling exactly 40º and see if you can get the other two angles not to equal each other.

- anonymous

a kite

- perl

|dw:1366882582720:dw|

- perl

peter, oh yes a kite does satisfy these conditions , but is not a parallelogram

- anonymous

are rhombuses (rhombii?) kites?

- .Sam.

Can I post the solution? ;)

- perl

sam, i would prefer you not, but...

- perl

give loveyou a chance :)

- anonymous

DC and AB are congruent angles tho right? so if ABC = DCB then ADC = CBA which means DC = AB and DA = BC

- anonymous

Lets not give me a chance lol im making myself feel stupid

- anonymous

how about this: look at all the choices from D to A and try to draw a counterexample for each one.

- perl

peter, good idea :)

- anonymous

lol,letsnot, i didnt get sleep im too tired for this :P

- anonymous

no, let's do it!

- anonymous

Feel free

- anonymous

no! i'm volunteering you to do it! it's your problem...
I already know the answer.

- anonymous

It's not my problem lol

- anonymous

"Geometry Mathquestion for Loveya69"

- anonymous

It's not mine .-. If it was mine I'd be able to do it. I have 100 in my geometry class. but im not even doing this stuff in mine

- perl

Definition: A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent.
(1) The diagonals of a kite meet at a right angle.
(2) Kites have exactly one pair of opposite angles that are congruent.

- anonymous

thanks perl, I didn't remember that

- perl

and here http://www.wyzant.com/help/math/geometry/quadrilaterals/trapezoids_and_kites

- perl

peter I got B)

- mayankdevnani

@perl in my opinion the answer would be option b and option d!!!!!

- perl

option d is wrong, because you can produce a kite , b is right

- perl

a kite satisfies option d and is not a parallelogram

- mayankdevnani

but in quest. it is given that it is a parallegoram and in parallelogram , opposite sides are equal!!!!!

- mayankdevnani

@perl and @Peter14

- anonymous

no, in question it is given what conditions must be true for it to be a parallellogram

- mayankdevnani

but what about angles of kite?????

- mayankdevnani

@perl and @Peter14

- mayankdevnani

|dw:1366929990059:dw|

- anonymous

only two angles are given to be 40 degrees. The other two angles can be anything so that the sum of the 4 angles is 360 degrees

- mayankdevnani

|dw:1366930082573:dw|

- mayankdevnani

in triangle abc, it is an isosceles triangle. it means that angle 1=angle2!!!! right @Peter14

- anonymous

sure. set the sum of angles 1 and 4 to 40 degrees and the sum of angles 2 and 5 will also be 40 degrees.

- anonymous

sure, it could be a rhombus, and therefore a parallelogram, but you can't assume that.

- mayankdevnani

@Peter14 for this time, please forgot the question, concerntrate on my question!!!!

- anonymous

angles 3 and (not given) could vary. the sum just has to be 280.

- anonymous

sure, let's go with your question. yes, angle 1 = angle 2 and angle 4= angle 5.

- mayankdevnani

but in perl question!!!!!

- anonymous

|dw:1366885812169:dw|
so what about its angles?

- mayankdevnani

angle 1=angle2 and angle4=angle 5

- anonymous

yes... and?

- mayankdevnani

and what?

- anonymous

what exactly are you trying to prove here?

- mayankdevnani

that adjacent angles are equal

- perl

|dw:1366886101425:dw|

- perl

its difficult to force this into a kite shape

- perl

@Peter14
this definition is wrong:
Definition: A kite is a quadrilateral with two distinct pairs of adjacent sides that are congruent.
(1) The diagonals of a kite meet at a right angle.
(2) Kites have exactly one pair of opposite angles that are congruent.

- anonymous

(shrug) It doesn't really matter to me. I've already taken geometry.

- perl

it doesnt have to be exactly one pair of congruent sides, both pairs could be congruent. here is an animation
http://www.mathsisfun.com/definitions/kite.html

- perl

for instance a square is a kite

- perl

it should say, a kite has at least one pair of congruent angles

- perl

@Peter14
here is a discussion, its a controversy
http://answers.yahoo.com/question/index?qid=20100506151637AAPkWXY

- perl

about kites!

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