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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1its just an application of chaining a chain ....

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{d}{dx} f(g(h(k(...(x)))))=f'()~g'()~h'()~k'()~.......x'\]

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0wait what i dont get it..

perl
 one year ago
Best ResponseYou've already chosen the best response.0amistre is showing off :D

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1all this amounts to is chain rule practice .... if you know the chain rule, then its just a matter of keeping a clean record

perl
 one year ago
Best ResponseYou've already chosen the best response.0amistre, i dont thats right though

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0ok so im new to this ..can u teach me pls?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1there are some cases where the mechanism of a derivative works, but the equation itself is bad .... i dont think this is the case tho

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0what do u want me to do?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1y= tan(cos(e^sqrt(x^2+1))) let: f = tan(g) g= cos(h) h = e^j j = sqrt(k) k = x^2+1

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1then find the derivative of each one, and multiply them all together ...

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0but hw can i take derivative of tan(g)(h)(j)(k) ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1take the derivative of f take the derivative of g take the derivative of h ... NOT take the derivative of f tan(g)(h)(k)...

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0ok so i go backwards?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1let: f = tan(g) f' = ??? g= cos(h) g' = ??? h = e^j h' = ??? j = sqrt(k) j' = ??? k = x^2+1 k' = ???

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1take them one at a time

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0ok..so k'=2x and j'= 1/x^1/2 rite?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1except use the "variable" as in each case; only the last one uses an x

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1let: f = tan(g) f' = sec^2(g) g= cos(h) g' = sin(h) h = e^j h' = j e^j j = sqrt(k) j' = 1/(2sqrt(k)) k = x^2+1 k' = 2x

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0ok can u wait fr a few moments..ill try solving the whole thing and tell u the answer so u can tell me if its right or wrong?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1i would personally leave it in a "defined" format so that it is cleaner to write up

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0but tom i have an exam..so there i cant keep it clean..i have 2 give the answer..so ill solve it..would u pls pls check it?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1ill chk it when your done ....

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0wait..fr e^j shouldnt it be e^j * d/dx of j?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1hmmm, j' e^j yes, but your already solving for j' so thats really just e^j

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the j' is part of the chain rule process, which you are already doing ....

Nikhil619
 one year ago
Best ResponseYou've already chosen the best response.0:D thnx...fr ure help also.. :)
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