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amistre64Best ResponseYou've already chosen the best response.1
its just an application of chaining a chain ....
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
\[\frac{d}{dx} f(g(h(k(...(x)))))=f'()~g'()~h'()~k'()~.......x'\]
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
wait what i dont get it..
 11 months ago

perlBest ResponseYou've already chosen the best response.0
amistre is showing off :D
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
all this amounts to is chain rule practice .... if you know the chain rule, then its just a matter of keeping a clean record
 11 months ago

perlBest ResponseYou've already chosen the best response.0
amistre, i dont thats right though
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
ok so im new to this ..can u teach me pls?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
there are some cases where the mechanism of a derivative works, but the equation itself is bad .... i dont think this is the case tho
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
what do u want me to do?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
y= tan(cos(e^sqrt(x^2+1))) let: f = tan(g) g= cos(h) h = e^j j = sqrt(k) k = x^2+1
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
then find the derivative of each one, and multiply them all together ...
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
but hw can i take derivative of tan(g)(h)(j)(k) ?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
take the derivative of f take the derivative of g take the derivative of h ... NOT take the derivative of f tan(g)(h)(k)...
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
ok so i go backwards?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
let: f = tan(g) f' = ??? g= cos(h) g' = ??? h = e^j h' = ??? j = sqrt(k) j' = ??? k = x^2+1 k' = ???
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
take them one at a time
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
ok..so k'=2x and j'= 1/x^1/2 rite?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
except use the "variable" as in each case; only the last one uses an x
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
let: f = tan(g) f' = sec^2(g) g= cos(h) g' = sin(h) h = e^j h' = j e^j j = sqrt(k) j' = 1/(2sqrt(k)) k = x^2+1 k' = 2x
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
ok can u wait fr a few moments..ill try solving the whole thing and tell u the answer so u can tell me if its right or wrong?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
i would personally leave it in a "defined" format so that it is cleaner to write up
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
but tom i have an exam..so there i cant keep it clean..i have 2 give the answer..so ill solve it..would u pls pls check it?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
ill chk it when your done ....
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
wait..fr e^j shouldnt it be e^j * d/dx of j?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
hmmm, j' e^j yes, but your already solving for j' so thats really just e^j
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
the j' is part of the chain rule process, which you are already doing ....
 11 months ago

Nikhil619Best ResponseYou've already chosen the best response.0
:D thnx...fr ure help also.. :)
 11 months ago
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