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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
its just an application of chaining a chain ....
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{d}{dx} f(g(h(k(...(x)))))=f'()~g'()~h'()~k'()~.......x'\]
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
wait what i dont get it..
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
amistre is showing off :D
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
@amistre64
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
@perl can u help?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
all this amounts to is chain rule practice .... if you know the chain rule, then its just a matter of keeping a clean record
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
amistre, i dont thats right though
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1366900627282:dw
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
ok so im new to this ..can u teach me pls?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
there are some cases where the mechanism of a derivative works, but the equation itself is bad .... i dont think this is the case tho
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
what do u want me to do?
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1366900684785:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
y= tan(cos(e^sqrt(x^2+1))) let: f = tan(g) g= cos(h) h = e^j j = sqrt(k) k = x^2+1
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
then find the derivative of each one, and multiply them all together ...
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
but hw can i take derivative of tan(g)(h)(j)(k) ?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
take the derivative of f take the derivative of g take the derivative of h ... NOT take the derivative of f tan(g)(h)(k)...
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
ok so i go backwards?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
let: f = tan(g) f' = ??? g= cos(h) g' = ??? h = e^j h' = ??? j = sqrt(k) j' = ??? k = x^2+1 k' = ???
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
take them one at a time
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
ok..so k'=2x and j'= 1/x^1/2 rite?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
except use the "variable" as in each case; only the last one uses an x
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
let: f = tan(g) f' = sec^2(g) g= cos(h) g' = sin(h) h = e^j h' = j e^j j = sqrt(k) j' = 1/(2sqrt(k)) k = x^2+1 k' = 2x
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
ok can u wait fr a few moments..ill try solving the whole thing and tell u the answer so u can tell me if its right or wrong?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i would personally leave it in a "defined" format so that it is cleaner to write up
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
but tom i have an exam..so there i cant keep it clean..i have 2 give the answer..so ill solve it..would u pls pls check it?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
ill chk it when your done ....
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
wait..fr e^j shouldnt it be e^j * d/dx of j?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
hmmm, j' e^j yes, but your already solving for j' so thats really just e^j
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the j' is part of the chain rule process, which you are already doing ....
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good eye :)
 one year ago

Nikhil619 Group TitleBest ResponseYou've already chosen the best response.0
:D thnx...fr ure help also.. :)
 one year ago
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