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2.
Make a boxandwhisker plot of the data.
Average daily temperatures in Tucson, Arizona, in December:
67, 57, 52, 51, 64, 58, 67, 58, 55, 59, 66, 50, 57, 62, 58, 50, 58, 50, 60, 63 (1 point)
boxandwhisker plot answer a
boxandwhisker plot answer b
boxandwhisker plot answer c
boxandwhisker plot answer d
3.
Find the values of the 30th and 90th percentiles of the data.
129, 113, 200, 100, 105, 132, 100, 176, 146, 152 (1 point)
30th percentile = 105
90th percentile = 200
30th percentile = 113
90th percentile = 200
30th percentile = 105
90th percentile = 176
 11 months ago
 11 months ago
2. Make a boxandwhisker plot of the data. Average daily temperatures in Tucson, Arizona, in December: 67, 57, 52, 51, 64, 58, 67, 58, 55, 59, 66, 50, 57, 62, 58, 50, 58, 50, 60, 63 (1 point) boxandwhisker plot answer a boxandwhisker plot answer b boxandwhisker plot answer c boxandwhisker plot answer d 3. Find the values of the 30th and 90th percentiles of the data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152 (1 point) 30th percentile = 105 90th percentile = 200 30th percentile = 113 90th percentile = 200 30th percentile = 105 90th percentile = 176
 11 months ago
 11 months ago

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bethjewell1996Best ResponseYou've already chosen the best response.0
2. Make a boxandwhisker plot of the data. Average daily temperatures in Tucson, Arizona, in December: 67, 57, 52, 51, 64, 58, 67, 58, 55, 59, 66, 50, 57, 62, 58, 50, 58, 50, 60, 63 (1 point) boxandwhisker plot answer a boxandwhisker plot answer b boxandwhisker plot answer c boxandwhisker plot answer d 3. Find the values of the 30th and 90th percentiles of the data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152 (1 point) 30th percentile = 105 90th percentile = 200 30th percentile = 113 90th percentile = 200 30th percentile = 105 90th percentile = 176 30th percentile = 113 90th percentile = 176 4. What are the mean, variance, and standard deviation of these values? Round to the nearest tenth. 11, 11, 3, 1, 11, 11 (1 point) mean = 8 variance = 2.1 standard deviation = 4.7 mean = 11 variance = 2.1 standard deviation = 4.3 mean = 11 variance = 2.1 standard deviation = 4.3 mean = 8 variance = 18.3 standard deviation = 4.3 5. Mrs. Jones Algebra 2 class scored very well on yesterday’s quiz. With one exception, everyone received an A. Within how many standard deviations of the mean do all the quiz grades fall? 91, 92, 94, 88, 96, 99, 91, 93, 94, 97, 95, 97 (1 point) 2 1 3 4 6. According to one study, 61% of the population swallow at least one spider per year in their sleep. Based on this study, what is the probability that exactly 7 of 10 randomly selected people have swallowed at least one spider in their sleep in the last year. (1 point) 70% 22% 1% 34% 7. Use the Binomial Theorem to find the binomial expansion of the expression. (d–5)6 (1 point) d6 + 6d5 + 15d4 + 20d3 + 15d2 + 6d + 1 d6 – 6d5 + 15d4 – 20d3 + 15d2 – 6d + 1 d6 + 30d5 + 375d4 + 2,500d3 + 9,375d2 + 18,750d + 15,625 d6 – 30d5 + 375d4 – 2,500d3 + 9,375d2 – 18,750d + 15,625 The scores on an exam are normally distributed with a mean of 77 and a standard deviation of 10. What percent of the scores are greater than 87? (1 point) 68% 16% 84% 2.5% 10. A grocery store will only accept yellow onions that are at least 3 in. in diameter. A grower has a crop of onions with diameters that are normally distributed with a mean diameter of 3.25 in. and a standard deviation of 0.25 in. What percent of the onions will be accepted by the grocery store? (1 point) 34% 97.5% 84% 50% 11. A restaurant chain’s owners are trying to decide if they want to open up a franchise in your town. To help them decide, they want to find out how often people in your town go out to eat. A researcher interviews people leaving a local restaurant. Is there a bias in this sampling method? Explain. 12. Is there any bias in the following survey question? Explain. Should a state have the power to kill a person for breaking the law.
 11 months ago

bethjewell1996Best ResponseYou've already chosen the best response.0
can anyone help please I need to get this done?
 11 months ago
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