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ethompsonn

  • 3 years ago

HELP!? EXCLUDED VALUES?

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  1. ethompsonn
    • 3 years ago
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    |dw:1366986144149:dw|

  2. anonymous
    • 3 years ago
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    if you have a rational function, set the denominator equal to zero and solve

  3. ethompsonn
    • 3 years ago
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    x = 0 and 3 x = 0 and 2 x = -3 and 3 none of the above

  4. ethompsonn
    • 3 years ago
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    so B?

  5. ethompsonn
    • 3 years ago
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    @satellite73

  6. ethompsonn
    • 3 years ago
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    @snowman97

  7. nubeer
    • 3 years ago
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    set the denominator equal to 0 and then solve. x(x-3) = 0

  8. ethompsonn
    • 3 years ago
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    whaaat?

  9. ethompsonn
    • 3 years ago
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    ooooohhh

  10. ethompsonn
    • 3 years ago
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    so its C? @nubeer

  11. nubeer
    • 3 years ago
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    no.. x(x-3)=0.. it means x = 0 , x-3=0 , x = 3 so 0 and 3

  12. ethompsonn
    • 3 years ago
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    can you help with one more?

  13. nubeer
    • 3 years ago
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    ya sure.

  14. ethompsonn
    • 3 years ago
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    \[\frac{ y+5 }{ y^2 +4y - 32 }\]

  15. ethompsonn
    • 3 years ago
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    y = -5 and 4 y = 5 and 32 y = 4 and -8 none of the above

  16. ethompsonn
    • 3 years ago
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    @nubeer ?

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