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Beautiful_Lier96
Group Title
1. Find f (g(7)) and g(f(7)) for the functions f (x) = x2 – 3x + 15 and g(x) = –x
A. f (g(7)) = 85; g(f(7)) = –43
B. f (g(7)) = –13; g(f(7)) = –8
C. f (g(7)) = –55; g(f(7)) = –27
D. f (g(7)) = –43; g(f(7)) = –43
find the functions that result from f(g(x)) and g(f(x)).
2. f(x)=√2x1, g(x)=5x+3
A. g(f(x))=√5x+4; f(g(x))=5(√2x1)+3
B. F(G(X))=√5X+4; G(F(X))=5(√2X1)+3
C. f(g(x))=√10x+5; g(f(x))=5√(2x1)+3
D. f(g(x))=√10x5; g(f(x))=5√(2x1)3
3. f(x)=2x^2, g(x)=x+4
A. f(g(x))=2x^216x32; g(f(x))=2x^2+4
B. g(f(x))=2x^216x32; f(g(x))=2x^2+4
C. f(g(x))=2x^2+16x+32; g(f(x))=2x^2+4
D. g(f(x))=2x^2+16x+32; f(g(x))=2x^2+4
 one year ago
 one year ago
Beautiful_Lier96 Group Title
1. Find f (g(7)) and g(f(7)) for the functions f (x) = x2 – 3x + 15 and g(x) = –x A. f (g(7)) = 85; g(f(7)) = –43 B. f (g(7)) = –13; g(f(7)) = –8 C. f (g(7)) = –55; g(f(7)) = –27 D. f (g(7)) = –43; g(f(7)) = –43 find the functions that result from f(g(x)) and g(f(x)). 2. f(x)=√2x1, g(x)=5x+3 A. g(f(x))=√5x+4; f(g(x))=5(√2x1)+3 B. F(G(X))=√5X+4; G(F(X))=5(√2X1)+3 C. f(g(x))=√10x+5; g(f(x))=5√(2x1)+3 D. f(g(x))=√10x5; g(f(x))=5√(2x1)3 3. f(x)=2x^2, g(x)=x+4 A. f(g(x))=2x^216x32; g(f(x))=2x^2+4 B. g(f(x))=2x^216x32; f(g(x))=2x^2+4 C. f(g(x))=2x^2+16x+32; g(f(x))=2x^2+4 D. g(f(x))=2x^2+16x+32; f(g(x))=2x^2+4
 one year ago
 one year ago

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ajprincess Group TitleBest ResponseYou've already chosen the best response.1
to find f(g(x)) plug in g(x) in place of x in f(x). so can u find f(g(x)) for the first question @Beautiful_Lier96
 one year ago

Beautiful_Lier96 Group TitleBest ResponseYou've already chosen the best response.0
im still lost _
 one year ago

GeorgeLavergne Group TitleBest ResponseYou've already chosen the best response.0
Yeah it's kind of confusing but you need to reread it to understand it a bit more
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
f (x) = x2 – 3x + 15, g(x) = –x . to find f(g(x)) u have to plug in g(x) in stead of x in f(x). f(g(x))=(g(x))^23(g(x))+15 =(x)^23(x)+15 getting this? @Beautiful_Lier96
 one year ago
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