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use plancks equation:
E=hc/lambda

how?

so is it 6.62*10^-34/3.2? hey what is c then?

the charge, e, is \(1.6 \times 10^{-19}C\)

so is the answer 1.24*10^-6

ya and then i solved it using calculator...i got\[3.89 * 10^{-7}\]

That's the wavelength :)

and the unit of wavelength is Hz right

Hertz is for frequency, Wavelength is meter,

3.89∗10^(−7) meters ???

oh ya thx...what abt 2nd one

So the frequency plays a role here on the emission of photons.

I gotta go now, I'll leave it here, think about that :)

this is beyond my learning curve :) i can recall levers and rotations and such

haha thx tho

I would need to refresh my memory in modern physics. So no. Lol

haha ok.

@Frostbite might know.

well looks like audience is here...but the players are not. haha

I will make some researches and see if i can help :3

can't you use kirkchoffs laws here?

i really dont know how to do this...so if anyone can ex[lain it will be great

i do think we r using planck's equation and stuff here

is this first answer?

Yes.

oh gotcha

so energy photons absorbed are all of them?

Photons could only be absorbed if that have E = (E2-E0), E = (E1-E0), or E= (E2-E1).

ohk...so thats the second answer...what abt third one

oh so in last two answers we dont need any calculations and stuff?

No.

what abt work function...is it the same thing as absorbing and emitting photons

No. The work function is not related to your question at all. It is a separate effect.

nice thanks...

wish to give u 3 medals but just have 1

Quite alright, medals are not important.

exactly thx for explaining stuff