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Moneeka96

  • 3 years ago

Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)

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  1. electrokid
    • 3 years ago
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    \[\Huge \color{Lime}{~\:\:\:\:\:\:\:\:\:\:\:\:\frak Welcome\:\:\frak To\:\:\frak Open\frak Study}\]

  2. Yahoo!
    • 3 years ago
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    F = Kq1q2/r^2

  3. electrokid
    • 3 years ago
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    Coulomb's Law: \[F=K{q_1q_2\over d^2}\] \[K = const.\\ q_1 = 2\times10^{-6}C\\ q_2= 2\times10^{-6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m} \]

  4. electrokid
    • 3 years ago
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    the important thing is to have all the units in SI system

  5. Moneeka96
    • 3 years ago
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    So i had to put cm into m like i believe you did above?

  6. electrokid
    • 3 years ago
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    yep

  7. Moneeka96
    • 3 years ago
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    now from here where do I go?

  8. Moneeka96
    • 3 years ago
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    wouldnt q2 be negative?

  9. electrokid
    • 3 years ago
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    we plug em in the equation for the force. \[ F=8.99\times10^{9}\times \frac{2\times10^{-6}\times2\times10^{-6}}{(0.05)^2} \]

  10. electrokid
    • 3 years ago
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    the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges

  11. Moneeka96
    • 3 years ago
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    Okay cool so then Id just plug the above into my calculator and thats the answer. right?

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