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## Moneeka96 Group Title Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C) one year ago one year ago

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1. electrokid Group Title

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2. Yahoo! Group Title

F = Kq1q2/r^2

3. electrokid Group Title

Coulomb's Law: $F=K{q_1q_2\over d^2}$ $K = const.\\ q_1 = 2\times10^{-6}C\\ q_2= 2\times10^{-6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m}$

4. electrokid Group Title

the important thing is to have all the units in SI system

5. Moneeka96 Group Title

So i had to put cm into m like i believe you did above?

6. electrokid Group Title

yep

7. Moneeka96 Group Title

now from here where do I go?

8. Moneeka96 Group Title

wouldnt q2 be negative?

9. electrokid Group Title

we plug em in the equation for the force. $F=8.99\times10^{9}\times \frac{2\times10^{-6}\times2\times10^{-6}}{(0.05)^2}$

10. electrokid Group Title

the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges

11. Moneeka96 Group Title

Okay cool so then Id just plug the above into my calculator and thats the answer. right?