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anonymous
 3 years ago
Pleaseeee help me..
What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)
anonymous
 3 years ago
Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Huge \color{Lime}{~\:\:\:\:\:\:\:\:\:\:\:\:\frak Welcome\:\:\frak To\:\:\frak Open\frak Study}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Coulomb's Law: \[F=K{q_1q_2\over d^2}\] \[K = const.\\ q_1 = 2\times10^{6}C\\ q_2= 2\times10^{6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the important thing is to have all the units in SI system

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So i had to put cm into m like i believe you did above?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now from here where do I go?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wouldnt q2 be negative?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we plug em in the equation for the force. \[ F=8.99\times10^{9}\times \frac{2\times10^{6}\times2\times10^{6}}{(0.05)^2} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay cool so then Id just plug the above into my calculator and thats the answer. right?
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