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Moneeka96 Group Title

Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)

  • one year ago
  • one year ago

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  1. electrokid Group Title
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    • one year ago
  2. Yahoo! Group Title
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    F = Kq1q2/r^2

    • one year ago
  3. electrokid Group Title
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    Coulomb's Law: \[F=K{q_1q_2\over d^2}\] \[K = const.\\ q_1 = 2\times10^{-6}C\\ q_2= 2\times10^{-6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m} \]

    • one year ago
  4. electrokid Group Title
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    the important thing is to have all the units in SI system

    • one year ago
  5. Moneeka96 Group Title
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    So i had to put cm into m like i believe you did above?

    • one year ago
  6. electrokid Group Title
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    yep

    • one year ago
  7. Moneeka96 Group Title
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    now from here where do I go?

    • one year ago
  8. Moneeka96 Group Title
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    wouldnt q2 be negative?

    • one year ago
  9. electrokid Group Title
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    we plug em in the equation for the force. \[ F=8.99\times10^{9}\times \frac{2\times10^{-6}\times2\times10^{-6}}{(0.05)^2} \]

    • one year ago
  10. electrokid Group Title
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    the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges

    • one year ago
  11. Moneeka96 Group Title
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    Okay cool so then Id just plug the above into my calculator and thats the answer. right?

    • one year ago
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