anonymous
  • anonymous
Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\Huge \color{Lime}{~\:\:\:\:\:\:\:\:\:\:\:\:\frak Welcome\:\:\frak To\:\:\frak Open\frak Study}\]
anonymous
  • anonymous
F = Kq1q2/r^2
anonymous
  • anonymous
Coulomb's Law: \[F=K{q_1q_2\over d^2}\] \[K = const.\\ q_1 = 2\times10^{-6}C\\ q_2= 2\times10^{-6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m} \]

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anonymous
  • anonymous
the important thing is to have all the units in SI system
anonymous
  • anonymous
So i had to put cm into m like i believe you did above?
anonymous
  • anonymous
yep
anonymous
  • anonymous
now from here where do I go?
anonymous
  • anonymous
wouldnt q2 be negative?
anonymous
  • anonymous
we plug em in the equation for the force. \[ F=8.99\times10^{9}\times \frac{2\times10^{-6}\times2\times10^{-6}}{(0.05)^2} \]
anonymous
  • anonymous
the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges
anonymous
  • anonymous
Okay cool so then Id just plug the above into my calculator and thats the answer. right?

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