## Moneeka96 2 years ago Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)

1. electrokid

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2. Yahoo!

F = Kq1q2/r^2

3. electrokid

Coulomb's Law: $F=K{q_1q_2\over d^2}$ $K = const.\\ q_1 = 2\times10^{-6}C\\ q_2= 2\times10^{-6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m}$

4. electrokid

the important thing is to have all the units in SI system

5. Moneeka96

So i had to put cm into m like i believe you did above?

6. electrokid

yep

7. Moneeka96

now from here where do I go?

8. Moneeka96

wouldnt q2 be negative?

9. electrokid

we plug em in the equation for the force. $F=8.99\times10^{9}\times \frac{2\times10^{-6}\times2\times10^{-6}}{(0.05)^2}$

10. electrokid

the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges

11. Moneeka96

Okay cool so then Id just plug the above into my calculator and thats the answer. right?