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Moneeka96

  • one year ago

Pleaseeee help me.. What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? (µC = 1.0 × 10–6 C)

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  1. electrokid
    • one year ago
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  2. Yahoo!
    • one year ago
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    F = Kq1q2/r^2

  3. electrokid
    • one year ago
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    Coulomb's Law: \[F=K{q_1q_2\over d^2}\] \[K = const.\\ q_1 = 2\times10^{-6}C\\ q_2= 2\times10^{-6}C\\ d=5{\rm cm}\times {1{\rm m}\over 100{\rm cm}}=0.05{\rm m} \]

  4. electrokid
    • one year ago
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    the important thing is to have all the units in SI system

  5. Moneeka96
    • one year ago
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    So i had to put cm into m like i believe you did above?

  6. electrokid
    • one year ago
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    yep

  7. Moneeka96
    • one year ago
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    now from here where do I go?

  8. Moneeka96
    • one year ago
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    wouldnt q2 be negative?

  9. electrokid
    • one year ago
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    we plug em in the equation for the force. \[ F=8.99\times10^{9}\times \frac{2\times10^{-6}\times2\times10^{-6}}{(0.05)^2} \]

  10. electrokid
    • one year ago
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    the negative sign can be neglected since we are only looking for the magnitude (i.e., the amount) of force. since the two charges are oppositely charged, the above force will be a force of attraction. this is the information we get from the charges

  11. Moneeka96
    • one year ago
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    Okay cool so then Id just plug the above into my calculator and thats the answer. right?

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