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2x3 - 5x2y + xy2 + 2y3 a. Simplify (2x2 + y2)(x - 2y) = ? b. Simplify (2x + y)(x2 -3xy + 2y 2 ) = ?

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where is c and d?
\[2\,{x}^{3}-5\,{x}^{2}y+x{y}^{2}+2\,{y}^{3}\] did you mean that?

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Other answers:

ooh where are c and d then :) i got my own answer can i see c and d?
theyre not right for this
so far i think it is b but i feel it can be simplified further :)
its a
was it a?
well i get :) (-y+x)*(x-2*y)*(y+2*x) fully factored
:) i'll check a and b :)
i dont think it is a :(
now for b
its b!!!!!!!!!!!!!!!!!!:)))))))))))))))))))))))))))
told ya ;)
and i check to and it is b :D
If you know algrabeic long division then there is a theory of if you divide your given polynomial in this case 2x3 - 5x2y + xy2 + 2y3 by a suspected binomial or trinomial (2x + y) or (x2 -3xy + 2y 2 ) ^ those are from B the 2 expressions inside the ( ) and you get 0 then that trinomial or binomial is a factor and therfore part of the answer :)
if you get a remainder of 0 :P
in other words 2x3 - 5x2y + xy2 + 2y3 -------------------- = (x2 -3xy + 2y 2 ) with no remainder (2x + y) and obviously 2x3 - 5x2y + xy2 + 2y3 --------------------- = 2x+y with no remainder (x2 -3xy + 2y 2 )
But if you dont know algabreic long division dont bother with that method :P

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