InsanelyChaotic 2 years ago 2x3 - 5x2y + xy2 + 2y3 a. Simplify (2x2 + y2)(x - 2y) = ? b. Simplify (2x + y)(x2 -3xy + 2y 2 ) = ?

1. timo86m

where is c and d?

2. timo86m

\[2\,{x}^{3}-5\,{x}^{2}y+x{y}^{2}+2\,{y}^{3}\] did you mean that?

3. InsanelyChaotic

yes

4. timo86m

ooh where are c and d then :) i got my own answer can i see c and d?

5. InsanelyChaotic

theyre not right for this

6. timo86m

so far i think it is b but i feel it can be simplified further :)

7. InsanelyChaotic

elimination

8. InsanelyChaotic

its a

9. InsanelyChaotic

;)

10. timo86m

was it a?

11. timo86m

well i get :) (-y+x)*(x-2*y)*(y+2*x) fully factored

12. InsanelyChaotic

idk

13. timo86m

:) i'll check a and b :)

14. timo86m

i dont think it is a :(

15. timo86m

now for b

16. InsanelyChaotic

its b!!!!!!!!!!!!!!!!!!:)))))))))))))))))))))))))))

17. timo86m

told ya ;)

18. timo86m

and i check to and it is b :D

19. timo86m

If you know algrabeic long division then there is a theory of if you divide your given polynomial in this case 2x3 - 5x2y + xy2 + 2y3 by a suspected binomial or trinomial (2x + y) or (x2 -3xy + 2y 2 ) ^ those are from B the 2 expressions inside the ( ) and you get 0 then that trinomial or binomial is a factor and therfore part of the answer :)

20. timo86m

if you get a remainder of 0 :P

21. timo86m

in other words 2x3 - 5x2y + xy2 + 2y3 -------------------- = (x2 -3xy + 2y 2 ) with no remainder (2x + y) and obviously 2x3 - 5x2y + xy2 + 2y3 --------------------- = 2x+y with no remainder (x2 -3xy + 2y 2 )

22. timo86m

But if you dont know algabreic long division dont bother with that method :P