anonymous
  • anonymous
Help http://prntscr.com/12brlc
Precalculus
schrodinger
  • schrodinger
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anonymous
  • anonymous
take derivitive first :D
anonymous
  • anonymous
brb :)
anonymous
  • anonymous
okay tell me when your back

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goformit100
  • goformit100
First of all for solving this question do you know the conception of : Derivatives. and i know you can then definitely can solve the question on your own
anonymous
  • anonymous
take dervitive first of all : can you do that?
anonymous
  • anonymous
I dont remember reading anything about derivatives in the text book
anonymous
  • anonymous
how about differentials?
anonymous
  • anonymous
A little. I remember seeing it. Didnt go into much detail
anonymous
  • anonymous
you weren't paying much attention lol :P
anonymous
  • anonymous
Can you tell me. or send me a link about them. either one is fine. :)
anonymous
  • anonymous
anyhoo first we must take the derivative aka differential. x^2+5*x luckily this one is one of the most basic and using the rules aka formulas. http://myhandbook.info/form_diff.html look at constant rule, sum rule and power rule :D try it out if you can
anonymous
  • anonymous
also the factor rule :)
anonymous
  • anonymous
which factor rul
anonymous
  • anonymous
what do i plug in for d?
anonymous
  • anonymous
and d/dx just means the derivative operator so d/dx(x^2+5*x) means derivitve of x^2+5*x with respect to x d/dx(x^2)+ d/dx(5*x) the sum rule this makes it more easy :) seperated into 2 small derivatives instead of one big one. we handle it as 2 seperate problems d/dx(x^2)= 2x by the power rule simply decrease the exponent by 1 and multiply the variable and coefficient by the exponent you just decrased. you get 2 :). d/dx(5*x) = 5 by factor rule now you plug back in because you did them seperately 2x+5 and that is derivative :) with me so far?
anonymous
  • anonymous
yes
anonymous
  • anonymous
2x+5 is also a tangent function which gives the slope of the tangent at any given x. For example at x=0 the slope is 5. they want it at 4 tho. So plug it in 2(4)+5=8+5=13 That is your answer :)
anonymous
  • anonymous
no
anonymous
  • anonymous
But i saw where I messed up!
anonymous
  • anonymous
its fixed
anonymous
  • anonymous
was i right tho :)
anonymous
  • anonymous
Thank you so much!
anonymous
  • anonymous
weird tho if you not familiar with calc 1 concepts then it is weird problem to do.
anonymous
  • anonymous
Im not in Calc 1 lol
anonymous
  • anonymous
precalc?
anonymous
  • anonymous
yes
bahrom7893
  • bahrom7893
hmm maybe if we do: x1 = 3 x2 = 5 y1 = 9+15 = 24 y2 = 25+25 = 50 M = (y2-y1)/(x2-x1) = (50-24)/(5-3) = 26/2=13
bahrom7893
  • bahrom7893
Voila, the answer given to us by calculus matches up: f'(4) = 2x+5 = 2*4+5=13
anonymous
  • anonymous
aaa :) calc way is easier tho.
bahrom7893
  • bahrom7893
:)
anonymous
  • anonymous
Thank you both!
anonymous
  • anonymous
Im going through all the qustions I missed so i can understand them better
anonymous
  • anonymous
good for you :D

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