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Skittles456

  • 3 years ago

Help http://prntscr.com/12brlc

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  1. timo86m
    • 3 years ago
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    take derivitive first :D

  2. timo86m
    • 3 years ago
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    brb :)

  3. Skittles456
    • 3 years ago
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    okay tell me when your back

  4. goformit100
    • 3 years ago
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    First of all for solving this question do you know the conception of : Derivatives. and i know you can then definitely can solve the question on your own

  5. timo86m
    • 3 years ago
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    take dervitive first of all : can you do that?

  6. Skittles456
    • 3 years ago
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    I dont remember reading anything about derivatives in the text book

  7. timo86m
    • 3 years ago
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    how about differentials?

  8. Skittles456
    • 3 years ago
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    A little. I remember seeing it. Didnt go into much detail

  9. timo86m
    • 3 years ago
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    you weren't paying much attention lol :P

  10. Skittles456
    • 3 years ago
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    Can you tell me. or send me a link about them. either one is fine. :)

  11. timo86m
    • 3 years ago
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    anyhoo first we must take the derivative aka differential. x^2+5*x luckily this one is one of the most basic and using the rules aka formulas. http://myhandbook.info/form_diff.html look at constant rule, sum rule and power rule :D try it out if you can

  12. timo86m
    • 3 years ago
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    also the factor rule :)

  13. Skittles456
    • 3 years ago
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    which factor rul

  14. Skittles456
    • 3 years ago
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    what do i plug in for d?

  15. timo86m
    • 3 years ago
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    and d/dx just means the derivative operator so d/dx(x^2+5*x) means derivitve of x^2+5*x with respect to x d/dx(x^2)+ d/dx(5*x) the sum rule this makes it more easy :) seperated into 2 small derivatives instead of one big one. we handle it as 2 seperate problems d/dx(x^2)= 2x by the power rule simply decrease the exponent by 1 and multiply the variable and coefficient by the exponent you just decrased. you get 2 :). d/dx(5*x) = 5 by factor rule now you plug back in because you did them seperately 2x+5 and that is derivative :) with me so far?

  16. Skittles456
    • 3 years ago
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    yes

  17. timo86m
    • 3 years ago
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    2x+5 is also a tangent function which gives the slope of the tangent at any given x. For example at x=0 the slope is 5. they want it at 4 tho. So plug it in 2(4)+5=8+5=13 That is your answer :)

  18. Skittles456
    • 3 years ago
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    no

  19. Skittles456
    • 3 years ago
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    But i saw where I messed up!

  20. Skittles456
    • 3 years ago
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    its fixed

  21. timo86m
    • 3 years ago
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    was i right tho :)

  22. Skittles456
    • 3 years ago
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    Thank you so much!

  23. timo86m
    • 3 years ago
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    weird tho if you not familiar with calc 1 concepts then it is weird problem to do.

  24. Skittles456
    • 3 years ago
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    Im not in Calc 1 lol

  25. timo86m
    • 3 years ago
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    precalc?

  26. Skittles456
    • 3 years ago
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    yes

  27. bahrom7893
    • 3 years ago
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    hmm maybe if we do: x1 = 3 x2 = 5 y1 = 9+15 = 24 y2 = 25+25 = 50 M = (y2-y1)/(x2-x1) = (50-24)/(5-3) = 26/2=13

  28. bahrom7893
    • 3 years ago
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    Voila, the answer given to us by calculus matches up: f'(4) = 2x+5 = 2*4+5=13

  29. timo86m
    • 3 years ago
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    aaa :) calc way is easier tho.

  30. bahrom7893
    • 3 years ago
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    :)

  31. Skittles456
    • 3 years ago
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    Thank you both!

  32. Skittles456
    • 3 years ago
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    Im going through all the qustions I missed so i can understand them better

  33. timo86m
    • 3 years ago
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    good for you :D

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