Help http://prntscr.com/12brlc

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Help http://prntscr.com/12brlc

Precalculus
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

take derivitive first :D
brb :)
okay tell me when your back

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

First of all for solving this question do you know the conception of : Derivatives. and i know you can then definitely can solve the question on your own
take dervitive first of all : can you do that?
I dont remember reading anything about derivatives in the text book
how about differentials?
A little. I remember seeing it. Didnt go into much detail
you weren't paying much attention lol :P
Can you tell me. or send me a link about them. either one is fine. :)
anyhoo first we must take the derivative aka differential. x^2+5*x luckily this one is one of the most basic and using the rules aka formulas. http://myhandbook.info/form_diff.html look at constant rule, sum rule and power rule :D try it out if you can
also the factor rule :)
which factor rul
what do i plug in for d?
and d/dx just means the derivative operator so d/dx(x^2+5*x) means derivitve of x^2+5*x with respect to x d/dx(x^2)+ d/dx(5*x) the sum rule this makes it more easy :) seperated into 2 small derivatives instead of one big one. we handle it as 2 seperate problems d/dx(x^2)= 2x by the power rule simply decrease the exponent by 1 and multiply the variable and coefficient by the exponent you just decrased. you get 2 :). d/dx(5*x) = 5 by factor rule now you plug back in because you did them seperately 2x+5 and that is derivative :) with me so far?
yes
2x+5 is also a tangent function which gives the slope of the tangent at any given x. For example at x=0 the slope is 5. they want it at 4 tho. So plug it in 2(4)+5=8+5=13 That is your answer :)
no
But i saw where I messed up!
its fixed
was i right tho :)
Thank you so much!
weird tho if you not familiar with calc 1 concepts then it is weird problem to do.
Im not in Calc 1 lol
precalc?
yes
hmm maybe if we do: x1 = 3 x2 = 5 y1 = 9+15 = 24 y2 = 25+25 = 50 M = (y2-y1)/(x2-x1) = (50-24)/(5-3) = 26/2=13
Voila, the answer given to us by calculus matches up: f'(4) = 2x+5 = 2*4+5=13
aaa :) calc way is easier tho.
:)
Thank you both!
Im going through all the qustions I missed so i can understand them better
good for you :D

Not the answer you are looking for?

Search for more explanations.

Ask your own question