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- anonymous

Help
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- schrodinger

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- anonymous

take derivitive first :D

- anonymous

brb :)

- anonymous

okay tell me when your back

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## More answers

- goformit100

First of all for solving this question do you know the conception of : Derivatives.
and i know you can then definitely can solve the question on your own

- anonymous

take dervitive first of all : can you do that?

- anonymous

I dont remember reading anything about derivatives in the text book

- anonymous

how about differentials?

- anonymous

A little. I remember seeing it. Didnt go into much detail

- anonymous

you weren't paying much attention lol :P

- anonymous

Can you tell me. or send me a link about them. either one is fine. :)

- anonymous

anyhoo first we must take the derivative aka differential.
x^2+5*x
luckily this one is one of the most basic and using the rules aka formulas.
http://myhandbook.info/form_diff.html
look at constant rule, sum rule and power rule :D try it out if you can

- anonymous

also the factor rule :)

- anonymous

which factor rul

- anonymous

what do i plug in for d?

- anonymous

and d/dx just means the derivative operator
so
d/dx(x^2+5*x)
means derivitve of x^2+5*x with respect to x
d/dx(x^2)+ d/dx(5*x)
the sum rule this makes it more easy :) seperated into 2 small derivatives instead of one big one. we handle it as 2 seperate problems
d/dx(x^2)= 2x
by the power rule simply decrease the exponent by 1 and multiply the variable and coefficient by the exponent you just decrased. you get 2 :).
d/dx(5*x) = 5
by factor rule
now you plug back in because you did them seperately
2x+5 and that is derivative :) with me so far?

- anonymous

yes

- anonymous

2x+5 is also a tangent function which gives the slope of the tangent at any given x. For example at x=0 the slope is 5.
they want it at 4 tho. So plug it in
2(4)+5=8+5=13
That is your answer :)

- anonymous

no

- anonymous

But i saw where I messed up!

- anonymous

its fixed

- anonymous

was i right tho :)

- anonymous

Thank you so much!

- anonymous

weird tho if you not familiar with calc 1 concepts then it is weird problem to do.

- anonymous

Im not in Calc 1 lol

- anonymous

precalc?

- anonymous

yes

- bahrom7893

hmm maybe if we do:
x1 = 3
x2 = 5
y1 = 9+15 = 24
y2 = 25+25 = 50
M = (y2-y1)/(x2-x1) = (50-24)/(5-3) = 26/2=13

- bahrom7893

Voila, the answer given to us by calculus matches up:
f'(4) = 2x+5 = 2*4+5=13

- anonymous

aaa :) calc way is easier tho.

- bahrom7893

:)

- anonymous

Thank you both!

- anonymous

Im going through all the qustions I missed so i can understand them better

- anonymous

good for you :D

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