Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Skittles456 Group TitleBest ResponseYou've already chosen the best response.0
http://prntscr.com/12c0hj  thats D
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
I am looking at it :)
 one year ago

Skittles456 Group TitleBest ResponseYou've already chosen the best response.0
Take your time :)
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
For the first, since x=2t, then t=x/2. Replace t in the y=t^2+t+3 equation with x/2.. but you don't even need to do that. Can you find the y intercept of y=t^2+t+3? That's all you need to choose the answer. (what is y equal to when t=0? and note that when t=0, x=0 since x=2t)
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
First one isn't B.
 one year ago

Skittles456 Group TitleBest ResponseYou've already chosen the best response.0
Opps! I ment D not B
 one year ago

Skittles456 Group TitleBest ResponseYou've already chosen the best response.0
Let me double check to make sure D is my final answere lol
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
http://graphsketch.com/parametric.php :D ooh
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
yintercept is when x=0
 one year ago

Skittles456 Group TitleBest ResponseYou've already chosen the best response.0
well. I know its C now but yintercept when x=0? what do you mean?
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
The yintercept is... when x=0. Did you find the yintercept of y=t^2+t+3? To find it: Replace t in y=t^2+t+3 with x/2, since t=x/2 \[\Large y=\left( \frac{ x }{ 2 } \right)^2+\frac{ x }{2 }+3 \] Two equations have the required yintercept, so you'll have to plug in a couple of points to check which is correct.
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
This would be easier if the graphs weren't so tiny...
 one year ago

Skittles456 Group TitleBest ResponseYou've already chosen the best response.0
I can send them bigger lol. I have to run for a little. I hope to be back on shortly. Ill keep this open
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Oh and you can find the vertex of a graph y=ax^2+bx+c as \[\Large x=\frac{ b }{ 2a }\] then you plug in that x value to find y. That will be the minimum value for y (ie the lowest point in the range)
 one year ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
First of all for solving this question do you know the conception of : Parametric Equations ? And after doing that, I personally guarantee that you can on your own solve this particular question. I personally believe, the happiness of solving Mathematics is much better.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.