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Skittles456
 2 years ago
Best ResponseYou've already chosen the best response.0http://prntscr.com/12c0hj  thats D

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.1For the first, since x=2t, then t=x/2. Replace t in the y=t^2+t+3 equation with x/2.. but you don't even need to do that. Can you find the y intercept of y=t^2+t+3? That's all you need to choose the answer. (what is y equal to when t=0? and note that when t=0, x=0 since x=2t)

Skittles456
 2 years ago
Best ResponseYou've already chosen the best response.0Opps! I ment D not B

Skittles456
 2 years ago
Best ResponseYou've already chosen the best response.0Let me double check to make sure D is my final answere lol

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.1yintercept is when x=0

Skittles456
 2 years ago
Best ResponseYou've already chosen the best response.0well. I know its C now but yintercept when x=0? what do you mean?

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.1The yintercept is... when x=0. Did you find the yintercept of y=t^2+t+3? To find it: Replace t in y=t^2+t+3 with x/2, since t=x/2 \[\Large y=\left( \frac{ x }{ 2 } \right)^2+\frac{ x }{2 }+3 \] Two equations have the required yintercept, so you'll have to plug in a couple of points to check which is correct.

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.1This would be easier if the graphs weren't so tiny...

Skittles456
 2 years ago
Best ResponseYou've already chosen the best response.0I can send them bigger lol. I have to run for a little. I hope to be back on shortly. Ill keep this open

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.1Oh and you can find the vertex of a graph y=ax^2+bx+c as \[\Large x=\frac{ b }{ 2a }\] then you plug in that x value to find y. That will be the minimum value for y (ie the lowest point in the range)

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0First of all for solving this question do you know the conception of : Parametric Equations ? And after doing that, I personally guarantee that you can on your own solve this particular question. I personally believe, the happiness of solving Mathematics is much better.
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