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Simplify using De Morgan's LAW: f = (qr'+q'r)'

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who is de morgan do u know
That + there is a logical AND ?
thats an inversion of xor so u should get xnor after simplifying

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Other answers:

(qr'+q'r)' (qr')'(q'r)' (q'+r)(q+r') foil it now and simplify
What is the final simplification answer??
(q'+r)(q+r') q'q + rq + q'r' + rr' qr + q'r'
thats the final simplification using demorgan's laws. the thing to notice here is that you're taking negation of ex-or
Can the equation be further simplified?
ok thx
yw ! xor and xnor are very important gates so its good idea to remember their boolean function and truth table atleast.

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