ketz
Simplify using De Morgan's LAW:
f = (qr'+q'r)'



This Question is Closed

chmvijay
Best Response
You've already chosen the best response.
0
who is de morgan do u know

terenzreignz
Best Response
You've already chosen the best response.
0
That + there is a logical AND ?

ganeshie8
Best Response
You've already chosen the best response.
2
thats an inversion of xor so u should get xnor after simplifying

ganeshie8
Best Response
You've already chosen the best response.
2
(qr'+q'r)'
(qr')'(q'r)'
(q'+r)(q+r')
foil it now and simplify

ketz
Best Response
You've already chosen the best response.
0
What is the final simplification answer??

ganeshie8
Best Response
You've already chosen the best response.
2
(q'+r)(q+r')
q'q + rq + q'r' + rr'
qr + q'r'

ganeshie8
Best Response
You've already chosen the best response.
2
thats the final simplification using demorgan's laws. the thing to notice here is that you're taking negation of exor

ketz
Best Response
You've already chosen the best response.
0
Can the equation be further simplified?

ganeshie8
Best Response
You've already chosen the best response.
2
impossible

ketz
Best Response
You've already chosen the best response.
0
ok thx

ganeshie8
Best Response
You've already chosen the best response.
2
yw ! xor and xnor are very important gates so its good idea to remember their boolean function and truth table atleast.