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ketz

  • one year ago

Simplify using De Morgan's LAW: f = (qr'+q'r)'

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  1. chmvijay
    • one year ago
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    who is de morgan do u know

  2. terenzreignz
    • one year ago
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    That + there is a logical AND ?

  3. ganeshie8
    • one year ago
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    thats an inversion of xor so u should get xnor after simplifying

  4. ganeshie8
    • one year ago
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    (qr'+q'r)' (qr')'(q'r)' (q'+r)(q+r') foil it now and simplify

  5. ketz
    • one year ago
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    What is the final simplification answer??

  6. ganeshie8
    • one year ago
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    (q'+r)(q+r') q'q + rq + q'r' + rr' qr + q'r'

  7. ganeshie8
    • one year ago
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    thats the final simplification using demorgan's laws. the thing to notice here is that you're taking negation of ex-or

  8. ketz
    • one year ago
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    Can the equation be further simplified?

  9. ganeshie8
    • one year ago
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    impossible

  10. ketz
    • one year ago
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    ok thx

  11. ganeshie8
    • one year ago
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    yw ! xor and xnor are very important gates so its good idea to remember their boolean function and truth table atleast.

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