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\[J kg ^{-1} K ^{-1}\] this is the correct way of writing the unit

Use the formul heat required =\(mc \Delta t\)

q=McDelta T

where m is mass c is specific heat capacity ,delta t=change in temperature

ok thanks

yw :)

i worked it out...is the answer 4200J

a b or c?

for a)

right !

hmm and b) is 21000J while c) is 1.68*10\[1.68\times10^{5}\] am i right???

yep :)

was it that simple?

oh and the specific heat capacity of graphite is 600\[J kg ^{-1}K ^{-1}\]

same formula !

Why dont you make a new question? rather than lump several into one post?

um i honestly dont know....im a beginner. Dont really know about this stuff! sorry!

ok i understand.

2000 J.

1600

i dont know that one, do i have to transpose?

m means Mass; c means specific heat capacity and delta T means the rise in temperature.

\[E _{H}=mcΔT\]
so the temperature rise will be:
EH divided by mass times c
am i right?

Thats perfectly correct. Just type d ans also when you find it. :)

ok i will, im working on it

Is the answer 2°C?

Yes. :)

yes!!!!! thanks :) i have one more question though

whats the unit for a) ???

ok ok so a) =60 J

Thats correct.

and c) = \[7.5\times 10^{-2} \deg C\]

Which is correct, :)

I hope you're familiar with law of conservation of energy right?

no but i will just look back in a textbook! thank you soooo much!!! you saved me!! :)

yeah no probs as long as you're familiar with concepts and numericals :)