The specific heat capacity of water= 4200 J kg-1K-1
1) How much heat energy is required to warm a) 1 kg of water from 14°C to 15°C; b) 5 kg of water from 14°C to 15°C; and c) 5 kg of water from 14°C to 22°C. THANK YOU!!

- anonymous

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

\[J kg ^{-1} K ^{-1}\] this is the correct way of writing the unit

- AravindG

Use the formul heat required =\(mc \Delta t\)

- chmvijay

q=McDelta T

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- AravindG

where m is mass c is specific heat capacity ,delta t=change in temperature

- anonymous

ok thanks

- AravindG

yw :)

- anonymous

i worked it out...is the answer 4200J

- AravindG

a b or c?

- anonymous

for a)

- AravindG

right !

- anonymous

hmm and b) is 21000J while c) is 1.68*10\[1.68\times10^{5}\] am i right???

- AravindG

yep :)

- anonymous

was it that simple?

- anonymous

question 2!
one way to measure the energy contained in a beam of x-rays is to absorb the beam by a piece of pure graphite. If x-rays are shone on to a cavity in a block of graphite of mass 10 g (0.01 kg), and a rise in temperature of 0.005K, work out the energy supplied by the beam.

- anonymous

oh and the specific heat capacity of graphite is 600\[J kg ^{-1}K ^{-1}\]

- AravindG

same formula !

- anonymous

ok......just making sure.
question 3!
An electric drill consuming energy at a rate of 200 W is used to make a small hole in a block of copper of mass 2 kg. Assuming that 80% of the electrical energy used ends up in the block as heat, and that this heat is spread evenly throughout the block, estimate its rise in temperature in 10 seconds.

- austinL

Why dont you make a new question? rather than lump several into one post?

- anonymous

ok @kym02 i'll give a brief info.
so energy is 200 W i.e. it uses 200 J in 1 second, correct?

- anonymous

um i honestly dont know....im a beginner. Dont really know about this stuff! sorry!

- anonymous

Ok, then there is one concept.
W means Watt. Watt is the unit of power of a machine.
We say that the power of a machine is the amount of work it can do in 1 second.(i.e. rate of doing work,)
Hence its unit is Watt(W) also expressed as Joule/second.
so 200 W basically means that the machine will use 200 Joules of energy in 1 second.
Ok?

- anonymous

ok i understand.

- anonymous

Fine. so if the machine uses 200 Joules of energy in 1 second, how much of energy would it use in 10 seconds?

- anonymous

2000 J.

- anonymous

Ok. 2000 J is the electrical energy used.
Now he says that 80% of this 2000 J is used as heat energy.
So what is 80% of 2000 ?

- anonymous

1600

- anonymous

Thats right.
So this 1600 is the heat energy.
As shown above, Heat energy = Mass x sp. heat capacity x rise in temp.
You have mass = 2 kg, sp. heat capacity(c) = 400 JKg^-1K^-1, can you find the rise in temperature?

- anonymous

i dont know that one, do i have to transpose?

- anonymous

Yep you have to. above there was a formula mentioned
Heat energy = m x c x delta T
Here Heat energy = 1600, m = 2 kg, c = 400 J/KgK, u need to find delta T

- anonymous

m means Mass; c means specific heat capacity and delta T means the rise in temperature.

- anonymous

\[E _{H}=mcΔT\]
so the temperature rise will be:
EH divided by mass times c
am i right?

- anonymous

Thats perfectly correct. Just type d ans also when you find it. :)

- anonymous

ok i will, im working on it

- anonymous

Is the answer 2°C?

- anonymous

Yes. :)

- anonymous

yes!!!!! thanks :) i have one more question though

- anonymous

a)How much potential energy does a 2.0 kg lump of copper possess when it is lifted 3.0 m from the ground? (Take g to be 10 N kg^-1.)
b) If it is dropped, how much kinetic energy will it have just before it hits the ground?
c) If all that energy is converted to heat, and if all that heat goes into the copper, what rise in temperature would you expect?
That's all ! :)

- anonymous

a) m = 2, h = 3, g = 10. Use Potential Energy = mgh.
b) Potential Energy found in a) = Kinetic Energy
(By law of conservation of energy)
c) Whatever PE you get, assume that as heat energy, the use C , M of copper to find rise in temp by formula EH = m.c. delta T.

- anonymous

whats the unit for a) ???

- anonymous

a) Any form of energy, whether potential energy, electric energy, heat energy, is expressed in joules( J ) (Please please note this fact; )

- anonymous

ok ok so a) =60 J

- anonymous

Thats correct.

- anonymous

and c) = \[7.5\times 10^{-2} \deg C\]

- anonymous

Which is correct, :)

- anonymous

I hope you're familiar with law of conservation of energy right?

- anonymous

no but i will just look back in a textbook! thank you soooo much!!! you saved me!! :)

- anonymous

yeah no probs as long as you're familiar with concepts and numericals :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.