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Adorkable
 one year ago
T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes.
How long did it take for a sandwich to reach an internal temputure of 30 degrees.
I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.
Adorkable
 one year ago
T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes. How long did it take for a sandwich to reach an internal temputure of 30 degrees. I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.

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UF_Cormac
 one year ago
Best ResponseYou've already chosen the best response.130 = 63(0.5)^(t/10) + 19 11 = 63(0.5)^(t/10) 11/63 = (0.5)6(t/10) ln(11/63) = (t/10)ln(0.5) Should be able to solve from there.

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0I'm not able to solve from here. How would I do this. Please.

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0I get where you got everything from what I"m having trouble with is isolating t.

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0As of right now I have 11/63=(.5)^t/10

UF_Cormac
 one year ago
Best ResponseYou've already chosen the best response.1Do you know logarithms?

UF_Cormac
 one year ago
Best ResponseYou've already chosen the best response.1Or at least what they are?

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0Nope. I think we learn that next year.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0makes me wonder why you're doing this now then :

UF_Cormac
 one year ago
Best ResponseYou've already chosen the best response.1Agreed, the only way to solve for the independent variable t is to use logarithms.

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0Lol, Can you give me the jist of this? I probably have learned it but we don't call it logarithms.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0so, you learned it "next year", but can't recall it in the present..... ooookkk

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0I haven't learned it. Its in next years curriculum im told...

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0We havent learned this. o.o Log business.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0so, this exercise doesn't apply then

UF_Cormac
 one year ago
Best ResponseYou've already chosen the best response.1\[\log_{b}y = x ...... b^x=y \]

Adorkable
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for your help I guess.
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