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T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes.
How long did it take for a sandwich to reach an internal temputure of 30 degrees.
I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.
 11 months ago
 11 months ago
T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes. How long did it take for a sandwich to reach an internal temputure of 30 degrees. I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.
 11 months ago
 11 months ago

This Question is Closed

UF_CormacBest ResponseYou've already chosen the best response.1
30 = 63(0.5)^(t/10) + 19 11 = 63(0.5)^(t/10) 11/63 = (0.5)6(t/10) ln(11/63) = (t/10)ln(0.5) Should be able to solve from there.
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
I'm not able to solve from here. How would I do this. Please.
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
I get where you got everything from what I"m having trouble with is isolating t.
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
As of right now I have 11/63=(.5)^t/10
 11 months ago

UF_CormacBest ResponseYou've already chosen the best response.1
Do you know logarithms?
 11 months ago

UF_CormacBest ResponseYou've already chosen the best response.1
Or at least what they are?
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
Nope. I think we learn that next year.
 11 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
makes me wonder why you're doing this now then :
 11 months ago

UF_CormacBest ResponseYou've already chosen the best response.1
Agreed, the only way to solve for the independent variable t is to use logarithms.
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
Lol, Can you give me the jist of this? I probably have learned it but we don't call it logarithms.
 11 months ago

UF_CormacBest ResponseYou've already chosen the best response.1
http://www.purplemath.com/modules/logs.htm
 11 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
so, you learned it "next year", but can't recall it in the present..... ooookkk
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
I haven't learned it. Its in next years curriculum im told...
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
We havent learned this. o.o Log business.
 11 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
so, this exercise doesn't apply then
 11 months ago

UF_CormacBest ResponseYou've already chosen the best response.1
\[\log_{b}y = x ...... b^x=y \]
 11 months ago

AdorkableBest ResponseYou've already chosen the best response.0
Thanks for your help I guess.
 11 months ago
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