## Adorkable 2 years ago T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes. How long did it take for a sandwich to reach an internal temputure of 30 degrees. I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.

1. UF_Cormac

30 = 63(0.5)^(t/10) + 19 11 = 63(0.5)^(t/10) 11/63 = (0.5)6(t/10) ln(11/63) = (t/10)ln(0.5) Should be able to solve from there.

I'm not able to solve from here. How would I do this. Please.

I get where you got everything from what I"m having trouble with is isolating t.

As of right now I have 11/63=(.5)^t/10

5. UF_Cormac

Do you know logarithms?

6. UF_Cormac

Or at least what they are?

Nope. I think we learn that next year.

8. jdoe0001

makes me wonder why you're doing this now then :|

9. UF_Cormac

Agreed, the only way to solve for the independent variable t is to use logarithms.

Lol, Can you give me the jist of this? I probably have learned it but we don't call it logarithms.

11. UF_Cormac
12. jdoe0001

so, you learned it "next year", but can't recall it in the present..... ooookkk

I haven't learned it. Its in next years curriculum im told...

We havent learned this. o.o Log business.

15. jdoe0001

so, this exercise doesn't apply then

16. UF_Cormac

\[\log_{b}y = x ...... b^x=y \]