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anonymous
 3 years ago
T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes.
How long did it take for a sandwich to reach an internal temputure of 30 degrees.
I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.
anonymous
 3 years ago
T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes. How long did it take for a sandwich to reach an internal temputure of 30 degrees. I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.030 = 63(0.5)^(t/10) + 19 11 = 63(0.5)^(t/10) 11/63 = (0.5)6(t/10) ln(11/63) = (t/10)ln(0.5) Should be able to solve from there.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not able to solve from here. How would I do this. Please.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I get where you got everything from what I"m having trouble with is isolating t.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As of right now I have 11/63=(.5)^t/10

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know logarithms?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Or at least what they are?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nope. I think we learn that next year.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0makes me wonder why you're doing this now then :

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Agreed, the only way to solve for the independent variable t is to use logarithms.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Lol, Can you give me the jist of this? I probably have learned it but we don't call it logarithms.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, you learned it "next year", but can't recall it in the present..... ooookkk

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I haven't learned it. Its in next years curriculum im told...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We havent learned this. o.o Log business.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, this exercise doesn't apply then

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\log_{b}y = x ...... b^x=y \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks for your help I guess.
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