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Adorkable
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T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes.
How long did it take for a sandwich to reach an internal temputure of 30 degrees.
I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.
 one year ago
 one year ago
Adorkable Group Title
T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes. How long did it take for a sandwich to reach an internal temputure of 30 degrees. I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.
 one year ago
 one year ago

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UF_Cormac Group TitleBest ResponseYou've already chosen the best response.1
30 = 63(0.5)^(t/10) + 19 11 = 63(0.5)^(t/10) 11/63 = (0.5)6(t/10) ln(11/63) = (t/10)ln(0.5) Should be able to solve from there.
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
I'm not able to solve from here. How would I do this. Please.
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
I get where you got everything from what I"m having trouble with is isolating t.
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
As of right now I have 11/63=(.5)^t/10
 one year ago

UF_Cormac Group TitleBest ResponseYou've already chosen the best response.1
Do you know logarithms?
 one year ago

UF_Cormac Group TitleBest ResponseYou've already chosen the best response.1
Or at least what they are?
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
Nope. I think we learn that next year.
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
makes me wonder why you're doing this now then :
 one year ago

UF_Cormac Group TitleBest ResponseYou've already chosen the best response.1
Agreed, the only way to solve for the independent variable t is to use logarithms.
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
Lol, Can you give me the jist of this? I probably have learned it but we don't call it logarithms.
 one year ago

UF_Cormac Group TitleBest ResponseYou've already chosen the best response.1
http://www.purplemath.com/modules/logs.htm
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
so, you learned it "next year", but can't recall it in the present..... ooookkk
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
I haven't learned it. Its in next years curriculum im told...
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
We havent learned this. o.o Log business.
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
so, this exercise doesn't apply then
 one year ago

UF_Cormac Group TitleBest ResponseYou've already chosen the best response.1
\[\log_{b}y = x ...... b^x=y \]
 one year ago

Adorkable Group TitleBest ResponseYou've already chosen the best response.0
Thanks for your help I guess.
 one year ago
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